Assume you know eigenvectors and eigenvalues for a matrix, find the matrix. a1,a2,a3 are eigenvalues b1,b2,b3 are eigenvectors assume matrix ttt is |a11 a12 a13| |a21 a22 a23| |a31 a32 a33| a1*b1--ttt*a1=jp1 a2*b2--ttt*a2=jp2 a3*b3--ttt*a3=jp3 Solve jp1=0 jp2=0 jp3=0 for amn Here is TI-89 solution a=| -0.5 -3.0 8.0 | | -1.0 3.0 -5.0 | | -0.1 -0.2 -0.1 | matrix to be determined ======== TI-89 program ff() Prgm ClrIO SetMode("Vector Format", "Rectangular") SetMode("Exact/Approximate","Approximate") [[-0.5,-3.0,8.0][-1.0,3.0,-5.0],[-0.1 -0.2 -0.1]]->a Matrix to be solved for eigVc(a)->ea subMat(ea,1,1,3,1)->a1 subMat(ea,1,2,3,2)->a2 subMat(ea,1,3,3,3)->a3 eigVl(a)->h product(mid(h,1,1))->b1 product(mid(h,2,1))->b2 product(mid(h,3,1))->b3 DelVar a11_,a12_,a13_ DelVar a21_,a22_,a23_ DelVar a31_,a32_,a33_,x [[a11_,a12_,a13_][a21_,a22_,a23_][a31_,a32_,a33_]]->ttt ttt*a1-a1*b1->jp1_ ttt*a1-a1*b1->jp1_ ttt*a1-a1*b1->jp1_ First subMat(jp1_,1,1,1,1)->j1_ subMat(jp2_,1,1,1,1)->j2_ subMat(jp3_,1,1,1,1)->j3_ det(jp1_)->v1_ det(jp2_)->v2_ det(jp3_)->v3_ csolve(v1_=0 and v2_=0 and v3_=0,{a11_,a12_,a13_})->nn part(nn,1)->zz0 part(nn,2)->zz1 part(zz1,1)->zz2 part(zz1,2)->zz3 part(zz0,2)->aa11 part(zz2,2)->aa12 part(zz3,2)->aa13 Solve for second set subMat(jp1_,2,1,2,1)->j1_ subMat(jp2_,2,1,2,1)->j2_ subMat(jp3_,2,1,2,1)->j3_ det(j1_)->v1_ det(j2_)->v2_ det(j3_)->v3_ csolve(v1_=0 and v2_=0 and v3_=0,{a21_,a22_,a23_})->nn part(nn,1)->zz0 part(nn,2)->zz1 part(zz1,1)->zz2 part(zz1,2)->zz3 part(zz0,2)->aa21 part(zz2,2)->aa22 part(zz3,2)->aa23 Solve for third set subMat(jp1_,3,1,3,1)->j1_ subMat(jp2_,3,1,3,1)->j2_ subMat(jp3_,3,1,3,1)->j3_ det(j1_)->v1_ det(j2_)->v2_ det(j3_)->v3_ csolve(v1_=0 and v2_=0 and v3_=0,{a31_,a32_,a33_})->nn part(nn,1)->zz0 part(nn,2)->zz1 part(zz1,1)->zz2 part(zz1,2)->zz3 part(zz0,2)->aa31 part(zz2,2)->aa32 part(zz3,2)->aa33 Answer [[aa11,aa12,aa13][aa21,aa22,aa23][aa31,aa32,aa33]]->b Disp b EndPrgm Results b on main screen | -.5 -3.+3.E-14*i 8.+2.4E-13*i | | -1. -3. -5.-2.5E-13*i | | -.1 -.2-4.E-15*i -.1 | *****************************************