.1108 posting-account=fgGaTw0AAAD45Fx2_7bZCc6hcNf--wQo Belkin ?! Thats the company that after 8 hours sends out your bio's to another site !!! Caught red handed , their router firmware did a spy thing against you !!! Now on to the better stuff . Would it not be great if cameras and 49G+ could hook easy to 2.5 HDD ? USB to USB !! They do , but few companys are in the competition . They're called wallets .... X-RFC2646: Format=Flowed; Original Hey, I don't like Belkin any more than you do, but occasionally they seem to come up with good quality products. (E.g., the 'pre-N' wireless routers gets very good reviews as a regular 802.11b/g router, even if the 'pre-N' silliness is distressing.) Sure, that would be great. Absolutely... the number of people who are willing to put in the kind of effort needed to pull off such a product for _free_ is quite minimal compared to the number who will do it for decent engineering salaries. :-) X-RFC2646: Format=Flowed; Original There is a good section in the help file called Troubleshooting, Communications. Have you looked there yet? news search for tons of past suggestions. With Windows XP, it will work, with most Win 98 (and good USB) it will also work. -- - - - - - - - - - - - - - - - - Bill Graves RKBA! bgraves@ix.netcom.com a lib ID must be between 769 and 1792. What if I use a number outside those bounds? Will it conflict with internal libs and not show up in my LIB menu? What if I have two libs with the same ID? Will only one of them work? Is there a list somewhere of the lib numbers authors have already used so I don't have to worry about a lib I make conflicting with other libs? Bob posting-account=CdmerAwAAAA_5trBbttE1dOcxC9Z5qXZ Assuming you have a 49, there's a document and list of IDs at: http://www.hpcalc.org/details.php?id=4533 If you have two libs with the same ID, I assume that the calc will say Object in use or similar. I don't suppose a whole lot will go wrong if you use an ID outside the range, but then you're introducing one more unknown into a calc with a rep for bugs... Bill Ha, I wonder why I never noticed that... Looks like a lot of the IDs are used. But I suppose if you wanted to use a new library with the same ID as one you already had, you could easily change the ID. Bob You simply worry too much :-) -look around a bit and choose any number that seem nice to you :-) -number under 769 are permitted but (how i look at it) these should be used for system enhancements or otherwize important libraries When enough people suges (or complain) about your library ID (where they can't combine your library with some other with the same ID) it is esay to change you library's ID and recompile. I think it is important to take care not to use already used library number in related fields for example: if you made an IO library and give it ID 123, when i make something related to IO which may have a good use combined with your library -i will most probably choose 124 (just thoughts) manjo Yeah, I probably do :-) in related fields I'll keep that in mind. Bob How do I use SysRPL to purge an object from ports 0,1,2, or 3? PURGE and ^SAFEPURGE don't work. I have been trying :port:ID but nothing happens. Do the SysRPL purge commands require different arguments? I can't find any info on this. Please help! Bob There are no direct SysRPL command to do this IIRC. Browsing with Nosy reveals FPTR 2 12, but I'd say you'd be better off with ' xPURGE EvalNoCk in this case. Steen One more question: is there a way to overwrite the contents of an object stored in a port? Or do I have to purge the object and then sto? Bob mbelzinga@mindspring.com says... But then you've limited yourself to the case where z1 = z2. In the more general case, where z1 and z2 are allowed to be different, the limit can have any arbitrary value. For instance the case where z1 and z2 are both real (let's call them x and y), such that y=log(a)/log(x) where a is an arbitrary real constant - in that case the limit will be a, which can be quite different from one. We can extend this case to complex values: let z2 = log(z_c)/log(z1) where z_c is an arbitrary complex constant. When z1 approaches zero, log(z1) will rush towards negative or positive infinity, and thus z2 will also approach zero. And the limit of z1^z2 will be the arbitrary complex constant z_c. posting-account=pvQg3wwAAAC_AqJ2VAHUnamEmkWlN60n Z1^Z2 is, of course, a different function, with many more degrees of freedom. Regarding your previous mention of 4-dimensional plots, the several times I was able to picture 4 dimensions, I unfortunately then woke up and couldn't remember how I did it. Mike mbelzinga@mindspring.com says... If one wants to claim that 0^0 has an obvious value, that value ought to be the limit of z1^z2 when z1 and z2 both go to zero, no matter how z1 and z2 are related to one another. It's not enough that the limit is unique when z1 = z2, as you assume. posting-account=pvQg3wwAAAC_AqJ2VAHUnamEmkWlN60n the then to We have no disagreement here. I haven't been able to get back to picturing 4 dimensions so I have to retreat to more conventional methods. I think there might be an instructive way to illustrate the idea it graphically; I just haven't thought of how to do it yet. The problem is, as you implied, that there are many cases. One would suspect however, that in every instance when z1 and z2 are near each other, their phases and noduli are also close. I suspect that the trick in illustrating this graphically is to do is to plot this behavior in the vicinity of (0,0). Any ideas? Mike posting-account=pvQg3wwAAAC_AqJ2VAHUnamEmkWlN60n Sorry about the badly edited sentences. I need to take a nap. Been up all night. Mike posting-account=pvQg3wwAAAC_AqJ2VAHUnamEmkWlN60n up Some additional thoughts on Paul's z1^z2: The solution isn't hard mathematically. The important part of the problem is when z1 and z2 are near each other (because we are interested in the cases where they approach each other and both approach (0,0)). Therefore it is only necessary to take the difference between them and let z=z1-z2. Then look at z^z so that now the problem is recast into the original problem where we did the 3D plots of abs(z^z) and arg(z^z). However that doesn't illustrate how the surfaces of abs(Z1^z2) and arg(z1^z2) relax onto the surfaces of the original plots. I was imagining something in the way of an animated set of plots that would illustrate this. Animated 3D plots are easy to do in Maple. I have a 49G but I have never tried to do animated 3D plots on it (actually, I am embarassed to say, I haven't even checked if it could be done). I am also guessing that we would want to keep the differences between z1 and z2 small as well as keeping each of them small. Otherwise we start running into the range limitations of the arg and arctan functions, and this would make the plots confusing. This seems to be a pretty savvy group. How about making this a challenge? Mike Yup, and the derivation follows from the definition of w^z for complex numbers: w^z = e^(z * Log(w)), where Log is the principal logarithm So z^z = e^(z * Log(z)). Substitute z=r*e^(i*theta) in z*Log(z), where theta is the principle argument of z: z*Log(z) = r*e^(i*theta) * (log(r)+i*theta) = r*(cos(theta)+i*sin(theta)) * (log(r)+i*theta) = (r*log(r)*cos(theta) - r*theta*sin(theta)) + i * (r*log(r)*sin(theta) + r*theta*cos(theta)) Since theta, sin(theta), and cos(theta) are bounded, as r goes to zero, this expression goes to zero, and z^z = e^(z*Log(z)) goes to e^0 = 1. Scott -- Scott Hemphill hemphill@alumni.caltech.edu This isn't flying. This is falling, with style. -- Buzz Lightyear posting-account=pvQg3wwAAAC_AqJ2VAHUnamEmkWlN60n direction complex where I found it interesting that if you analytically expand Z^Z and then rewrite it in polar form, and then do 3D plots the modulus and argument of that expansion, you get surfaces that are different from the ones I mentioned earlier. However, the conclusions are the same from these plots. I suspect it has something to do with the machine convention adopted for the range of the arctan function. We don't get the full information of the argument going passed 2*pi. However, as long as we confine our observations to within a radius of,say, 0.1 of the origin, the plots are nice and smooth as we approach (0,0). Mike That assumes that you stick with the 'principle value', but since w^z is not single valued for complex w and z, one need not do that. Right, in which case z^z need not approach 1. If you always choose the branch that makes z^z continuous along your path, then you can choose a spiral around the origin. For example, if you pick theta = 1/r, then and These terms don't go to zero, so z^z doesn't go to 1. And yes, I note that I spelled 'principal' two different ways. I guess I unconsciously wanted to make sure I got it right at least once. :-) Scott -- Scott Hemphill hemphill@alumni.caltech.edu This isn't flying. This is falling, with style. -- Buzz Lightyear X-RFC2646: Format=Flowed; Original Bonjour, + Manuel d'Utilisation en Fran.8dais + Cable de liaison HP-PC (officiel HP) + Cable d'alimentation sur secteur + Carte memoire MATHEZ Livres en Francais: + MATHEZ la HP48G/GX en 380 programmes pages: 474, edition: D3I Diffusion (1994) auteur : J-M. Ferrard + Assembleur sur HP48 Initiation, programmation et .8el.8ectronique pages: 394, edition: D3I Diffusion (1994) auteur : P. Kezirian + Les Secrets de la HP48G/GX, Tome 1 6000 Bonnes Adresses pages: 420, edition: D3I Diffusion (1993) auteur : J-M. Ferrard + Les Secrets de la HP48G/GX, Tome 2 Externals et Assembleur pages: 393, edition: D3I Diffusion (1993) auteur : J-M. Ferrard J-M Ferrard, ex prof de math en Math Sup au Lycee D.8eodat de Severac (Toulouse) Le tout pour 200 Euros !!!! Me contacter au 06.15.09.69.49, demander Ben. A bientot. Ne pas r.8epondre .88 ce message. X-RFC2646: Format=Flowed; Original L'adaptateur HP F-1212A convient-il pour une utilisation de la Hp 49G+ avec un retroprojecteur? (Je ne vois aucune sortie vid.8eo sur hp49) Je ne trouve sa trace que sur le site: http://www.calculatrices.ch/artikel.cfm?typ=20&e=0 Mic, le sam 05 f?v 2005 15:47:11 +0100, a dit : Tel quel, il ne peut m?me pas se brancher. Apr?s, il y a le mode contr?le qui pourrait ?tre utilis? par un p?riph?rique USB adapt? (je n'en conna?t pas de tel), voir http://youpibouh.thefreecat.org/info/prog/down/hp49g+control.tgz Translated into english: Mic, on Sat 05 feb 2005 15:47:11 +0100, said: As such, it can't even be plugged in. Then there is the control mode which could be used by an appropriate USB device (I don't know any), see http://youpibouh.thefreecat.org/info/prog/down/hp49g+control.tgz Samuel I have a Palm Tungsten E, and I bought a graphic calc program for it (powerOne Graph from Infinity Softworks), and it works really good. It does graphs in different colors, and does asymptotes really nicely. Don't think it will ever replace a graphic calculator, but it is a nice complement to it. X-RFC2646: Format=Flowed; Original could you tell me how the software (bmp2gg) works? or any other similar posting-account=InIDMwwAAACLZ3gpW5d6vXE1F8VsBdvN feature What's wrong with putting things in the hp49+ section of hpcalc.org? I think it's a good idea to stick together somewhat without getting in the way. posting-account=DCDh0g0AAAClUU8ftahyKTTAVpnfEsLo As far as things go. I'm hoping to get up the initial site with the ability to start documenting the calculator, and a place to upload/download files in about 2 months. I still have a lot to learn in order to be able to do this, but I'm cruising in that respect. After that I will add features and areas as I go. posting-account=CdmerAwAAAA_5trBbttE1dOcxC9Z5qXZ A single site with every feature of the 49G+? That should get you a knighthood! :-) I could start by donating my HLP49 help library, which would get you all the non-CAS commands explained. I could send the source code, I mean. Best of luck! Bill Count me in. What do you need done? -Al A. -- ~/.signature