mm-1739 === Subject: Re: Epistemology 201: The Science of Science Allan C Cybulskie said: >Substance is an entity? I thought maybe entities were made of >substances.....but substances seem like continuous fields, rather than discrete entities. Some entities are made of other entities. Like water is made of hydrogen and oxygen. > Water is often referred to as a substance, and yet the existence of water seems > to depend of the existence of hyrdogen and oxygen, which are more like > objects. > Are you saying that hyrdogen and oxygen aren't substnaces, yet water is? > That must be some really good stuff you're smoking. Canadian, is it? > I'll pick up the replies to me later, but in following the thread (although > perhaps it shifted a bit, since I haven't read all of these yet) it seems > like Tony's comment is a reply to Bob's initial definition which is that > something is a substance if it doesn't depend on other substances for its > existence. By that definition, water is not a substance, since it depends > on hydrogen and oxygen for its existence. See? Allan understood what I was saying. as opposed to substances was a fortuitous ambiguity in my speaking and elicited a good response from Wolf that made me think a minute. That was good. :) -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >> robert j. kolker said: >Substance is an entity? I thought maybe entities were made of >>substances.....but substances seem like continuous fields, rather than >discrete >>entities. >>Some entities are made of other entities. Like water is made of hydrogen >and oxygen. >>Bob Kolker > Water is often referred to as a substance, and yet the existence of >water seems >> to depend of the existence of hyrdogen and oxygen, which are more like >objects. >> Are you saying that hyrdogen and oxygen aren't substnaces, yet water is? >> That must be some really good stuff you're smoking. Canadian, is it? >I'll pick up the replies to me later, but in following the thread (although >perhaps it shifted a bit, since I haven't read all of these yet) it seems >like Tony's comment is a reply to Bob's initial definition which is that >something is a substance if it doesn't depend on other substances for its >existence. By that definition, water is not a substance, since it depends >on hydrogen and oxygen for its existence. And by that definition substance must be circular. === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >> robert j. kolker said: >Substance is an entity? I thought maybe entities were made of >>substances.....but substances seem like continuous fields, rather than >discrete >>entities. >>Some entities are made of other entities. Like water is made of hydrogen >and oxygen. >>Bob Kolker > Water is often referred to as a substance, and yet the existence of >water seems >> to depend of the existence of hyrdogen and oxygen, which are more like >objects. Are you saying that hyrdogen and oxygen aren't substnaces, yet water is? That must be some really good stuff you're smoking. Canadian, is it? >I'll pick up the replies to me later, but in following the thread (although >perhaps it shifted a bit, since I haven't read all of these yet) it seems >like Tony's comment is a reply to Bob's initial definition which is that >something is a substance if it doesn't depend on other substances for its >existence. By that definition, water is not a substance, since it depends >on hydrogen and oxygen for its existence. > And by that definition substance must be circular. Or mathematical. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >robert j. kolker said: >Substance is an entity? I thought maybe entities were made of >substances.....but substances seem like continuous fields, rather than > discrete >entities. >>Some entities are made of other entities. Like water is made of hydrogen >>and oxygen. >>Bob Kolker >Water is often referred to as a substance, and yet the existence of > water seems >to depend of the existence of hyrdogen and oxygen, which are more like > objects. >>Are you saying that hyrdogen and oxygen aren't substnaces, yet water is? >>That must be some really good stuff you're smoking. Canadian, is it? > I'll pick up the replies to me later, but in following the thread (although > perhaps it shifted a bit, since I haven't read all of these yet) it seems > like Tony's comment is a reply to Bob's initial definition which is that > something is a substance if it doesn't depend on other substances for its > existence. By that definition, water is not a substance, since it depends > on hydrogen and oxygen for its existence. Yes, those mathematiker boys have trouble staying on topic. They seem to do fine when a reply can be quoted from a textbook, but are completely lost outside of their Hilbert space. -- I consider it quite possible that physics cannot be based on the field concept, i. e., on continuous structures. In that case nothing remains of my entire castle in the air, gravitation theory included, [and of] the rest of modern physics. -- Albert Einstein in a 1954 letter to Michele Besso. === Subject: Re: Epistemology 201: The Science of Science >robert j. kolker said: >Substance is an entity? I thought maybe entities were made of >substances.....but substances seem like continuous fields, rather than > discrete >entities. >>Some entities are made of other entities. Like water is made of hydrogen >>and oxygen. >>Bob Kolker >Water is often referred to as a substance, and yet the existence of > water seems >to depend of the existence of hyrdogen and oxygen, which are more like > objects. >>Are you saying that hyrdogen and oxygen aren't substnaces, yet water is? >>That must be some really good stuff you're smoking. Canadian, is it? > I'll pick up the replies to me later, but in following the thread (although > perhaps it shifted a bit, since I haven't read all of these yet) it seems > like Tony's comment is a reply to Bob's initial definition which is that > something is a substance if it doesn't depend on other substances for its > existence. By that definition, water is not a substance, since it depends > on hydrogen and oxygen for its existence. Water IS hydrogen and oxygen, so hydrogen and oxygen are closer to the substance of water. But of what is hydrogen and oxygen made? Well, there are the subatomic components so they are close to the basic stuff of water etc. So a substance the basic stuff of which things consist. What we see are the appearences of the substance, i.e. its form, in the Aristotelean sense. The not well defined notion of substance is that which stands a search for -substance- in the old metaphysical meaning of the word. String or brane theory would be the ultimate theory accounting for the existence and composition of things that are perceived or inferred. See: http://www.bris.ac.uk/Depts/Philosophy/UG/Studyguide/meta.html Identity, Substance and Ontology What is it for the table in my office to be the same as the one I used to have at home, or the same as the one that was in my office yesterday? Judgements that some entity A is identical to some entity B seem to be either trivial or false: if A really is the same as B then we are just saying that A is A which is analytically true and knowable a priori, since it is a law of logic that everything is identical to itself; on the other hand if we are saying that some entity A is identical to another entity B, then this is surely false for no two entities can be the same entity. The classic discussion of identity statements is FregeÍs ïSense and ReferenceÍ. Identity and necessity Saul Kripke, in Naming and Necessity, put forward the revolutionary view that identity statements can be necessary but knowable only a posteriori. He also argued that there exist truths which are contingent but knowable a priori. See the collection, Naming, Necessity, and Natural Kinds, edited by S.P.Schwartz, and N.Salmon, Frege's Puzzle; see also Part II of J.Kim and E.Sosa (eds), Metaphysics: An Anthology. Identity over Time What is it for the table in my office to be the same table as the one that was there yesterday? If I replace one of the legs, is it the same table? What if I replace all of them? In virtue of what can an entity be said to persist while its properties and parts change? There are two main theories of persistence, the endurance theory which says that ordinary objects are wholly present at moments in time and that we can see numerically identical objects at different times, and the perdurance theory which says that ordinary objects, like tables, are stretched out in time just as they are in space having 'temporal parts' just as they have spatial parts. M.Loux, Metaphysics: a contemporary introduction, chapter 6 S.Shoemaker, ïIdentity, Properties and CausalityÍ, in his Identity, Cause and Mind D.M.Armstrong, ïIdentity through TimeÍ, in P.van Inwagen (ed.), Time and Cause M.Johnston, ïIs there a Problem about Persistence?Í, Proceedings of the Aristotelian Society Supplementary Volume, 1987 D.Lewis, On the Plurality of Worlds, pp. 202-206 P.van Inwagen, '4D Objects', Nous 1990 J.Kim and E.Sosa (eds), Metaphysics: An Anthology, Part V Substance Are objects mere bundles of properties or do the properties inhere in some substratum? Substance has been defined as that which does not depend for its existence on anything else. Bob Kolker === Subject: Re: Epistemology 201: The Science of Science >>robert j. kolker said: >Substance is an entity? I thought maybe entities were made of >>substances.....but substances seem like continuous fields, rather than >> discrete >>entities. >>Some entities are made of other entities. Like water is made of hydrogen >and oxygen. >>Bob Kolker >Water is often referred to as a substance, and yet the existence of >> water seems >>to depend of the existence of hyrdogen and oxygen, which are more like >> objects. >Are you saying that hyrdogen and oxygen aren't substnaces, yet water is? >That must be some really good stuff you're smoking. Canadian, is it? >> I'll pick up the replies to me later, but in following the thread (although >> perhaps it shifted a bit, since I haven't read all of these yet) it seems >> like Tony's comment is a reply to Bob's initial definition which is that >> something is a substance if it doesn't depend on other substances for its >> existence. By that definition, water is not a substance, since it depends >> on hydrogen and oxygen for its existence. >Water IS hydrogen and oxygen, so hydrogen and oxygen are closer to the >substance of water. But of what is hydrogen and oxygen made? Well, there >are the subatomic components so they are close to the basic stuff of >water etc. >So a substance the basic stuff of which things consist. What we see are >the appearences of the substance, i.e. its form, in the Aristotelean >sense. The not well defined notion of substance is that which stands >a search for -substance- in the old metaphysical meaning of the word. >String or brane theory would be the ultimate theory accounting for the >existence and composition of things that are perceived or inferred. Yes, well, Bob, I imagine there is a definite fullness here to your pseudo scientific ruminations wherein you acknowledge no idea concerning the substance of your substances or the truth of your facts wherein there is no finite tautological regression to self contradictory alternatives to define an otherwise infinite regression of substances. That was Aristotle's problem as well. The notion of substance is not well defined because there is no substantial limit to the regress. >See: >http://www.bris.ac.uk/Depts/Philosophy/UG/Studyguide/meta.html >Identity, Substance and Ontology >What is it for the table in my office to be the same as the one I used >to have at home, or the same as the one that was in my office yesterday? > Judgements that some entity A is identical to some entity B seem to be >either trivial or false: if A really is the same as B then we are just >saying that A is A which is analytically true and knowable a priori, >since it is a law of logic that everything is identical to itself; on >the other hand if we are saying that some entity A is identical to >another entity B, then this is surely false for no two entities can be >the same entity. The classic discussion of identity statements is >Frege.89s ëSense and Reference.89. >Identity and necessity >Saul Kripke, in Naming and Necessity, put forward the revolutionary view >that identity statements can be necessary but knowable only a >posteriori. He also argued that there exist truths which are contingent >but knowable a priori. See the collection, Naming, Necessity, and >Natural Kinds, edited by S.P.Schwartz, and N.Salmon, Frege's Puzzle; see >also Part II of J.Kim and E.Sosa (eds), Metaphysics: An Anthology. >Identity over Time >What is it for the table in my office to be the same table as the one >that was there yesterday? If I replace one of the legs, is it the same >table? What if I replace all of them? In virtue of what can an entity >be said to persist while its properties and parts change? There are two >main theories of persistence, the endurance theory which says that >ordinary objects are wholly present at moments in time and that we can >see numerically identical objects at different times, and the perdurance >theory which says that ordinary objects, like tables, are stretched out >in time just as they are in space having 'temporal parts' just as they >have spatial parts. >M.Loux, Metaphysics: a contemporary introduction, chapter 6 >S.Shoemaker, ëIdentity, Properties and Causality.89, in his Identity, >Cause and Mind >D.M.Armstrong, ëIdentity through Time.89, in P.van Inwagen (ed.), Time and >Cause >M.Johnston, ëIs there a Problem about Persistence?.89, Proceedings of the >Aristotelian Society Supplementary Volume, 1987 >D.Lewis, On the Plurality of Worlds, pp. 202-206 >P.van Inwagen, '4D Objects', Nous 1990 >J.Kim and E.Sosa (eds), Metaphysics: An Anthology, Part V >Substance >Are objects mere bundles of properties or do the properties inhere in >some substratum? Substance has been defined as that which does not >depend for its existence on anything else. >Bob Kolker === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > 1. Consistency > Consistency is a requirement for any theory. With incosistent theories > all well formed formulae can be derived as theorems. > 2. Science > Science as a method? It is no guarantee of truth at all. The only thing > we can be sure of is when a scientific theory is falsified empirically. > There is no way to determine whether all the predictions of a scientific > theory will be empirically corroberated. The fact that science works is evidence of the consistency in the universe. So much for concise language. > Bob Kolker -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >> It is quite well defined as a class of undefined's >Is the set of integers defined? Yes or No. Well, Bob, I find you curiously demanding when it comes to other peoples' definitions but singularly unforthcoming when it comes to your own definitions, as in the universal implications of true facts. Integers are certainly well defined. Whether that means your sets of integers are well defined or even defined in all respects is another matter requiring definition of sets. If your sets are in a one to one mapping with the integers in them I would be inclined to say that they are poorly defined. > As a one to one onto mapping >well defined? Yes or No. One to one mapping is no better defined than things mapped or for that matter things counted since you assume counting and mapping are more basic than things counted or mapped. Basically my problem with modern mathematikers is they profess their interest in counting countables but then spend all their time counting uncountable countables. === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > That's the definition? I thought it was the cardinality of the set of > rationals......... > The rationals and the integers have the same cardinality. A one to one > function from the integers onto the rationals can be defined. Countable > is countable. > Bob Kolker Right Bob, that's why that definition is anything but exact or precise. If I say a chicken is a bird, does that tell you what a bird is? What proof do we have that Cantor's cardinality measure is valid for infinite sets? Is it empirically verified, or simply assumed as an axiom? -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science Daryl McCullough said: > aeo6 says... >robert j. kolker said: >> You are a flat-earther. Aleph-0 is perfectly well defined. It is the >> cardinality of the set of integers. >That's the definition? I thought it was the cardinality of the set of >rationals......... >Okay, maybe not PERFECTLY well defined...... > Yes, it is perfectly well defined. > The cardinality of the rationals > = The cardinality of the naturals > = The cardinality of the integers > = The cardinality of the finite character strings > = The cardinality of the finite ordinals > = The cardinality of the even integers > = The cardinality of the prime numbers > = aleph_0 > -- > Daryl McCullough > Ithaca, NY As well defined as animal Animal= The group that includes people the group that include fish the group that includes birds the group that includes amphibians the group that includes chickens the group that includes termites the group that includes worms =animals -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >Lester Zick said: >> >>Lester Zick said: > >Wolf Kirchmeir said: >> >> >AFAIK, photons don't have as structure, so if you have evidence to the >contrary, I'd like to know where I can find it. >>Photons have wavelength and polarization. >>True, but I don't think that's what Lester has in mind. Of course, I >could be wrong - it's hard to tell what Lester has in mind. His talk >about accounting for spin in mechanical terms suggests to me that he >thinks a photon is like a little spinning billiard ball. >>Lester, care to explain? Curious minds want to know. >>A couple of weeks back, Wolf, I posed to curious minds whether they >>for the electron and proton apparently represents the radial integral >>of radial velocity? To date the question has been studiously ignored >>by all these curious minds. >>Well, if you could explain what a radial integral is, and what a radial >velcoity is, and how you integrate an radial velocity, and why this is a >defintion or calculation of spin, I might understand what you have in mind. >> >> >> Yeah, Wolf. Fortunately I don't need you to do my thinking for me but >> you badly seem to need someone to do it for you. I guessed I deserve >> it when I ask the incompetent. Maybe in your next profession you can >> learn some physics before pontificating about curious minds and >> >> >> You have your own definition of spin, which is not the same as the >> are length^2/time. But the units of the expression you quote (1/2 >> h/2pi)includes mass. So either you have discovered something that other >> physicists haven't discovered, in which case a write up of your >> experimental setup and data is in order; or else you are producing >> pseudo-scientific claptrap. >> >Actually, Lester, I think Wolf has a point. When I was going through your >previously you had been speaking purely of spacetime and geometry. My original >question was about the source of mass, and yet somehow your model seems to >introduce mass spontaneously without mention. Of course, I may have your out, >but only if you pay attention to the question I asked. :) > > Oh, I paid attention all right, Tony. But I'm wondering if the mass > you're referring to isn't the analytical masslet m0 ~ 10^-50kg-sec > I used to define the origin of Planck's constant rather than mass in > absolute terms. >> >>I meant mass in absolute terms. I am not sure where the value for this masslet >>comes from except as a retrofitted number. The question as to what causes mass >>at all is what I was asking. What causes this masslet? >> >> by rotational frequency dependent on the ratio of radial velocity in >> relation to c. I have no explanation as to why there are only the two >> stable ratios, one for the electron and one for the proton. Electron >> mass is probably minimal and reflects some fundamental aspect of >> interaction with the plenum. I imagine the proton is some convoluted >> tiny flux of geometrically stable interaction with the plenum. >If protons and electrons only differ in radius/energy, then how do you account >for opposite charge? Doesn't the proton have a more complex structure than an >electron? > Existence of positrons and negative protons shows charge is a > symmetric property. I don't explain it exactly at present but I'm > pretty sure it's explicable. I assume proton structure is a reflection > amount to. Things yet to figger out, as always, indeed. And the band plays on...... > > itself is defined in terms of the magnitude of radially directed > r/t2pi in relation to tangential r/t which is just the constant > velocity of translation of light through space. The radial velocity > r/t2pi can be of any finite magnitude and defines the radius of >> >>This part makes sense to me. Higher energy/mass means higher frequency (as in >>light), which means smaller radius, assuming constant tangetntial velocity. I >>am not sure what eveidence there is for higher mass being associated with >>smaller radius, but it still makes abstract sense. >> >> Yeah, it's basically a similar approach as used in macro angular >> mechanics except that it accounts for constant rotational velocity >> cases more accurately or more precisely or whatever. When the >> tangential velocity is fixed, reducing the radius of rotation >> increases energy with a constant spin whereas conventional macro >> angular mechanics shows decreasing angular momentum L = r x p. >> even though spin looks a lot like angular momentum. >That makes some sense. If rotation is always at a constant radial velocity then >they would all fit in some way like clockwork gears. I can see that... > Good, Tony. It's a considerably more sensible explanation than trying > to see things in terms of macro angular momentum and oscillating > rotating transverse waveforms the way classical physics did. Macro > angular mechanics mainly deals in rigid body rotation of fixed radius > which yields incorrect interpretations of rr/t mechanics for angular > momentum as r changes. >> is Heisenberg's uncertainty relation. That's why this relation is what >> it is and what it identifies. People were just so used to visualizing >> the low mass electron as tiny and the high mass proton as large that >> they never stopped to regress alternatives tautologically. >That seems like a strange visualization, if it's widespread, since the electron >cloud occupies most of the space of an atom, and the protons are all squished >on the surface of the nucleus. Also, given the known realtionship between >frequency and energy for photons, one might think that idea was extended to > Of course, you're right, Tony. I can only say that my own previous > interpretations rested on a direct equivalence between mass and size. > Even today people look askance when I say it. So I'm not surprized. I guess it's true that in the macro world, bigger and similar means heavier. I guess that's one of the backwards kind of things one has to get used to with QM. > > I use m0 simply to postulate some characteristic property of the > energy is any other terms. Wolf's point seemed to be that analysis of > Planck's constant depended on mass, but that isn't correct. I only > have to regress mass to the plenum in some way consistent with >I still say that an object moving with a radial velocity of c, despite the >radius, would at any given moment have a translational velocity of c and >it could acquire relativistic mass that would look like absolute mass from >outside the rotation. The relativistic mass would probably be proportional to >the frequency, as with free photons. > Okay. I can see the plausibility of your idea. But that assumes > relativistic mass increase is the explanation and not what is to be > explained mechanically by means of other residual constants and > interactions. Nor would your explanation explain Planck's constant or of c. I can't comment on Planck's constant at this time, but I am not sure you explained Planck's constant anyway. It seemed like you derived the unit masslet using Planck's constant, creating a new relation, but not deriving the constant from more elementary constants and relations. Did I miss something? >>Are you sure that there is no relativistic component creating the mass from a >>masslesslet, due to the tangential velocity of c? Wouldn't the radial >>acceleration then be proportional to the mass as always? >> >> dependent on the bidirectional average velocity of rotation in >> relation to the velocity of light. At velocity this increases because >> reverse side the rotation is shorter but the average for both >This sounds like you are saying there is radial inertia that acts according to >anyone else have comment on this? > relations as well. relativistically due to tangential velocity of c would wreck any of what you have. I think you might find it helps. Come on, try it. First one's free..... >> structure to mention of the kind in photons that causes cosmic >> indefinitely. (I considered mentioning this earlier because I just >> knew someone would think of it but decided it would complicate the >> subject unnecessarily at this point.) >what everyone says about photons. I don't think photons have any distinct >structure, but are 2D wavelets passing through 3D space, and they are not >supposed to slow down, since their masslessness requires that any energy they >have be translated into velocity of c. I think it's exactly this initial >masslessness you should be looking at for the source of mass IMHO. > Well, there's a very good reason they all look similar, Tony. I think > waves of light in space rotating only because they are half and not > whole waves like photons. But electrons absorb photons and turn them into increased energy levels, and release photons when they drop back down to lower energy levels. How can a half electrons and protons have a level of 3D structure that is missing in photons, but of course I've never seen either one in detail. > And of course you're at liberty to visualize > spin characteristics, Planck's constant and the Heisenberg uncertainty > same wavelength. So to speak ;) Yes I share your desire for a more mechanical explanation tying all these constants together and explaining things in simplest possible form. Of course, I have been working, when I find time, on other things too....:) -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >Lester Zick said: >>Lester Zick said: > >Lester Zick said: >> >>Wolf Kirchmeir said: > > >AFAIK, photons don't have as structure, so if you have evidence to the >>contrary, I'd like to know where I can find it. >Photons have wavelength and polarization. >True, but I don't think that's what Lester has in mind. Of course, I >>could be wrong - it's hard to tell what Lester has in mind. His talk >>about accounting for spin in mechanical terms suggests to me that he >>thinks a photon is like a little spinning billiard ball. >>Lester, care to explain? Curious minds want to know. >A couple of weeks back, Wolf, I posed to curious minds whether they >for the electron and proton apparently represents the radial integral >of radial velocity? To date the question has been studiously ignored >by all these curious minds. >Well, if you could explain what a radial integral is, and what a radial >>velcoity is, and how you integrate an radial velocity, and why this is a >>defintion or calculation of spin, I might understand what you have in mind. > > > Yeah, Wolf. Fortunately I don't need you to do my thinking for me but > you badly seem to need someone to do it for you. I guessed I deserve > it when I ask the incompetent. Maybe in your next profession you can > learn some physics before pontificating about curious minds and > > > You have your own definition of spin, which is not the same as the > are length^2/time. But the units of the expression you quote (1/2 > h/2pi)includes mass. So either you have discovered something that other > physicists haven't discovered, in which case a write up of your > experimental setup and data is in order; or else you are producing > pseudo-scientific claptrap. > >>Actually, Lester, I think Wolf has a point. When I was going through your >>previously you had been speaking purely of spacetime and geometry. My original >>question was about the source of mass, and yet somehow your model seems to >>introduce mass spontaneously without mention. Of course, I may have your out, >>but only if you pay attention to the question I asked. :) >> >> Oh, I paid attention all right, Tony. But I'm wondering if the mass >> you're referring to isn't the analytical masslet m0 ~ 10^-50kg-sec >> I used to define the origin of Planck's constant rather than mass in >> absolute terms. > >I meant mass in absolute terms. I am not sure where the value for this masslet >comes from except as a retrofitted number. The question as to what causes mass >at all is what I was asking. What causes this masslet? > > by rotational frequency dependent on the ratio of radial velocity in > relation to c. I have no explanation as to why there are only the two > stable ratios, one for the electron and one for the proton. Electron > mass is probably minimal and reflects some fundamental aspect of > interaction with the plenum. I imagine the proton is some convoluted > tiny flux of geometrically stable interaction with the plenum. >>If protons and electrons only differ in radius/energy, then how do you account >>for opposite charge? Doesn't the proton have a more complex structure than an >>electron? >> Existence of positrons and negative protons shows charge is a >> symmetric property. I don't explain it exactly at present but I'm >> pretty sure it's explicable. I assume proton structure is a reflection >> amount to. >Things yet to figger out, as always, indeed. And the band plays on...... >> >> itself is defined in terms of the magnitude of radially directed >> r/t2pi in relation to tangential r/t which is just the constant >> velocity of translation of light through space. The radial velocity >> r/t2pi can be of any finite magnitude and defines the radius of > >This part makes sense to me. Higher energy/mass means higher frequency (as in >light), which means smaller radius, assuming constant tangetntial velocity. I >am not sure what eveidence there is for higher mass being associated with >smaller radius, but it still makes abstract sense. > > Yeah, it's basically a similar approach as used in macro angular > mechanics except that it accounts for constant rotational velocity > cases more accurately or more precisely or whatever. When the > tangential velocity is fixed, reducing the radius of rotation > increases energy with a constant spin whereas conventional macro > angular mechanics shows decreasing angular momentum L = r x p. > even though spin looks a lot like angular momentum. >>That makes some sense. If rotation is always at a constant radial velocity then >>they would all fit in some way like clockwork gears. I can see that... >> Good, Tony. It's a considerably more sensible explanation than trying >> to see things in terms of macro angular momentum and oscillating >> rotating transverse waveforms the way classical physics did. Macro >> angular mechanics mainly deals in rigid body rotation of fixed radius >> which yields incorrect interpretations of rr/t mechanics for angular >> momentum as r changes. >> > is Heisenberg's uncertainty relation. That's why this relation is what > it is and what it identifies. People were just so used to visualizing > the low mass electron as tiny and the high mass proton as large that > they never stopped to regress alternatives tautologically. >>That seems like a strange visualization, if it's widespread, since the electron >>cloud occupies most of the space of an atom, and the protons are all squished >>on the surface of the nucleus. Also, given the known realtionship between >>frequency and energy for photons, one might think that idea was extended to >> Of course, you're right, Tony. I can only say that my own previous >> interpretations rested on a direct equivalence between mass and size. >> Even today people look askance when I say it. So I'm not surprized. >I guess it's true that in the macro world, bigger and similar means heavier. I >guess that's one of the backwards kind of things one has to get used to with >QM. Now at least we know what we're talking about for a change. >> I use m0 simply to postulate some characteristic property of the >> energy is any other terms. Wolf's point seemed to be that analysis of >> Planck's constant depended on mass, but that isn't correct. I only >> have to regress mass to the plenum in some way consistent with >>I still say that an object moving with a radial velocity of c, despite the >>radius, would at any given moment have a translational velocity of c and >>it could acquire relativistic mass that would look like absolute mass from >>outside the rotation. The relativistic mass would probably be proportional to >>the frequency, as with free photons. >> Okay. I can see the plausibility of your idea. But that assumes >> relativistic mass increase is the explanation and not what is to be >> explained mechanically by means of other residual constants and >> interactions. Nor would your explanation explain Planck's constant or >of c. I can't comment on Planck's constant at this time, but I am not sure you >explained Planck's constant anyway. It seemed like you derived the unit masslet >using Planck's constant, creating a new relation, but not deriving the constant >from more elementary constants and relations. Did I miss something? Actually not, Tony. This is a reasonable assessment. I have regressed Planck's constant to more fundamental considerations without proving those more fundamental considerations independently. So in this sense I have only regressed Planck's constant without explaining it in more fundamental terms. However I would add that proof of the regression relies on the self characteristics defined in terms of Planck's constant. In other words there is no other interpretation consistent with the facts of constant suggest that in the absence of any other constant such as c, m0 is proven by regression through Planck's constant. Planck's constant is properties are regressed in terms of the natural constant c to m0. >Are you sure that there is no relativistic component creating the mass from a >masslesslet, due to the tangential velocity of c? Wouldn't the radial >acceleration then be proportional to the mass as always? > > dependent on the bidirectional average velocity of rotation in > relation to the velocity of light. At velocity this increases because > reverse side the rotation is shorter but the average for both >>This sounds like you are saying there is radial inertia that acts according to >>anyone else have comment on this? >> relations as well. >relativistically due to tangential velocity of c would wreck any of what you >have. I think you might find it helps. Come on, try it. First one's free..... I have been considering the idea, Tony. The problem is that it does kinda wreck things by mucking them up. Let's say I go along with the maybe, moving at c. So we have zero mass transmogrified into finite mass through an infinite increase in mass. So far so good. spin and produce the uncertainty constant inversely proportional to mass? Then how does relativistic rotational latency correlate with relativistic mass increase dependent on velocity because that latency certainly correlates with something? These are exactly the kinds of considerations we have to explain in terms of one another and not by resort to ad hoc possibilities. > structure to mention of the kind in photons that causes cosmic > indefinitely. (I considered mentioning this earlier because I just > knew someone would think of it but decided it would complicate the > subject unnecessarily at this point.) >> >>what everyone says about photons. I don't think photons have any distinct >>structure, but are 2D wavelets passing through 3D space, and they are not >>supposed to slow down, since their masslessness requires that any energy they >>have be translated into velocity of c. I think it's exactly this initial >>masslessness you should be looking at for the source of mass IMHO. >> Well, there's a very good reason they all look similar, Tony. I think >> waves of light in space rotating only because they are half and not >> whole waves like photons. >But electrons absorb photons and turn them into increased energy levels, and >release photons when they drop back down to lower energy levels. How can a half >electrons and protons have a level of 3D structure that is missing in photons, >but of course I've never seen either one in detail. This is exactly why I don't like analogical reasoning, Tony, because I'm dealing at a speculative level below what I can explain mechanically. How all this happens depends on what various terms are taken to indicate exactly. And so far all I've done is sketch in the basics in mechanical terms. I think you're probably right that protons at least have some structure, and that is something I think topology could work on constructively. But I don't see the lack of information on such issues as anything more than missing links. I don't think they represent any kind of basic threat to the ideas I've developed so far. >> And of course you're at liberty to visualize >> spin characteristics, Planck's constant and the Heisenberg uncertainty >> same wavelength. >So to speak ;) >Yes I share your desire for a more mechanical explanation tying all these >constants together and explaining things in simplest possible form. Of >course, I have been working, when I find time, on other things too....:) Go for it, Tony. No one ever said science is content with what it knows. I think for my part though I'm pretty much content with what I do know of the mechanics involved because I have other tools in the fire as well. === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >Lester Zick said: >> >>Lester Zick said: > >Lester Zick said: >> >>Wolf Kirchmeir said: > > >AFAIK, photons don't have as structure, so if you have evidence to the >>contrary, I'd like to know where I can find it. >Photons have wavelength and polarization. >True, but I don't think that's what Lester has in mind. Of course, I >>could be wrong - it's hard to tell what Lester has in mind. His talk >>about accounting for spin in mechanical terms suggests to me that he >>thinks a photon is like a little spinning billiard ball. >>Lester, care to explain? Curious minds want to know. >A couple of weeks back, Wolf, I posed to curious minds whether they >for the electron and proton apparently represents the radial integral >of radial velocity? To date the question has been studiously ignored >by all these curious minds. >Well, if you could explain what a radial integral is, and what a radial >>velcoity is, and how you integrate an radial velocity, and why this is a >>defintion or calculation of spin, I might understand what you have in mind. > > > Yeah, Wolf. Fortunately I don't need you to do my thinking for me but > you badly seem to need someone to do it for you. I guessed I deserve > it when I ask the incompetent. Maybe in your next profession you can > learn some physics before pontificating about curious minds and > > > You have your own definition of spin, which is not the same as the > are length^2/time. But the units of the expression you quote (1/2 > h/2pi)includes mass. So either you have discovered something that other > physicists haven't discovered, in which case a write up of your > experimental setup and data is in order; or else you are producing > pseudo-scientific claptrap. > >>Actually, Lester, I think Wolf has a point. When I was going through your >>previously you had been speaking purely of spacetime and geometry. My original >>question was about the source of mass, and yet somehow your model seems to >>introduce mass spontaneously without mention. Of course, I may have your out, >>but only if you pay attention to the question I asked. :) >> >> Oh, I paid attention all right, Tony. But I'm wondering if the mass >> you're referring to isn't the analytical masslet m0 ~ 10^-50kg-sec >> I used to define the origin of Planck's constant rather than mass in >> absolute terms. > >I meant mass in absolute terms. I am not sure where the value for this masslet >comes from except as a retrofitted number. The question as to what causes mass >at all is what I was asking. What causes this masslet? > > by rotational frequency dependent on the ratio of radial velocity in > relation to c. I have no explanation as to why there are only the two > stable ratios, one for the electron and one for the proton. Electron > mass is probably minimal and reflects some fundamental aspect of > interaction with the plenum. I imagine the proton is some convoluted > tiny flux of geometrically stable interaction with the plenum. >> >>If protons and electrons only differ in radius/energy, then how do you account >>for opposite charge? Doesn't the proton have a more complex structure than an >>electron? >> >> Existence of positrons and negative protons shows charge is a >> symmetric property. I don't explain it exactly at present but I'm >> pretty sure it's explicable. I assume proton structure is a reflection >> amount to. >Things yet to figger out, as always, indeed. And the band plays on...... >> >> itself is defined in terms of the magnitude of radially directed >> r/t2pi in relation to tangential r/t which is just the constant >> velocity of translation of light through space. The radial velocity >> r/t2pi can be of any finite magnitude and defines the radius of > >This part makes sense to me. Higher energy/mass means higher frequency (as in >light), which means smaller radius, assuming constant tangetntial velocity. I >am not sure what eveidence there is for higher mass being associated with >smaller radius, but it still makes abstract sense. > > Yeah, it's basically a similar approach as used in macro angular > mechanics except that it accounts for constant rotational velocity > cases more accurately or more precisely or whatever. When the > tangential velocity is fixed, reducing the radius of rotation > increases energy with a constant spin whereas conventional macro > angular mechanics shows decreasing angular momentum L = r x p. > even though spin looks a lot like angular momentum. >> >>That makes some sense. If rotation is always at a constant radial velocity then >>they would all fit in some way like clockwork gears. I can see that... >> >> Good, Tony. It's a considerably more sensible explanation than trying >> to see things in terms of macro angular momentum and oscillating >> rotating transverse waveforms the way classical physics did. Macro >> angular mechanics mainly deals in rigid body rotation of fixed radius >> which yields incorrect interpretations of rr/t mechanics for angular >> momentum as r changes. >> > is Heisenberg's uncertainty relation. That's why this relation is what > it is and what it identifies. People were just so used to visualizing > the low mass electron as tiny and the high mass proton as large that > they never stopped to regress alternatives tautologically. >> >>That seems like a strange visualization, if it's widespread, since the electron >>cloud occupies most of the space of an atom, and the protons are all squished >>on the surface of the nucleus. Also, given the known realtionship between >>frequency and energy for photons, one might think that idea was extended to >> >> Of course, you're right, Tony. I can only say that my own previous >> interpretations rested on a direct equivalence between mass and size. >> Even today people look askance when I say it. So I'm not surprized. >I guess it's true that in the macro world, bigger and similar means heavier. I >guess that's one of the backwards kind of things one has to get used to with >QM. > Now at least we know what we're talking about for a change. Change is good :) > >> I use m0 simply to postulate some characteristic property of the >> energy is any other terms. Wolf's point seemed to be that analysis of >> Planck's constant depended on mass, but that isn't correct. I only >> have to regress mass to the plenum in some way consistent with >> >>I still say that an object moving with a radial velocity of c, despite the >>radius, would at any given moment have a translational velocity of c and >>it could acquire relativistic mass that would look like absolute mass from >>outside the rotation. The relativistic mass would probably be proportional to >>the frequency, as with free photons. >> >> Okay. I can see the plausibility of your idea. But that assumes >> relativistic mass increase is the explanation and not what is to be >> explained mechanically by means of other residual constants and >> interactions. Nor would your explanation explain Planck's constant or >of c. I can't comment on Planck's constant at this time, but I am not sure you >explained Planck's constant anyway. It seemed like you derived the unit masslet >using Planck's constant, creating a new relation, but not deriving the constant >from more elementary constants and relations. Did I miss something? > Actually not, Tony. This is a reasonable assessment. I have regressed > Planck's constant to more fundamental considerations without proving > those more fundamental considerations independently. So in this sense > I have only regressed Planck's constant without explaining it in more > fundamental terms. > However I would add that proof of the regression relies on the self > characteristics defined in terms of Planck's constant. In other words > there is no other interpretation consistent with the facts of constant > suggest that in the absence of any other constant such as c, m0 is > proven by regression through Planck's constant. Planck's constant is > properties are regressed in terms of the natural constant c to m0. I suspect that Planck's constant and c are intimately connected and determined by similar underlying variables. It is quite likely that the values are basically arbitrary, and vary from universelet to universelet, depending on their particular dimensional characteristics. So, if that is the case, there may be no direct derivation of certain root variables, but only identification and measurement of them, and integration of them into a cohesive picture. Sounds like that's what you're working on. Keep up the good work, you crank ;) Yeah I know, takes one to know one. Consider it a complement! :) >Are you sure that there is no relativistic component creating the mass from a >masslesslet, due to the tangential velocity of c? Wouldn't the radial >acceleration then be proportional to the mass as always? > > dependent on the bidirectional average velocity of rotation in > relation to the velocity of light. At velocity this increases because > reverse side the rotation is shorter but the average for both >> >>This sounds like you are saying there is radial inertia that acts according to >>anyone else have comment on this? >> >> relations as well. >relativistically due to tangential velocity of c would wreck any of what you >have. I think you might find it helps. Come on, try it. First one's free..... > I have been considering the idea, Tony. The problem is that it does > kinda wreck things by mucking them up. Let's say I go along with the > maybe, moving at c. So we have zero mass transmogrified into finite > mass through an infinite increase in mass. So far so good. > spin and produce the uncertainty constant inversely proportional to > mass? Then how does relativistic rotational latency correlate with > relativistic mass increase dependent on velocity because that latency > certainly correlates with something? These are exactly the kinds of > considerations we have to explain in terms of one another and not by > resort to ad hoc possibilities. Good questions and worth answering, although I am not sure what you mean by the rotational latency. As far as what makes them go, rotating, orbiting or simply reason to stop moving. What makes a piano string go? How long would it go with no friction? > structure to mention of the kind in photons that causes cosmic > indefinitely. (I considered mentioning this earlier because I just > knew someone would think of it but decided it would complicate the > subject unnecessarily at this point.) >> >>what everyone says about photons. I don't think photons have any distinct >>structure, but are 2D wavelets passing through 3D space, and they are not >>supposed to slow down, since their masslessness requires that any energy they >>have be translated into velocity of c. I think it's exactly this initial >>masslessness you should be looking at for the source of mass IMHO. >> >> Well, there's a very good reason they all look similar, Tony. I think >> waves of light in space rotating only because they are half and not >> whole waves like photons. >But electrons absorb photons and turn them into increased energy levels, and >release photons when they drop back down to lower energy levels. How can a half >electrons and protons have a level of 3D structure that is missing in photons, >but of course I've never seen either one in detail. > This is exactly why I don't like analogical reasoning, Tony, because > I'm dealing at a speculative level below what I can explain > mechanically. How all this happens depends on what various terms are > taken to indicate exactly. And so far all I've done is sketch in the > basics in mechanical terms. I think you're probably right that protons > at least have some structure, and that is something I think topology > could work on constructively. But I don't see the lack of information > on such issues as anything more than missing links. I don't think they > represent any kind of basic threat to the ideas I've developed so far. Probably not, though I think another type of mechanics is in order besides the macro kind. I don't know enough about QM to critique it, but what I do know makes some sense. Still, I agree that there is a basic mechanical picture of what's going on that is still quite hazy. I think you have some good ideas happening. Still a lot of missing links we have to identify, but maybe fewer than we think. I read somewhere how protons are dodecahedrons. Did you ever notice there are two electrons missing from the shell progression? What makes a neutron stick together, really, and where can we find the next stable nucleus or electron shell? There are some interesting ideas about, indeed, if one looks. >> And of course you're at liberty to visualize >> spin characteristics, Planck's constant and the Heisenberg uncertainty >> same wavelength. >So to speak ;) >Yes I share your desire for a more mechanical explanation tying all these >constants together and explaining things in simplest possible form. Of >course, I have been working, when I find time, on other things too....:) > Go for it, Tony. No one ever said science is content with what it > knows. I think for my part though I'm pretty much content with what I > do know of the mechanics involved because I have other tools in the > fire as well. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >Lester Zick said: >>Lester Zick said: > >Lester Zick said: >> >>Lester Zick said: > >Wolf Kirchmeir said: >> >> >AFAIK, photons don't have as structure, so if you have evidence to the >contrary, I'd like to know where I can find it. >>Photons have wavelength and polarization. >>True, but I don't think that's what Lester has in mind. Of course, I >could be wrong - it's hard to tell what Lester has in mind. His talk >about accounting for spin in mechanical terms suggests to me that he >thinks a photon is like a little spinning billiard ball. >>Lester, care to explain? Curious minds want to know. >>A couple of weeks back, Wolf, I posed to curious minds whether they >>for the electron and proton apparently represents the radial integral >>of radial velocity? To date the question has been studiously ignored >>by all these curious minds. >>Well, if you could explain what a radial integral is, and what a radial >velcoity is, and how you integrate an radial velocity, and why this is a >defintion or calculation of spin, I might understand what you have in mind. >> >> >> Yeah, Wolf. Fortunately I don't need you to do my thinking for me but >> you badly seem to need someone to do it for you. I guessed I deserve >> it when I ask the incompetent. Maybe in your next profession you can >> learn some physics before pontificating about curious minds and >> >> >> You have your own definition of spin, which is not the same as the >> are length^2/time. But the units of the expression you quote (1/2 >> h/2pi)includes mass. So either you have discovered something that other >> physicists haven't discovered, in which case a write up of your >> experimental setup and data is in order; or else you are producing >> pseudo-scientific claptrap. >> >Actually, Lester, I think Wolf has a point. When I was going through your >previously you had been speaking purely of spacetime and geometry. My original >question was about the source of mass, and yet somehow your model seems to >introduce mass spontaneously without mention. Of course, I may have your out, >but only if you pay attention to the question I asked. :) > > Oh, I paid attention all right, Tony. But I'm wondering if the mass > you're referring to isn't the analytical masslet m0 ~ 10^-50kg-sec > I used to define the origin of Planck's constant rather than mass in > absolute terms. >> >>I meant mass in absolute terms. I am not sure where the value for this masslet >>comes from except as a retrofitted number. The question as to what causes mass >>at all is what I was asking. What causes this masslet? >> >> by rotational frequency dependent on the ratio of radial velocity in >> relation to c. I have no explanation as to why there are only the two >> stable ratios, one for the electron and one for the proton. Electron >> mass is probably minimal and reflects some fundamental aspect of >> interaction with the plenum. I imagine the proton is some convoluted >> tiny flux of geometrically stable interaction with the plenum. > >If protons and electrons only differ in radius/energy, then how do you account >for opposite charge? Doesn't the proton have a more complex structure than an >electron? > > Existence of positrons and negative protons shows charge is a > symmetric property. I don't explain it exactly at present but I'm > pretty sure it's explicable. I assume proton structure is a reflection > amount to. >>Things yet to figger out, as always, indeed. And the band plays on...... > > itself is defined in terms of the magnitude of radially directed > r/t2pi in relation to tangential r/t which is just the constant > velocity of translation of light through space. The radial velocity > r/t2pi can be of any finite magnitude and defines the radius of >> >>This part makes sense to me. Higher energy/mass means higher frequency (as in >>light), which means smaller radius, assuming constant tangetntial velocity. I >>am not sure what eveidence there is for higher mass being associated with >>smaller radius, but it still makes abstract sense. >> >> Yeah, it's basically a similar approach as used in macro angular >> mechanics except that it accounts for constant rotational velocity >> cases more accurately or more precisely or whatever. When the >> tangential velocity is fixed, reducing the radius of rotation >> increases energy with a constant spin whereas conventional macro >> angular mechanics shows decreasing angular momentum L = r x p. >> even though spin looks a lot like angular momentum. > >That makes some sense. If rotation is always at a constant radial velocity then >they would all fit in some way like clockwork gears. I can see that... > > Good, Tony. It's a considerably more sensible explanation than trying > to see things in terms of macro angular momentum and oscillating > rotating transverse waveforms the way classical physics did. Macro > angular mechanics mainly deals in rigid body rotation of fixed radius > which yields incorrect interpretations of rr/t mechanics for angular > momentum as r changes. > >> is Heisenberg's uncertainty relation. That's why this relation is what >> it is and what it identifies. People were just so used to visualizing >> the low mass electron as tiny and the high mass proton as large that >> they never stopped to regress alternatives tautologically. > >That seems like a strange visualization, if it's widespread, since the electron >cloud occupies most of the space of an atom, and the protons are all squished >on the surface of the nucleus. Also, given the known realtionship between >frequency and energy for photons, one might think that idea was extended to > > Of course, you're right, Tony. I can only say that my own previous > interpretations rested on a direct equivalence between mass and size. > Even today people look askance when I say it. So I'm not surprized. >>I guess it's true that in the macro world, bigger and similar means heavier. I >>guess that's one of the backwards kind of things one has to get used to with >>QM. >> Now at least we know what we're talking about for a change. >Change is good :) >> > I use m0 simply to postulate some characteristic property of the > energy is any other terms. Wolf's point seemed to be that analysis of > Planck's constant depended on mass, but that isn't correct. I only > have to regress mass to the plenum in some way consistent with > >I still say that an object moving with a radial velocity of c, despite the >radius, would at any given moment have a translational velocity of c and >it could acquire relativistic mass that would look like absolute mass from >outside the rotation. The relativistic mass would probably be proportional to >the frequency, as with free photons. > > Okay. I can see the plausibility of your idea. But that assumes > relativistic mass increase is the explanation and not what is to be > explained mechanically by means of other residual constants and > interactions. Nor would your explanation explain Planck's constant or >>of c. I can't comment on Planck's constant at this time, but I am not sure you >>explained Planck's constant anyway. It seemed like you derived the unit masslet >>using Planck's constant, creating a new relation, but not deriving the constant >>from more elementary constants and relations. Did I miss something? >> Actually not, Tony. This is a reasonable assessment. I have regressed >> Planck's constant to more fundamental considerations without proving >> those more fundamental considerations independently. So in this sense >> I have only regressed Planck's constant without explaining it in more >> fundamental terms. >> However I would add that proof of the regression relies on the self >> characteristics defined in terms of Planck's constant. In other words >> there is no other interpretation consistent with the facts of constant >> suggest that in the absence of any other constant such as c, m0 is >> proven by regression through Planck's constant. Planck's constant is >> properties are regressed in terms of the natural constant c to m0. >I suspect that Planck's constant and c are intimately connected and determined >by similar underlying variables. It is quite likely that the values are >basically arbitrary, and vary from universelet to universelet, depending on >their particular dimensional characteristics. So, if that is the case, there >may be no direct derivation of certain root variables, but only identification >and measurement of them, and integration of them into a cohesive picture. >Sounds like that's what you're working on. Keep up the good work, you crank ;) >Yeah I know, takes one to know one. Consider it a complement! :) is determined by m0 and c (and pi and circular rotation of course). >>Are you sure that there is no relativistic component creating the mass from a >>masslesslet, due to the tangential velocity of c? Wouldn't the radial >>acceleration then be proportional to the mass as always? >> >> dependent on the bidirectional average velocity of rotation in >> relation to the velocity of light. At velocity this increases because >> reverse side the rotation is shorter but the average for both > >This sounds like you are saying there is radial inertia that acts according to >anyone else have comment on this? > > relations as well. >>relativistically due to tangential velocity of c would wreck any of what you >>have. I think you might find it helps. Come on, try it. First one's free..... >> I have been considering the idea, Tony. The problem is that it does >> kinda wreck things by mucking them up. Let's say I go along with the >> maybe, moving at c. So we have zero mass transmogrified into finite >> mass through an infinite increase in mass. So far so good. >> spin and produce the uncertainty constant inversely proportional to >> mass? Then how does relativistic rotational latency correlate with >> relativistic mass increase dependent on velocity because that latency >> certainly correlates with something? These are exactly the kinds of >> considerations we have to explain in terms of one another and not by >> resort to ad hoc possibilities. >Good questions and worth answering, although I am not sure what you mean by the >rotational latency. As far as what makes them go, rotating, orbiting or simply >reason to stop moving. What makes a piano string go? How long would it go with >no friction? Well friction is a very interesting subject in its own right, Tony. But saying boundary velocity rotates is not the same as saying equal-and-opposite reactions because there is a lack of constant angular momentum requiring explanation. This isn't just something which can be put off to some other speculative cause like ethereal vibration. Rotational latency has several potential implications but the one I'm translation through space in ways directly related to relativistic effects. >> structure to mention of the kind in photons that causes cosmic >> indefinitely. (I considered mentioning this earlier because I just >> knew someone would think of it but decided it would complicate the >> subject unnecessarily at this point.) > >what everyone says about photons. I don't think photons have any distinct >structure, but are 2D wavelets passing through 3D space, and they are not >supposed to slow down, since their masslessness requires that any energy they >have be translated into velocity of c. I think it's exactly this initial >masslessness you should be looking at for the source of mass IMHO. > > Well, there's a very good reason they all look similar, Tony. I think > waves of light in space rotating only because they are half and not > whole waves like photons. >> >>But electrons absorb photons and turn them into increased energy levels, and >>release photons when they drop back down to lower energy levels. How can a half >>electrons and protons have a level of 3D structure that is missing in photons, >>but of course I've never seen either one in detail. >> This is exactly why I don't like analogical reasoning, Tony, because >> I'm dealing at a speculative level below what I can explain >> mechanically. How all this happens depends on what various terms are >> taken to indicate exactly. And so far all I've done is sketch in the >> basics in mechanical terms. I think you're probably right that protons >> at least have some structure, and that is something I think topology >> could work on constructively. But I don't see the lack of information >> on such issues as anything more than missing links. I don't think they >> represent any kind of basic threat to the ideas I've developed so far. >Probably not, though I think another type of mechanics is in order besides the >macro kind. I don't know enough about QM to critique it, but what I do know >makes some sense. Still, I agree that there is a basic mechanical picture of >what's going on that is still quite hazy. I think you have some good ideas >happening. Still a lot of missing links we have to identify, but maybe fewer >than we think. >I read somewhere how protons are dodecahedrons. Did you ever notice there are >two electrons missing from the shell progression? No, I can't say as I have. At least not that I remember. > What makes a neutron stick >together, really, Well, this is a question that turns out to have a really fascinating and very specific mechanical answer, Tony. But I'm reluctant to get into it all at present because there is also a tenuous connection to planetary perihelion advance involved as well. All will be revealed in the fullness of time I hope. > and where can we find the next stable nucleus or electron >shell? There are some interesting ideas about, indeed, if one looks. > And of course you're at liberty to visualize > spin characteristics, Planck's constant and the Heisenberg uncertainty > same wavelength. >>So to speak ;) Yes I share your desire for a more mechanical explanation tying all these >>constants together and explaining things in simplest possible form. Of >>course, I have been working, when I find time, on other things too....:) >> Go for it, Tony. No one ever said science is content with what it >> knows. I think for my part though I'm pretty much content with what I >> do know of the mechanics involved because I have other tools in the >> fire as well. === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >robert j. kolker said: >> >> >> And the mind and mental effects are non material factors unless you >> propose to show an equal-and-opposite-ideas rule for the mind.So what? >> >> What does equal and opposite mean when those words refer to ideas. Are >> you talking about one idea being the logical negation of the other? In >> that case the ideas are not equal. Are you talking about a pair of >> vectors of equal magnitude but pointing in opposite directions? What the >> hell are you talking about? >> >> Bob Kolker >> >> >Duh! Tautological regression to self-contradictory alternatives, doofus! >Everybody knows that! > Don't forget the finite Tony. Lest we be accused of undefined > infinite countation. Oh yeah, finite, though I am not so worried about infinite regressions.....I rather look forward to them! -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >Lester Zick said: >>robert j. kolker said: > > > And the mind and mental effects are non material factors unless you > propose to show an equal-and-opposite-ideas rule for the mind.So what? > > What does equal and opposite mean when those words refer to ideas. Are > you talking about one idea being the logical negation of the other? In > that case the ideas are not equal. Are you talking about a pair of > vectors of equal magnitude but pointing in opposite directions? What the > hell are you talking about? > > Bob Kolker > > >>Duh! Tautological regression to self-contradictory alternatives, doofus! >>Everybody knows that! >> Don't forget the finite Tony. Lest we be accused of undefined >> infinite countation. >Oh yeah, finite, though I am not so worried about infinite regressions.....I >rather look forward to them! Just don't hold your breath, Tony. Infinite regressions take a while. It turns out they require an uncountable number of breaths to finish. === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >Lester Zick said: >> >>robert j. kolker said: > > > And the mind and mental effects are non material factors unless you > propose to show an equal-and-opposite-ideas rule for the mind.So what? > > What does equal and opposite mean when those words refer to ideas. Are > you talking about one idea being the logical negation of the other? In > that case the ideas are not equal. Are you talking about a pair of > vectors of equal magnitude but pointing in opposite directions? What the > hell are you talking about? > > Bob Kolker > > >>Duh! Tautological regression to self-contradictory alternatives, doofus! >>Everybody knows that! >> >> Don't forget the finite Tony. Lest we be accused of undefined >> infinite countation. >> >> >Oh yeah, finite, though I am not so worried about infinite regressions.....I >rather look forward to them! > Just don't hold your breath, Tony. Infinite regressions take a while. > It turns out they require an uncountable number of breaths to finish. Unless you hold your breath!!! -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >Lester Zick said: >>Lester Zick said: > >robert j. kolker said: >> >> >> And the mind and mental effects are non material factors unless you >> propose to show an equal-and-opposite-ideas rule for the mind.So what? >> >> What does equal and opposite mean when those words refer to ideas. Are >> you talking about one idea being the logical negation of the other? In >> that case the ideas are not equal. Are you talking about a pair of >> vectors of equal magnitude but pointing in opposite directions? What the >> hell are you talking about? >> >> Bob Kolker >> >> >Duh! Tautological regression to self-contradictory alternatives, doofus! >Everybody knows that! > > Don't forget the finite Tony. Lest we be accused of undefined > infinite countation. > > >>Oh yeah, finite, though I am not so worried about infinite regressions.....I >>rather look forward to them! >> Just don't hold your breath, Tony. Infinite regressions take a while. >> It turns out they require an uncountable number of breaths to finish. >Unless you hold your breath!!! Known as the breathless hush of anticipation. Not an infinite regress however. === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >Lester Zick said: >> >>Lester Zick said: > >robert j. kolker said: >> >> >> And the mind and mental effects are non material factors unless you >> propose to show an equal-and-opposite-ideas rule for the mind.So what? >> >> What does equal and opposite mean when those words refer to ideas. Are >> you talking about one idea being the logical negation of the other? In >> that case the ideas are not equal. Are you talking about a pair of >> vectors of equal magnitude but pointing in opposite directions? What the >> hell are you talking about? >> >> Bob Kolker >> >> >Duh! Tautological regression to self-contradictory alternatives, doofus! >Everybody knows that! > > Don't forget the finite Tony. Lest we be accused of undefined > infinite countation. > > >>Oh yeah, finite, though I am not so worried about infinite regressions.....I >>rather look forward to them! >> >> Just don't hold your breath, Tony. Infinite regressions take a while. >> It turns out they require an uncountable number of breaths to finish. >> >> >Unless you hold your breath!!! > Known as the breathless hush of anticipation. Not an infinite regress > however. I still like the giant pile of children's extra fingers that awaits us at the end...... -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: > On 15 Mar 2005 08:38:31 -0800, stevendaryl3016@yahoo.com (Daryl >Lester Zick says... >>And bijective mapping is about the comparison of non differentiable >>countable undefined cardinalities. >There is a definition of the cardinality of an infinite set, >so calling it undefined is incorrect. >Actually, there are two definitions: > Definition 1 (due to Russell, I think): The cardinality of a set A > is the proper class of all sets A' such that there exists a bijection > between A and A'. > Definition 2 (due to Von Neumann, I think): The cardinality of a set A > is the smallest Von Neumann ordinal alpha such that there is a > bijection between A and the set of ordinals less than alpha. > But either way the actual cardinality of an infinite set is undefined > whether you can compare that lack of definition to other lack of > definitions or not. It's the same analytical technique employed by > L'Hospital's Rule except that countable points are not differentiable. Ah, but does this matter? If the discrete points are defined by a differentiable continuous function, can't one take the saturation of the infinity to be the inverse of the derivative of that function, or something similar? Ooh I'm going to catch it now! -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >Lester Zick said: >> On 15 Mar 2005 08:38:31 -0800, stevendaryl3016@yahoo.com (Daryl >>Lester Zick says... >And bijective mapping is about the comparison of non differentiable >countable undefined cardinalities. There is a definition of the cardinality of an infinite set, >>so calling it undefined is incorrect. Actually, there are two definitions: Definition 1 (due to Russell, I think): The cardinality of a set A >> is the proper class of all sets A' such that there exists a bijection >> between A and A'. Definition 2 (due to Von Neumann, I think): The cardinality of a set A >> is the smallest Von Neumann ordinal alpha such that there is a >> bijection between A and the set of ordinals less than alpha. >> But either way the actual cardinality of an infinite set is undefined >> whether you can compare that lack of definition to other lack of >> definitions or not. It's the same analytical technique employed by >> L'Hospital's Rule except that countable points are not differentiable. >Ah, but does this matter? If the discrete points are defined by a >differentiable continuous function, can't one take the saturation of the >infinity to be the inverse of the derivative of that function, or something >similar? Ooh I'm going to catch it now! a differentiable continuous function, it is the continuous function that is differentiable and not the countable discrete points. I don't quite understand what you mean by saturation of the infinity to be the inverse of the derivative. Countable points just have no defined functional derivative or, more to the point, they have an infinity of functional derivatives. === Subject: Re: Epistemology 201: The Science of Science > Ah, but does this matter? If the discrete points are defined by a > differentiable continuous function, How is a discrete point defined by a differentiable continuous function. Could you please define what you mean by that? What does that phrase mean? What is the domain of the function. What is its co-domain. What are the metrics (differentiability only pertains to functions from metric spaces to metric spaces where subtraction and additon are defined). Give us an example of a differentiable continuous function (specify domain and co-domain, please) which defines a discrete point. Bob Kolker === Subject: Re: Epistemology 201: The Science of Science >> Ah, but does this matter? If the discrete points are defined by a >> differentiable continuous function, >How is a discrete point defined by a differentiable continuous function. >Could you please define what you mean by that? What does that phrase >mean? What is the domain of the function. What is its co-domain. What >are the metrics (differentiability only pertains to functions from >metric spaces to metric spaces where subtraction and additon are >defined). Give us an example of a differentiable continuous function >(specify domain and co-domain, please) which defines a discrete point. This is how it works, Bob: you give me the definition of a fact, I give you the definition of a point. === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > > Ah, but does this matter? If the discrete points are defined by a > differentiable continuous function, > How is a discrete point defined by a differentiable continuous function. > Could you please define what you mean by that? What does that phrase > mean? What is the domain of the function. What is its co-domain. What > are the metrics (differentiability only pertains to functions from > metric spaces to metric spaces where subtraction and additon are > defined). Give us an example of a differentiable continuous function > (specify domain and co-domain, please) which defines a discrete point. > Bob Kolker Here I am trying to help you Bob, and what do I get? I mean that each discrete value is the value of a continuous function f(x) at discrete values of x. Take the size of the set of integers to be unit infinity, or aleph. The set of evens is bijectionable (like the new word?) using the function f(x)=2*x, since each even is twice the size of its corresponding integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is 1/2, which is the ratio of the size of that set to aleph. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science > I mean that each discrete value is the value of a continuous function f(x) at > discrete values of x. Take the size of the set of integers to be unit infinity, > or aleph. The set of evens is bijectionable (like the new word?) using the > function f(x)=2*x, since each even is twice the size of its corresponding > integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is > 1/2, which is the ratio of the size of that set to aleph. The function f(x) = 2*x restricted to the integers is not differentiable. what does lim (h -> 0) [(f(x + h) - f(x))/h] mean when were resrict the function to the integers? It makes sense over the rationals or the reals but not the integers. Bob Kolker === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > > I mean that each discrete value is the value of a continuous function f(x) at > discrete values of x. Take the size of the set of integers to be unit infinity, > or aleph. The set of evens is bijectionable (like the new word?) using the > function f(x)=2*x, since each even is twice the size of its corresponding > integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is > 1/2, which is the ratio of the size of that set to aleph. > The function f(x) = 2*x restricted to the integers is not > differentiable. what does lim (h -> 0) [(f(x + h) - f(x))/h] mean when > were resrict the function to the integers? It makes sense over the > rationals or the reals but not the integers. > Bob Kolker No kidding Bob, but I just demonstrated using as clear a method as Cantor that the set of integers is twice the size of the evens, which is what I've been saying all along. When I get this all fleshed out you're going to kick yourself for not grabbing the purse and running while you could. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science > No kidding Bob, but I just demonstrated using as clear a method as Cantor that > the set of integers is twice the size of the evens, which is what I've been > saying all along. When I get this all fleshed out you're going to kick yourself > for not grabbing the purse and running while you could. What do you mean by size? Yes, your demo is true on the rationals and the reals. It does not hold when restricted to the integers. Why? Because there is no definition of derivative on the integers. For there to be you must have a dense ordering. The derivative of f at x is -by definition- lim(h->0) (f(x + h) - f(x))/h. Hows is that defined on the integers? That is what a derivative is, so you have demonstrated nothing on the integers. Sure enough 2*x is twice x (by definition duh!). So what? This hs nothing to do with sizes of sets. Bob Kolker === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > No kidding Bob, but I just demonstrated using as clear a method as Cantor that > the set of integers is twice the size of the evens, which is what I've been > saying all along. When I get this all fleshed out you're going to kick yourself > for not grabbing the purse and running while you could. > What do you mean by size? Yes, your demo is true on the rationals and > the reals. It does not hold when restricted to the integers. Why? > Because there is no definition of derivative on the integers. For there > to be you must have a dense ordering. The derivative of f at x is -by > definition- lim(h->0) (f(x + h) - f(x))/h. Hows is that defined on the > integers? That is what a derivative is, so you have demonstrated nothing > on the integers. > Sure enough 2*x is twice x (by definition duh!). So what? This hs > nothing to do with sizes of sets. > Bob Kolker It works fine on the integers if the mapping function is continuous for reals. I already showed that. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science > It works fine on the integers if the mapping function is continuous for reals. > I already showed that. If the mapping function has domain = set of integers in what way is it continuous. Are you talking about a function defined on the integers or a function defined on the reals? If it is defined on the reals what does it have to do with a restriction to the integers? All you have said is that the slope of the curve y = 2*x is 2. So what? Bob Kolker === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > > It works fine on the integers if the mapping function is continuous for reals. > I already showed that. > If the mapping function has domain = set of integers in what way is it > continuous. Are you talking about a function defined on the integers or > a function defined on the reals? If it is defined on the reals what does > it have to do with a restriction to the integers? > All you have said is that the slope of the curve y = 2*x is 2. So what? > Bob Kolker I already ing explained this to you rock head. If one applies a continuous function f(x) to discrete integral values, one will get discrete values from the function. Are you saying I can apply f(x)=x^2 to reals but not integers? Can I tell what f(x)=x^2-4x+7 is at x=913? Does it matter that 913 is an integer? -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science <4235e31c.38492205@netnews.att.net> <42360b87.44041345@netnews.att.net> <39moaoF63lffvU3@individual.net> <4236fb50.49404197@netnews.att.net> <423731fa.54129391@netnews.att.net> <39r33gF4c6552U1@individual.net> <39re1dF62csvaU1@individual.net> > > > > I mean that each discrete value is the value of a continuous function f(x) at > discrete values of x. Take the size of the set of integers to be unit infinity, > or aleph. The set of evens is bijectionable (like the new word?) using the > function f(x)=2*x, since each even is twice the size of its corresponding > integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is > 1/2, which is the ratio of the size of that set to aleph. > > The function f(x) = 2*x restricted to the integers is not > differentiable. what does lim (h -> 0) [(f(x + h) - f(x))/h] mean when > were resrict the function to the integers? It makes sense over the > rationals or the reals but not the integers. > > Bob Kolker > > No kidding Bob, but I just demonstrated using as clear a method as Cantor that > the set of integers is twice the size of the evens, which is what I've been > saying all along. When I get this all fleshed out you're going to kick yourself > for not grabbing the purse and running while you could. Your proposal doesn't really work. Consider your map x->2*x restricted to the rationals. This map is a bijection from the rationals to itself, but according to your logic this would imply that the rationals had half as many elements as itself. === Subject: Re: Epistemology 201: The Science of Science Creighton Hogg said: > robert j. kolker said: > > > > > I mean that each discrete value is the value of a continuous function f(x) at > discrete values of x. Take the size of the set of integers to be unit infinity, > or aleph. The set of evens is bijectionable (like the new word?) using the > function f(x)=2*x, since each even is twice the size of its corresponding > integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is > 1/2, which is the ratio of the size of that set to aleph. > > The function f(x) = 2*x restricted to the integers is not > differentiable. what does lim (h -> 0) [(f(x + h) - f(x))/h] mean when > were resrict the function to the integers? It makes sense over the > rationals or the reals but not the integers. > > Bob Kolker > > No kidding Bob, but I just demonstrated using as clear a method as Cantor that > the set of integers is twice the size of the evens, which is what I've been > saying all along. When I get this all fleshed out you're going to kick yourself > for not grabbing the purse and running while you could. > Your proposal doesn't really work. > Consider your map x->2*x restricted to the rationals. This map is a > bijection from the rationals to itself, but according to your logic this > would imply that the rationals had half as many elements as itself. Are you saying that the set of all rationals with even numerators includes all rationals? I didn't think so. I'd say........about half. QED -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science <4235e31c.38492205@netnews.att.net> <42360b87.44041345@netnews.att.net> <39moaoF63lffvU3@individual.net> <4236fb50.49404197@netnews.att.net> <423731fa.54129391@netnews.att.net> <39r33gF4c6552U1@individual.net> <39re1dF62csvaU1@individual.net> > robert j. kolker said: > > > > > I mean that each discrete value is the value of a continuous function f(x) at > discrete values of x. Take the size of the set of integers to be unit infinity, > or aleph. The set of evens is bijectionable (like the new word?) using the > function f(x)=2*x, since each even is twice the size of its corresponding > integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is > 1/2, which is the ratio of the size of that set to aleph. > > The function f(x) = 2*x restricted to the integers is not > differentiable. what does lim (h -> 0) [(f(x + h) - f(x))/h] mean when > were resrict the function to the integers? It makes sense over the > rationals or the reals but not the integers. > > Bob Kolker > > No kidding Bob, but I just demonstrated using as clear a method as Cantor that > the set of integers is twice the size of the evens, which is what I've been > saying all along. When I get this all fleshed out you're going to kick yourself > for not grabbing the purse and running while you could. > > Your proposal doesn't really work. > Consider your map x->2*x restricted to the rationals. This map is a > bijection from the rationals to itself, but according to your logic this > would imply that the rationals had half as many elements as itself. > > Are you saying that the set of all rationals with even numerators includes all > rationals? I didn't think so. I'd say........about half. QED The map x->2*x doesn't map the set of all rationals to the set of all rationals with even numerators. Afterall, 1/6 * 2 = 1/3. You get back *all* the rationals this way, since for any rational y/x, y/(2x) is also a rational. === Subject: Re: Epistemology 201: The Science of Science Creighton Hogg said: > Creighton Hogg said: > > robert j. kolker said: > > > > > I mean that each discrete value is the value of a continuous function f(x) at > discrete values of x. Take the size of the set of integers to be unit infinity, > or aleph. The set of evens is bijectionable (like the new word?) using the > function f(x)=2*x, since each even is twice the size of its corresponding > integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is > 1/2, which is the ratio of the size of that set to aleph. > > The function f(x) = 2*x restricted to the integers is not > differentiable. what does lim (h -> 0) [(f(x + h) - f(x))/h] mean when > were resrict the function to the integers? It makes sense over the > rationals or the reals but not the integers. > > Bob Kolker > > No kidding Bob, but I just demonstrated using as clear a method as Cantor that > the set of integers is twice the size of the evens, which is what I've been > saying all along. When I get this all fleshed out you're going to kick yourself > for not grabbing the purse and running while you could. > > Your proposal doesn't really work. > Consider your map x->2*x restricted to the rationals. This map is a > bijection from the rationals to itself, but according to your logic this > would imply that the rationals had half as many elements as itself. > > Are you saying that the set of all rationals with even numerators includes all > rationals? I didn't think so. I'd say........about half. QED > The map x->2*x doesn't map the set of all rationals to the set of all > rationals with even numerators. Afterall, 1/6 * 2 = 1/3. You get back > *all* the rationals this way, since for any rational y/x, y/(2x) is also a > rational. Okay, I can see that, in the context of Cantorian orderings. I don't think that changes my argument, though. For any given rational value in x and 2*x, the second set will have half as many elements before it as the first set. The first set can be said to saturate the rationals fully, while second only saturates it half as quickly. I understand the logic behind the mappings but I think it causes problems due to unnatural orderings imposed arbitrarily. I mean, it seems obvious to me that there are more rationals in [0,2] than in [0,1]. This is basically what is at issue in my mind. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science <4235e31c.38492205@netnews.att.net> <42360b87.44041345@netnews.att.net> <39moaoF63lffvU3@individual.net> <4236fb50.49404197@netnews.att.net> <423731fa.54129391@netnews.att.net> <39r33gF4c6552U1@individual.net> <39re1dF62csvaU1@individual.net> > robert j. kolker said: > > > > > I mean that each discrete value is the value of a continuous function f(x) at > discrete values of x. Take the size of the set of integers to be unit infinity, > or aleph. The set of evens is bijectionable (like the new word?) using the > function f(x)=2*x, since each even is twice the size of its corresponding > integer. The derivative (slope of ascent) of f(x) is 2, the inverse of which is > 1/2, which is the ratio of the size of that set to aleph. > > The function f(x) = 2*x restricted to the integers is not > differentiable. what does lim (h -> 0) [(f(x + h) - f(x))/h] mean when > were resrict the function to the integers? It makes sense over the > rationals or the reals but not the integers. > > Bob Kolker > > No kidding Bob, but I just demonstrated using as clear a method as Cantor that > the set of integers is twice the size of the evens, which is what I've been > saying all along. When I get this all fleshed out you're going to kick yourself > for not grabbing the purse and running while you could. > > Your proposal doesn't really work. > Consider your map x->2*x restricted to the rationals. This map is a > bijection from the rationals to itself, but according to your logic this > would imply that the rationals had half as many elements as itself. > > Are you saying that the set of all rationals with even numerators includes all > rationals? I didn't think so. I'd say........about half. QED > The map x->2*x doesn't map the set of all rationals to the set of all > rationals with even numerators. Afterall, 1/6 * 2 = 1/3. You get back > *all* the rationals this way, since for any rational y/x, y/(2x) is also a > rational. I should probably expand on this and say that the rationals are a field under the usual operations of addition and multiplication, which is the essence of what I'm trying to illustrate above. === Subject: Re: Epistemology 201: The Science of Science Daryl McCullough said: > aeo6 says... >What I object to is the use of numbers in orderings that are not consistent, >using a technique that is not proven, to derive results that contradict more >basic notions of set theory > Well, nobody is using numbers in orderings that are not consistent, and > nobody is deriving results that contradict more basic notions of set theory. If the ordering of quantities is inconsistent with the quantities, then the ordering is inconsistent. If a set contains all the elements of another set, plus some more, then it has more. These are pretty basic concepts that I shouldn't have to repeat. >> I already told you, the result is not there are an infinite number >> of naturals between any two naturals, the result is that for the >> particular ordering that I defined, there are infinitely many >> naturals between any two naturals. >Right, but do you believe the conclusion based on that ordering? > The conclusion is: There exists an ordering R(x,y) on naturals > such that between any two naturals x and y, there exists infinitely > many naturals z such that R(x,z) and R(z,y). > Yes, I believe that. I constructed such an ordering. >Is it true that there are infinitely many naturals between >any two naturals, given the normal meaning of between for >natural numbers? > Of course not. >If not, then you should examine the train of thought that led to >that conclusion > Nothing led to that conclusion. You are misquoting the conclusion. > I came to the conclusion that > There exists an ordering R(x,y) on naturals > such that between any two naturals x and y, > there exists infinitely many naturals z such > that R(x,z) and R(z,y). You are not being honest. Here is your actual quote: I didn't say that. I said that for that particular *ordering* on the naturals, there exists infinitely many naturals between any pair of naturals. It is a property of the ordering, not the underlying set. Now, do you believe that there exists infinitely many naturals between any pair of naturals or not? If not, how do you explain the conclusion you drew? >because you either have a faulty premise, or a flawed method of >calculation. > Or, what's actually the case, you misquoted the conclusion. Or not. >This is yet another example of how artificial orderings that >violate the natural order of real numbers can lead to erroneous >results. > The only erroneous results are due to you. Try again. >>Doesn't a result like that give you any kind of twinge? >> >> The fact that you left out the qualifying phrase for that particular >> ordering certainly does. >That is my point. The ordering is the problem. The conclusion is wrong, > My conclusion wasn't wrong---yours was. Read your quoted conclusion above, again. >> Because you say things like >> >> anyone who argues there are as many rationals as integers is nuts, >> in my mind >> >> Why should anyone show you respect when you don't show any respect? >I have already made my case regarding the integers and rationals. > You have said nothing other than the obvious fact that the integers > are a proper subset of the rationals. Nobody disagrees with that. I never mentioned the subset relationship with respect to the integers and rationals. I mentioned that with respect to [0,1] and [0,2] for whatever numerical set you want over that domain. With respect to integers and rationals, I pointed to the consistent patter throughout the real number system that between any two naturals there are an infinite number of distinct rationals, but not vice versa. The logic concluding that there are infinitely many more rationals than integers is far more starightforward than your bijections and artificial orderings, and the preference by mathematicians for the latter is a form of confusion I'd like to see dispelled. You misquote yourself and misrepresent my position. Not a good sign. >If, for EVERY unit on the real number line there is exactly ONE >integer and INFINITE rationals, in EVERY unit, then it is a >no-brainer to conclude that overall, there are an infinity of >rationals for every integer, not one. > Nobody disagrees with the fact that, with the usual ordering > on the rationals, there are infinitely many rationals between > any two integers. Are there infinitely many integers between any two rationals? No? What does that tell you about the relative numbers integers and rationals? >To draw a conclusion so drastically different from the blatantly >obvious, > The only conclusion is that there exists a bijection between > the rationals and the integers. That's provably the case. More bijection genuflection. What does this case prove? Certainly nothing about the relative numbers of integers and rationals. >using a technique that is assumed to work because it >looks neat, > That's not true. Why else is it accepted? >but is not supported by any empirical evidence or >application to reality, > That's not true. What empirical evidence can you offer? >and to accept that conclusion over what >makes sense, to me, makes no sense. > What conclusion? The concusion is that there is a bijection > between the integers and the rationals. You disagree with that > conclusion? No, just with the conclusion that there exists infinitely many naturals between any pair of naturals >I believe I am entitled to that opinion. > I don't see how the word entitled applies here. You are almost > completely ignorant of the subject that you are criticizing, and > your criticism doesn't amount to a hill of beans. The complaints > you have are almost all complaints about *word* choice, which is > about the silliest basis for criticizing mathematics. see that you have not been reading too carefully, as I've been making a clear case that the conclusions drawn from bijection are overdrawn. Do you now agree that the conclusion you drew, which I quoted, is incorrect? > -- > Daryl McCullough > Ithaca, NY -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > Now, do you believe that there exists infinitely many naturals between > any pair of naturals or not? If not, how do you explain the conclusion you > drew? > It depends on what is meant by between. Let R be any linear > (transitive, non-symmetric and non-reflexive and trichotomy holds wrt R) > ordering (dense or not). We say z is R-between x and y if and only if > R(x,z) and R(z,y). There are many linear dense ordering on a countable > set, hence many linear dense orderings on the integers. > Bob Kolker Have you been paying attention Bob? In the context of numbers, between means greater than one and less than the other, in quantity. By this deifnition, does the conclusion make any sense? -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science <39r2t1F6495bnU1@individual.net> Discussion, linux) [Newsgroups trimmed a bit. Sorry if Tony's group was omitted.] > robert j. kolker said: >> Now, do you believe that there exists infinitely many naturals between >> any pair of naturals or not? If not, how do you explain the conclusion you >> drew? >> It depends on what is meant by between. Let R be any linear >> (transitive, non-symmetric and non-reflexive and trichotomy holds wrt R) >> ordering (dense or not). We say z is R-between x and y if and only if >> R(x,z) and R(z,y). There are many linear dense ordering on a countable >> set, hence many linear dense orderings on the integers. >> Bob Kolker > Have you been paying attention Bob? In the context of numbers, between means > greater than one and less than the other, in quantity. By this deifnition, does > the conclusion make any sense? Bull. In this context, between meant greater[1] than one and less Daryl has been absolutely precise on this point. No one here has said that *according to the usual ordering*, there exists infinitely many naturals between any two naturals. That is obviously false. Daryl constructed a particular (non-standard) ordering in which it is true. What is so hard to understand about that? Look: A linear order on a set S is any relation R satisfying the following (for all x, y, z in S): (1) x R x (2) x R y and y R z implies x R z (3) x R y and y R x implies x = y (4) x R y or y R x Daryl showed that there is a relation on N satisfying (1) - (4) and also the additional property that for all x, y such that x R y, there exist infinitely many z such that x R z and z R y. There isn't a damn thing controversial about that claim. Unless you're too thick to realize that there are non-standard linear orders on N. Footnotes: [1] I hesitate to use the words greater and less here, since they might imply the standard order. I mean nothing more than stand in the relation this way or that, loosely speaking. -- I'm starting to absorb information [...] as I find myself more and more fascinated by my own prime counting function. The rate of information absorption is on an exponential scale, like it always has been for me for things I'm interested in. -- James S. Harris === Subject: Re: Epistemology 201: The Science of Science >[Newsgroups trimmed a bit. Sorry if Tony's group was omitted.] Yeah, well, we've gotten along perfectly well without trimming the newsgroups that I put on the thread originally so if you want to broadcast to your own selected groups I suggest you find another thread to do it on. === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >[Newsgroups trimmed a bit. Sorry if Tony's group was omitted.] > Yeah, well, we've gotten along perfectly well without trimming the > newsgroups that I put on the thread originally so if you want to > broadcast to your own selected groups I suggest you find another > thread to do it on. That's alright. Nobody's interested in infinity ayway ;) -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >>[Newsgroups trimmed a bit. Sorry if Tony's group was omitted.] > Yeah, well, we've gotten along perfectly well without trimming the > newsgroups that I put on the thread originally so if you want to > broadcast to your own selected groups I suggest you find another > thread to do it on. I'm not sure I agree with that, Lester. We are each independent agents with complete control over which groups we choose to post on. If I thought it would work, I would do it too. -- I consider it quite possible that physics cannot be based on the field concept, i. e., on continuous structures. In that case nothing remains of my entire castle in the air, gravitation theory included, [and of] the rest of modern physics. -- Albert Einstein in a 1954 letter to Michele Besso. === Subject: Re: Epistemology 201: The Science of Science >[Newsgroups trimmed a bit. Sorry if Tony's group was omitted.] >> Yeah, well, we've gotten along perfectly well without trimming the >> newsgroups that I put on the thread originally so if you want to >> broadcast to your own selected groups I suggest you find another >> thread to do it on. >I'm not sure I agree with that, Lester. We are each independent >agents with complete control over which groups we choose to post >on. If I thought it would work, I would do it too. I never suggested we weren't independent agents. In fact early on I pointed out exactly that to Osher. It just strikes me as rude to jump into a thread with 4000-5000 post history and try to redirect it. === Subject: Re: Epistemology 201: The Science of Science Jesse F. Hughes said: > [Newsgroups trimmed a bit. Sorry if Tony's group was omitted.] > robert j. kolker said: >> >> >> Now, do you believe that there exists infinitely many naturals between >> any pair of naturals or not? If not, how do you explain the conclusion you >> drew? >> >> It depends on what is meant by between. Let R be any linear >> (transitive, non-symmetric and non-reflexive and trichotomy holds wrt R) >> ordering (dense or not). We say z is R-between x and y if and only if >> R(x,z) and R(z,y). There are many linear dense ordering on a countable >> set, hence many linear dense orderings on the integers. >> >> Bob Kolker >> >> > Have you been paying attention Bob? In the context of numbers, between means > greater than one and less than the other, in quantity. By this deifnition, does > the conclusion make any sense? > Bull. In this context, between meant greater[1] than one and less > Daryl has been absolutely precise on this point. > No one here has said that *according to the usual ordering*, there > exists infinitely many naturals between any two naturals. That is > obviously false. > Daryl constructed a particular (non-standard) ordering in which it is > true. What is so hard to understand about that? > Look: A linear order on a set S is any relation R satisfying the > following (for all x, y, z in S): > (1) x R x > (2) x R y and y R z implies x R z > (3) x R y and y R x implies x = y > (4) x R y or y R x > Daryl showed that there is a relation on N satisfying (1) - (4) and > also the additional property that for all x, y such that x R y, there > exist infinitely many z such that x R z and z R y. There isn't a damn > thing controversial about that claim. > Unless you're too thick to realize that there are non-standard linear > orders on N. > Footnotes: > [1] I hesitate to use the words greater and less here, since they > might imply the standard order. I mean nothing more than stand in > the relation this way or that, loosely speaking. Jesse, apparently you haven't been paying attention either. When you come to conclusions that make no sense, except in the case of an arbitrary ordering that makes no sense, do you take those conclusions as fact? The usual ordering of numbers is the one that makes them make sense. Numbers are naturally ordered by quantity, since that's what they represent. As was pointed out, precision does not equate to accuracy. If your shots cluster tightly, great, you're precise. But, if they are hitting the tree 8 feet to the left of the target, the gun is useless. If mathematicians conclude based on cardinality that there are as many integers as rationals, when in fact there are an infinite number of rationals for every integer (and in fact a larger infinity than the entire set of integers), then there is something wrong with cardinality, or at least the interpretation of it. As I've determined, the root flaw in the method is the assumption that one can rearrange the number system without violating the definition of its members. So, bull right back atcha! -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science <39r2t1F6495bnU1@individual.net> <87y8cnmlct.fsf@phiwumbda.org> Discussion, linux) > Jesse F. Hughes said: >> Bull. In this context, between meant greater[1] than one and less >> Daryl has been absolutely precise on this point. >> No one here has said that *according to the usual ordering*, there >> exists infinitely many naturals between any two naturals. That is >> obviously false. >> Daryl constructed a particular (non-standard) ordering in which it is >> true. What is so hard to understand about that? >> Look: A linear order on a set S is any relation R satisfying the >> following (for all x, y, z in S): >> (1) x R x >> (2) x R y and y R z implies x R z >> (3) x R y and y R x implies x = y >> (4) x R y or y R x >> Daryl showed that there is a relation on N satisfying (1) - (4) and >> also the additional property that for all x, y such that x R y, there >> exist infinitely many z such that x R z and z R y. There isn't a damn >> thing controversial about that claim. >> Unless you're too thick to realize that there are non-standard linear >> orders on N. >> Footnotes: >> [1] I hesitate to use the words greater and less here, since they >> might imply the standard order. I mean nothing more than stand in >> the relation this way or that, loosely speaking. > Jesse, apparently you haven't been paying attention either. When you come to > conclusions that make no sense, except in the case of an arbitrary ordering > that makes no sense, do you take those conclusions as fact? The usual > ordering of numbers is the one that makes them make sense. Numbers are > naturally ordered by quantity, since that's what they represent. Numbers do indeed have a natural ordering. They also have other orderings. What Daryl has said applies to other orderings. > As was pointed out, precision does not equate to accuracy. If your shots > cluster tightly, great, you're precise. But, if they are hitting the tree 8 > feet to the left of the target, the gun is useless. If mathematicians conclude > based on cardinality that there are as many integers as rationals, when in fact > there are an infinite number of rationals for every integer (and in fact a > larger infinity than the entire set of integers), then there is something wrong > with cardinality, or at least the interpretation of it. One might conclude that cardinality isn't the right concept for size when infinite sets are involved -- one *might* conclude that, but I can't imagine a better definition myself. Cardinality is very well motivated from a philosophical standpoint. But even *if* one doubted that cardinality was the right generalization of size for infinite sets, that has nothing to do with your complaints about Daryl's obvious and uncontroversial result. There is a relation R satisfying (1) - (4) such that it also satisfies the density property I mention above. His proof is simple and obvious. > As I've determined, the root flaw in the method is the assumption > that one can rearrange the number system without violating the > definition of its members. So, bull right back atcha! Yeah, well, the difference between my claim of bull and yours is that the supporting text made sense in my case. Look, maybe you have trouble with the term order when it's a non-standard order. Call a relation R satisfying (1)-(4) a gigglegoggle. Do you agree or disagree that there exists a gigglegoggle such that for all x and y where x R y, there exists a z (and hence infinitely many z) such that x R z and z R y? -- [Criticizing JSH's mathematics will result in] one of the worst debacles in the history of the world. It is foretold in most mythologies and religions. And yes, you are the ones, the cursed ones, who destroy the world. --James S. Harris reads from the Aztec Book of the Damned Mathematicians === Subject: Re: Epistemology 201: The Science of Science Jesse F. Hughes said: > Jesse F. Hughes said: >> >> Bull. In this context, between meant greater[1] than one and less >> Daryl has been absolutely precise on this point. >> >> No one here has said that *according to the usual ordering*, there >> exists infinitely many naturals between any two naturals. That is >> obviously false. >> >> Daryl constructed a particular (non-standard) ordering in which it is >> true. What is so hard to understand about that? >> >> Look: A linear order on a set S is any relation R satisfying the >> following (for all x, y, z in S): >> (1) x R x >> (2) x R y and y R z implies x R z >> (3) x R y and y R x implies x = y >> (4) x R y or y R x >> >> Daryl showed that there is a relation on N satisfying (1) - (4) and >> also the additional property that for all x, y such that x R y, there >> exist infinitely many z such that x R z and z R y. There isn't a damn >> thing controversial about that claim. >> >> Unless you're too thick to realize that there are non-standard linear >> orders on N. >> >> >> Footnotes: >> [1] I hesitate to use the words greater and less here, since they >> might imply the standard order. I mean nothing more than stand in >> the relation this way or that, loosely speaking. >> >> > Jesse, apparently you haven't been paying attention either. When you come to > conclusions that make no sense, except in the case of an arbitrary ordering > that makes no sense, do you take those conclusions as fact? The usual > ordering of numbers is the one that makes them make sense. Numbers are > naturally ordered by quantity, since that's what they represent. > Numbers do indeed have a natural ordering. They also have other > orderings. What Daryl has said applies to other orderings. > As was pointed out, precision does not equate to accuracy. If your shots > cluster tightly, great, you're precise. But, if they are hitting the tree 8 > feet to the left of the target, the gun is useless. If mathematicians conclude > based on cardinality that there are as many integers as rationals, when in fact > there are an infinite number of rationals for every integer (and in fact a > larger infinity than the entire set of integers), then there is something wrong > with cardinality, or at least the interpretation of it. > One might conclude that cardinality isn't the right concept for size > when infinite sets are involved -- one *might* conclude that, but I > can't imagine a better definition myself. Cardinality is very well > motivated from a philosophical standpoint. > But even *if* one doubted that cardinality was the right > generalization of size for infinite sets, that has nothing to do with > your complaints about Daryl's obvious and uncontroversial result. > There is a relation R satisfying (1) - (4) such that it also satisfies > the density property I mention above. His proof is simple and > obvious. > As I've determined, the root flaw in the method is the assumption > that one can rearrange the number system without violating the > definition of its members. So, bull right back atcha! > Yeah, well, the difference between my claim of bull and yours is > that the supporting text made sense in my case. > Look, maybe you have trouble with the term order when it's a > non-standard order. Call a relation R satisfying (1)-(4) a > gigglegoggle. Do you agree or disagree that there exists a > gigglegoggle such that for all x and y where x R y, there exists a z > (and hence infinitely many z) such that x R z and z R y? As I said, the conclusion that there are an infinite number of naturals between any two naturals is nonsensical to me. When that conclusion is drawn from an assumption that numbers can be placed between numbers when their values aren't between the values of the other numbers, then I credit that assumption with the error in the conclusion. So, like I said to Daryl, if you want to make that assumption, then sure, it is valid to draw that conclusion, but you can't claim the conclusion is sound unless you can justify the assumption. Since the conclusion makes no sense, and the assumption makes no sense, I reject the argument. If one can create a 1-1 and onto relation between members of two sets of numbers, *in their natural quantitative order*, and create a bijection, then the two sets have exactly the same size. When you introduce reordering of numbers, then you confound the picture so that you can basically only distinguish between countable infinities and continuous infinities of different dimensions. So, while you cannot imagine a better method of distinguishing infinities, I can. Is that really bull? -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science <39r2t1F6495bnU1@individual.net> <87y8cnmlct.fsf@phiwumbda.org> <87sm2vmk1n.fsf@phiwumbda.org> Discussion, linux) > Jesse F. Hughes said: >> Look, maybe you have trouble with the term order when it's a >> non-standard order. Call a relation R satisfying (1)-(4) a >> gigglegoggle. Do you agree or disagree that there exists a >> gigglegoggle such that for all x and y where x R y, there exists a z >> (and hence infinitely many z) such that x R z and z R y? > As I said, the conclusion that there are an infinite number of naturals between > any two naturals is nonsensical to me. When that conclusion is drawn from an > assumption that numbers can be placed between numbers when their values aren't > between the values of the other numbers, then I credit that assumption with the > error in the conclusion. So, like I said to Daryl, if you want to make that > assumption, then sure, it is valid to draw that conclusion, but you can't claim > the conclusion is sound unless you can justify the assumption. Since the > conclusion makes no sense, and the assumption makes no sense, I reject the > argument. I really have no idea what you mean. Let me ask again: Do you agree or disagree that there is a relation R on N satisfying the following conditions? (1) x R x (2) x R y and y R z implies x R z (3) x R y and y R x implies x = y (4) x R y or y R x (5) x R y implies there is a z such that x R z and z R y This is what Daryl has explicitly shown. You seem to think it involves moving numbers about, but it doesn't. It's a simple fact about the exist of a certain relation on N. > If one can create a 1-1 and onto relation between members of two sets of > numbers, *in their natural quantitative order*, and create a bijection, then > the two sets have exactly the same size. When you introduce reordering of > numbers, then you confound the picture so that you can basically only > distinguish between countable infinities and continuous infinities of different > dimensions. So, while you cannot imagine a better method of distinguishing > infinities, I can. Is that really bull? I don't see why order types are a particularly natural method of judging the sizes of sets. A good method of judging the sizes of linearly ordered sets *as such*, perhaps. But the set of natural numbers is a set as well as a linear ordered set. We can ask how it compares to the set Q without reference to its order as well as how it compares with respect to its order. They're distinct questions and they're both sensible questions. -- [Y]ou never understood the real role of mathematicians. The position is one of great responsibility and power. [...] You people have no concept of what it means to be an actual mathematician versus pretending to be one, dreaming you understand. -- James S. Harris === Subject: Re: Epistemology 201: The Science of Science Jesse F. Hughes said: > Jesse F. Hughes said: >> >> Look, maybe you have trouble with the term order when it's a >> non-standard order. Call a relation R satisfying (1)-(4) a >> gigglegoggle. Do you agree or disagree that there exists a >> gigglegoggle such that for all x and y where x R y, there exists a z >> (and hence infinitely many z) such that x R z and z R y? >> >> > As I said, the conclusion that there are an infinite number of naturals between > any two naturals is nonsensical to me. When that conclusion is drawn from an > assumption that numbers can be placed between numbers when their values aren't > between the values of the other numbers, then I credit that assumption with the > error in the conclusion. So, like I said to Daryl, if you want to make that > assumption, then sure, it is valid to draw that conclusion, but you can't claim > the conclusion is sound unless you can justify the assumption. Since the > conclusion makes no sense, and the assumption makes no sense, I reject the > argument. > I really have no idea what you mean. Let me ask again: > Do you agree or disagree that there is a relation R on N satisfying > the following conditions? > (1) x R x > (2) x R y and y R z implies x R z > (3) x R y and y R x implies x = y > (4) x R y or y R x > (5) x R y implies there is a z such that x R z and z R y > This is what Daryl has explicitly shown. You seem to think it > involves moving numbers about, but it doesn't. It's a simple fact > about the exist of a certain relation on N. > If one can create a 1-1 and onto relation between members of two sets of > numbers, *in their natural quantitative order*, and create a bijection, then > the two sets have exactly the same size. When you introduce reordering of > numbers, then you confound the picture so that you can basically only > distinguish between countable infinities and continuous infinities of different > dimensions. So, while you cannot imagine a better method of distinguishing > infinities, I can. Is that really bull? > I don't see why order types are a particularly natural method of > judging the sizes of sets. A good method of judging the sizes of > linearly ordered sets *as such*, perhaps. But the set of natural > numbers is a set as well as a linear ordered set. We can ask how it > compares to the set Q without reference to its order as well as how it > compares with respect to its order. They're distinct questions and > they're both sensible questions. Daryl's example for infinite naturals between any two naturals involved an ordering which was entirely non-standard. That's why he was able to draw that conclusion. In the context of the ordering, the conclusion is valid, but the ordering is artificial, and the conclusion cannot be applied to natural numbers in their natural order. By any normal sense of the naturals, it is not at all true that there are an infinite number of naturals between any two naturals. It is only in the context of a number system which totally rearranged so as to be almost unrecognizable. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science <39r2t1F6495bnU1@individual.net> <87y8cnmlct.fsf@phiwumbda.org> <87sm2vmk1n.fsf@phiwumbda.org> <874qfatbwq.fsf@phiwumbda.org> Discussion, linux) > Jesse F. Hughes said: >> I don't see why order types are a particularly natural method of >> judging the sizes of sets. A good method of judging the sizes of >> linearly ordered sets *as such*, perhaps. But the set of natural >> numbers is a set as well as a linear ordered set. We can ask how it >> compares to the set Q without reference to its order as well as how it >> compares with respect to its order. They're distinct questions and >> they're both sensible questions. > Daryl's example for infinite naturals between any two naturals involved an > ordering which was entirely non-standard. Duh. Explicitly so. > That's why he was able to draw that conclusion. Duh. He never claimed otherwise and he explicitly and repeatedly drew attention to the non-standard nature of his ordering. > In the context of the ordering, the conclusion is valid, but the > ordering is artificial, and the conclusion cannot be applied to > natural numbers in their natural order. No kidding. No one has claimed that it *does* apply to the naturals in their standard order. Anyway, nice to see that you're in total agreement with Daryl. -- Jesse F. Hughes I think the burden is on those people who think he didn't have weapons of mass destruction to tell the world where they are. -- White House spokesman Ari Fleischer === Subject: Re: Epistemology 201: The Science of Science Tony says... >As I said, the conclusion that there are an infinite number of >naturals between any two naturals is nonsensical to me. It's nonsensical to me, as well. As I said, nobody has drawn that conclusion. You got that conclusion by misquoting what I have said, by leaving out the most important part, namely, according to a particular ordering. >When that conclusion is drawn from an >assumption that numbers can be placed between >numbers when their values aren't between the >values of the other numbers, It's not an assumption if it is provably true. It is provably true that there exists orderings on the naturals other than the usual one. Write out what you think the assumption is in mathematical terms, and tell me why you think the assumption is false. Here's what I believe about orderings: Definition: If S is a set, and R is a binary relation on S, then we say that R is a total ordering on S if 1. For all x and y in S, either R(x,y) or R(y,x) 2. For all x, y and z in S, R(x,y) and R(y,z) implies R(x,z). Definition: If R is a total ordering on set S, and x,y, and z are elements of S, then we say that y is between x and z according to that ordering if R(x,y) and R(y,z). Theorem: There exists a total ordering R on the naturals such that 2 is between 0 and 1 according to that ordering. Proof: Let R(x,y) == if (x=2 and y=1) then true else x < y By definition of R, we find R(0,2) and R(2,1). By definition of between, 2 is between 0 and 1 according to ordering R. This is the ordering 0 2 1 3 4 5 ... Theorem: There exists a total ordering R on the naturals such that there are infinitely many naturals between 0 and 1 according to that ordering. Proof: Let R(x,y) == if x=y then false else if (x=1 or y=2) then true else x < y This is the ordering 0 2 3 4 5 6 ... 1 So exactly what am I assuming that you don't believe? Are you saying that I can't write down the above orderings? I just did. >then I credit that assumption with the >error in the conclusion. If you would actually quote the *entire* conclusion, then you would see that it isn't an error. It becomes an error when you misquote it. That makes the error due to *your* mistakes, not those of anyone else. >So, like I said to Daryl, if you want to make that >assumption, then sure, it is valid to draw that conclusion, >but you can't claim the conclusion is sound unless you can >justify the assumption. One way to justify an assumption is to prove it. That's been done. >Since the conclusion makes no sense, I agree that your conclusion makes no sense, but it wasn't *my* conclusion. My conclusion included the phrase according to the ordering, which is a critical point. >and the assumption makes no sense, I reject the argument. Why don't you reject the habit of misquoting conclusions? >If one can create a 1-1 and onto relation between members of two sets of >numbers, *in their natural quantitative order*, and create a bijection, then >the two sets have exactly the same size. You don't mean that. There exists a bijection between the naturals and the even naturals that preserves the natural quantitative ordering: n --> 2n You really don't know what you mean, do you? >When you introduce reordering of numbers, then you >confound the picture I would say that when you misquote people in such a way as to change the meaning of what they are saying, you confound the picture. >so that you can basically only distinguish between countable >infinities and continuous infinities of different >dimensions. *Who* can only distinguish between countable infinities and continuous infinities of different dimensions? I can certainly distinguish between the rationals and the naturals based on their order type, or based on the fact that one is a subset of the other. I can certainly distinguish between the naturals and the even numbers based on the fact that one is a subset of the other, and also based on the fact that the relative frequency of one set is 1/2 the relative frequency of the other set. You seem to have a totalitarian mindset in which anything that is not forbidden is mandatory. The fact that I *can* compare two sets using cardinality doesn't imply that I *must* compare them using cardinality. >So, while you cannot imagine a better method of distinguishing >infinities, I can. No, you can't. You haven't come up with any better method. There are no distinctions that you have been able to make that are not already well understood by conventional mathematics, which includes the tools of cardinality, relative frequency, measure, subset relationships, and order types. -- Daryl McCullough Ithaca, NY === Subject: Re: Epistemology 201: The Science of Science <39r2t1F6495bnU1@individual.net> <87y8cnmlct.fsf@phiwumbda.org> <87sm2vmk1n.fsf@phiwumbda.org> Discussion, linux) > Tony says... >>As I said, the conclusion that there are an infinite number of >>naturals between any two naturals is nonsensical to me. > It's nonsensical to me, as well. As I said, nobody has drawn that > conclusion. You got that conclusion by misquoting what I have said, > by leaving out the most important part, namely, according to a > particular ordering. >>When that conclusion is drawn from an >>assumption that numbers can be placed between >>numbers when their values aren't between the >>values of the other numbers, > It's not an assumption if it is provably true. It is provably > true that there exists orderings on the naturals other than the > usual one. > Write out what you think the assumption is in mathematical > terms, and tell me why you think the assumption is false. > Here's what I believe about orderings: > Definition: If S is a set, and R is a binary relation on > S, then we say that R is a total ordering on S if > 1. For all x and y in S, either R(x,y) or R(y,x) > 2. For all x, y and z in S, R(x,y) and R(y,z) implies > R(x,z). I guess you usually want anti-symmetry, too: R(x,y) and R(y,x) implies x = y. Else, you have a total pre-order. You don't need reflexivity, since that's provable by (1). I've been including it in my list, but it's not necessary. -- Jesse F. Hughes Ultimately, I can bring the entire mathematical establishment to its knees... Live in a fantasy world if you wish, but to me that's just an expression of your intellectual inferiority. --James Harris === Subject: Re: Epistemology 201: The Science of Science <39r2t1F6495bnU1@individual.net> <87y8cnmlct.fsf@phiwumbda.org> <87sm2vmk1n.fsf@phiwumbda.org> <87zmx2rs0r.fsf@phiwumbda.org> Discussion, linux) >> Tony says... >As I said, the conclusion that there are an infinite number of >naturals between any two naturals is nonsensical to me. >> It's nonsensical to me, as well. As I said, nobody has drawn that >> conclusion. You got that conclusion by misquoting what I have said, >> by leaving out the most important part, namely, according to a >> particular ordering. >When that conclusion is drawn from an >assumption that numbers can be placed between >numbers when their values aren't between the >values of the other numbers, >> It's not an assumption if it is provably true. It is provably >> true that there exists orderings on the naturals other than the >> usual one. >> Write out what you think the assumption is in mathematical >> terms, and tell me why you think the assumption is false. >> Here's what I believe about orderings: >> Definition: If S is a set, and R is a binary relation on >> S, then we say that R is a total ordering on S if >> 1. For all x and y in S, either R(x,y) or R(y,x) >> 2. For all x, y and z in S, R(x,y) and R(y,z) implies >> R(x,z). > I guess you usually want anti-symmetry, too: R(x,y) and R(y,x) implies > x = y. Else, you have a total pre-order. Oops! You're using a slightly different definition in the rest of your post, namely one in which R(x,y) implies NOT R(y,x). Nothing controversial, of course. Just the difference between <= and <. -- What if [...] these people HATE mathematics itself, but possibly hang out here to prove to themselves that there's nothing really to it and live in the fantasy that they can conquer mathematics itself? You know, like arsonists who become firefighters. --James S Harris === Subject: Re: Epistemology 201: The Science of Science Daryl McCullough said: > Tony says... >As I said, the conclusion that there are an infinite number of >naturals between any two naturals is nonsensical to me. > It's nonsensical to me, as well. As I said, nobody has drawn that > conclusion. You got that conclusion by misquoting what I have said, > by leaving out the most important part, namely, according to a > particular ordering. The ordering was the premise, and the conclusion about naturals is nonsensical, because the premise is nonsensical, because numbers come after smaller numbers and before larger numbers, by their very nature. In other words, once you rearrange the numbers, it is no longer the natural number system. What if you reordered the numbers from the beginning with Peano's axioms and said 3 came before 2? Wouldn't that just constitute switching the meanings of the two symbols? Wouldn't 3 mean this many ** and 2 mean this many ***? >When that conclusion is drawn from an >assumption that numbers can be placed between >numbers when their values aren't between the >values of the other numbers, > It's not an assumption if it is provably true. It is provably > true that there exists orderings on the naturals other than the > usual one. Is it provably true that the meaning that numbers derive from their order remains intact when the order is changed? I imagine it's provably false. > Write out what you think the assumption is in mathematical > terms, and tell me why you think the assumption is false. > Here's what I believe about orderings: > Definition: If S is a set, and R is a binary relation on > S, then we say that R is a total ordering on S if > 1. For all x and y in S, either R(x,y) or R(y,x) > 2. For all x, y and z in S, R(x,y) and R(y,z) implies R(x,z). > Definition: If R is a total ordering on set S, and x,y, and z > are elements of S, then we say that y is between x and z according > to that ordering if R(x,y) and R(y,z). > Theorem: There exists a total ordering R on the naturals such > that 2 is between 0 and 1 according to that ordering. > Proof: Let R(x,y) == if (x=2 and y=1) then true else x < y > By definition of R, we find R(0,2) and R(2,1). > By definition of between, 2 is between 0 and 1 > according to ordering R. > This is the ordering 0 2 1 3 4 5 ... > Theorem: There exists a total ordering R on the naturals such > that there are infinitely many naturals between 0 and 1 according > to that ordering. > Proof: Let R(x,y) == if x=y then false else if (x=1 or y=2) then true > else x < y > This is the ordering 0 2 3 4 5 6 ... 1 > So exactly what am I assuming that you don't believe? Are you saying > that I can't write down the above orderings? I just did. You can create any orderings you like, and draw conclusions based on those orderings. You cannot apply those conslusions generally. If you have a use for such a number system and such a fact concerning it, by all means derive your conclusions. But conclusions drawn from such ordering cannot be applied to the number system in its natural order. There are infinitely many more rationals than integers, in the real world, despite what ordering the rationals into a traversible matrix may imply in the Garden of Cantor. >then I credit that assumption with the >error in the conclusion. > If you would actually quote the *entire* conclusion, > then you would see that it isn't an error. It becomes > an error when you misquote it. That makes the error > due to *your* mistakes, not those of anyone else. I left out your premise. >So, like I said to Daryl, if you want to make that >assumption, then sure, it is valid to draw that conclusion, >but you can't claim the conclusion is sound unless you can >justify the assumption. > One way to justify an assumption is to prove it. That's been done. So, you proved that 15 comes before 2 and 6? Well, you also proved 3<2, so what do I expect? >Since the conclusion makes no sense, > I agree that your conclusion makes no sense, but it wasn't *my* > conclusion. My conclusion included the phrase according to the > ordering, which is a critical point. That phrase was an assertion, along with the validity of the method of bijection. >and the assumption makes no sense, I reject the argument. > Why don't you reject the habit of misquoting conclusions? >If one can create a 1-1 and onto relation between members of two sets of >numbers, *in their natural quantitative order*, and create a bijection, then >the two sets have exactly the same size. > You don't mean that. There exists a bijection between the > naturals and the even naturals that preserves the natural > quantitative ordering: > n --> 2n Then why does 4 appear before 3 does? Perhaps the definition needs refinement. It's a work in progess. I never claimed to have a full system worked out. That doesn't invalidate my objections. > You really don't know what you mean, do you? >When you introduce reordering of numbers, then you >confound the picture > I would say that when you misquote people in such a way > as to change the meaning of what they are saying, you > confound the picture. Boo hoo, you separated my premise frmm my conclusion to indetify the flaw in my argument. Come on Daryl, you know that given A then B is the same as if A is true then B is true, so your statement is equivalent to if there is an ordering R, then there are infinitely many naturals between any two naturals. The ordering serves as a starting assertion and the statement about naturals is the conclusion drawn. In the context of the premise the conclusion is valid, but conclusions drawn on artifical orderings cannot be applied to naturally ordered number systems. The fact is, there are infinitely many more rationals than integers, and the fact is that there are not really in infinite number of naturals between any two naturals. It is possible to draw any conclusion you want, validly, by using unsound assertions, but if you want to draw sound consclusions you have to start with real, true assertions. >so that you can basically only distinguish between countable >infinities and continuous infinities of different >dimensions. > *Who* can only distinguish between countable infinities > and continuous infinities of different dimensions? I > can certainly distinguish between the rationals and > the naturals based on their order type, or based on > the fact that one is a subset of the other. I can > certainly distinguish between the naturals and the > even numbers based on the fact that one is a subset > of the other, and also based on the fact that the > relative frequency of one set is 1/2 the relative > frequency of the other set. > You seem to have a totalitarian mindset in which anything > that is not forbidden is mandatory. The fact that I *can* > compare two sets using cardinality doesn't imply > that I *must* compare them using cardinality. I am only saying that cardinality does not capture these distinctions when it introduces artificial orderings. The other methods you mentioned for catching those distinction, if you will notice, involve no reordering of the number system. That's why they are able to make those distinctions. >So, while you cannot imagine a better method of distinguishing >infinities, I can. > No, you can't. You haven't come up with any better method. There > are no distinctions that you have been able to make that are not > already well understood by conventional mathematics, which includes > the tools of cardinality, relative frequency, measure, subset > relationships, and order types. I have successfully pointed out flaws in Cantor's method and their root source. I have not yet completed the method which will replace cardinality and unseat Cantor. I certainly have demonstrated that I can imagine a better method that draws sounder conclusions. > -- > Daryl McCullough > Ithaca, NY -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science > As I said, the conclusion that there are an infinite number of naturals between > any two naturals is nonsensical to me. If you are talking about the usual linear ordering, you are quite correct. If you are talking about -any- linear ordering you are quite wrong. There are linear orderings of the naturals which are dense and there are linear orders of the naturals which are not dense. The important thing is that the ordering in question must be specified or defined first, then statements can be made about it. Bob Kolker === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > > As I said, the conclusion that there are an infinite number of naturals between > any two naturals is nonsensical to me. > If you are talking about the usual linear ordering, you are quite > correct. If you are talking about -any- linear ordering you are quite > wrong. There are linear orderings of the naturals which are dense and > there are linear orders of the naturals which are not dense. > The important thing is that the ordering in question must be specified > or defined first, then statements can be made about it. > Bob Kolker See, Bob? You say the same thing over and over, refuse to acknowledge the problems I have pointed out, and insist on drawing false conclusions from false premises. You accuse me of not understanding you, but your responses sound like I have said what? instead of addressing particulars, because you dson't acknowledge them. Ho hum. The important thing is that the order of numbers not contradict their values, or the conclusion you draw from that order will contradict sense. -- Smiles, Tony === Subject: Distinct linear orderings on Z > Jesse, apparently you haven't been paying attention either. When you come to > conclusions that make no sense, If the ordering is defined it makes sense. It may not make the sense you want to make, but it makes sense. The set of distinct linear orderings on Z (the integers) has infinte cardinality. Now here is a serious question: (therefore not addressed to Tony or Albert). How many (in the sense of cardinality) distinct linear orderings are there on Z. I say two linear orderings L1 and L2 are distinct if L1 cannot be gotten from L2 by an order isomorphism with the ground set Z. Bob Kolker === Subject: Re: Distinct linear orderings on Z robert j. kolker said: > > Jesse, apparently you haven't been paying attention either. When you come to > conclusions that make no sense, > If the ordering is defined it makes sense. It may not make the sense you > want to make, but it makes sense. The set of distinct linear orderings > on Z (the integers) has infinte cardinality. > Now here is a serious question: (therefore not addressed to Tony or > Albert). How many (in the sense of cardinality) distinct linear > orderings are there on Z. I say two linear orderings L1 and L2 are > distinct if L1 cannot be gotten from L2 by an order isomorphism with the > ground set Z. > Bob Kolker Ooohh Ooohh!! Aleph-1! Aleph-1!!! -- Smiles, Tony === Subject: Re: Distinct linear orderings on Z > Now here is a serious question: (therefore not addressed to Tony or > Albert). How many (in the sense of cardinality) distinct linear > orderings are there on Z. I say two linear orderings L1 and L2 are > distinct if L1 cannot be gotten from L2 by an order isomorphism with > the ground set Z. I think the answer is aleph1 (the first uncountable ordinal). There are certainly aleph1 nonisomprophic well-orderings (for aleph1 is the set of all countable ordinals). Isn't any linear ordering of Z a pasting of a reverse well-ordering to a well-ordering? Or can one show otherwise that there are at most aleph1 linear orderings? -- Stephen J. Herschkorn sjherschko@netscape.net === Subject: Re: Epistemology 201: The Science of Science > Have you been paying attention Bob? In the context of numbers, between means > greater than one and less than the other, in quantity. By this deifnition, does > the conclusion make any sense? Greater with respect to what linear ordering? There are many linear orderings. If you mean the ordering induced by the Peano successor function there between an integer and its successor there is no integer. Bob Kolker === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > > Have you been paying attention Bob? In the context of numbers, between means > greater than one and less than the other, in quantity. By this deifnition, does > the conclusion make any sense? > Greater with respect to what linear ordering? There are many linear > orderings. If you mean the ordering induced by the Peano successor > function there between an integer and its successor there is no integer. > Bob Kolker And what other ordering of the naturals would you prefer? Does any other than the inherent ordering make sense? Clearly, not. Therefore the conclusion that there are infinitely many naturals between any pair of naturals is clearly wrong. Therefore there is clearly a flaw in the method. Therefore, if I were you, I would not try to prove anything to ME using that method, because I won't be fooled, now that I've identified the root problem with it. If I were you, I would further stop accepting it as true, just because it hasn't been voted out of office yet. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science > And what other ordering of the naturals would you prefer? Does any other than > the inherent ordering make sense? Any well defined linear ordering makes as much sense (or as little sense) as any other well defined linear ordering. > Clearly, not. Therefore the conclusion that > there are infinitely many naturals between any pair of naturals is clearly > wrong. This is the case wrt the normal ordering, i.e. the ordering induced by the successor function. But it is NOT generally true of all linear orderings on Z. Consider a mapping g from the set of integers Z into the set of rationals such that g is one to one onto. Such functions exist. Now define R(x,y) where x,y in Z to mean g(x) < g(y). It is trivial to show that R is a linear ordering on Z. Now let x, y in Z be distinct integers. Assume without loss of generality that g(x) < g(y) in the set of Rationals. Then there exist a rational number w such that g(x) < w < g(y). By definition of R, R(x, g-inverse(w)) and R(g-inverse(w), y). So in the R ordering g-inverse (w) is between (i.e. with respect to the linear ordering R) x and y. In particular this is true for x = 1 an y = 2. So there are linear orderings on the integers such that there is an integer between 1 and 2. So to say there is no integer between an integer and its successor one must specify the linear ordering to which between pertains. Bob Kolker === Subject: Re: Epistemology 201: The Science of Science robert j. kolker said: > > And what other ordering of the naturals would you prefer? Does any other than > the inherent ordering make sense? > Any well defined linear ordering makes as much sense (or as little > sense) as any other well defined linear ordering. > Clearly, not. Therefore the conclusion that > there are infinitely many naturals between any pair of naturals is clearly > wrong. > This is the case wrt the normal ordering, i.e. the ordering induced by > the successor function. But it is NOT generally true of all linear > orderings on Z. Consider a mapping g from the set of integers Z into > the set of rationals such that g is one to one onto. Such functions > exist. Now define R(x,y) where x,y in Z to mean g(x) < g(y). It is > trivial to show that R is a linear ordering on Z. Now let x, y in Z be > distinct integers. Assume without loss of generality that g(x) < g(y) in > the set of Rationals. Then there exist a rational number w such that > g(x) < w < g(y). By definition of R, R(x, g-inverse(w)) and > R(g-inverse(w), y). So in the R ordering g-inverse (w) is between > (i.e. with respect to the linear ordering R) x and y. In particular this > is true for x = 1 an y = 2. So there are linear orderings on the > integers such that there is an integer between 1 and 2. So to say > there is no integer between an integer and its successor one must > specify the linear ordering to which between pertains. > Bob Kolker Yet another example of number theory obfuscation. Very good. 1 and 2 have lost their meanings. Good job. Have a cookie. You might want to consider if you could possibly get all the counterintuitive results you get without reordering numbers out of sequence. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science aeo6 says... >Yet another example of number theory obfuscation. Very good. 1 and 2 have lost >their meanings. Good job. Have a cookie. Are you saying that if I write down 3 1 4 that suddenly 3 has lost its meaning? *I* still remember what it means, even if you don't. With a little practice, you can learn to recite your telephone number, or the digits of pi, even when the digits are out of order. The digits don't lose their meaning. -- Daryl McCullough Ithaca, NY === Subject: Re: Epistemology 201: The Science of Science > aeo6 says... >>Yet another example of number theory obfuscation. Very good. 1 and 2 have lost >>their meanings. Good job. Have a cookie. > Are you saying that if I write down > 3 1 4 > that suddenly 3 has lost its meaning? *I* still remember what it > means, even if you don't. With a little practice, you can learn > to recite your telephone number, or the digits of pi, even when > the digits are out of order. The digits don't lose their meaning. A telephone number is not a number. It is a character string composed of numerals. -- I consider it quite possible that physics cannot be based on the field concept, i. e., on continuous structures. In that case nothing remains of my entire castle in the air, gravitation theory included, [and of] the rest of modern physics. -- Albert Einstein in a 1954 letter to Michele Besso. === Subject: Re: Epistemology 201: The Science of Science :> aeo6 says... :>>Yet another example of number theory obfuscation. Very good. 1 and 2 have lost :>>their meanings. Good job. Have a cookie. :> Are you saying that if I write down :> 3 1 4 :> that suddenly 3 has lost its meaning? *I* still remember what it :> means, even if you don't. With a little practice, you can learn :> to recite your telephone number, or the digits of pi, even when :> the digits are out of order. The digits don't lose their meaning. : A telephone number is not a number. It is a character string : composed of numerals. An ordering is not a number either. Once again you miss the point. Stephen === Subject: Re: Epistemology 201: The Science of Science stephen@nomail.com said: > :> aeo6 says... > :> > :> > :>>Yet another example of number theory obfuscation. Very good. 1 and 2 have lost > :>>their meanings. Good job. Have a cookie. > :> > :> > :> Are you saying that if I write down > :> > :> 3 1 4 > :> > :> that suddenly 3 has lost its meaning? *I* still remember what it > :> means, even if you don't. With a little practice, you can learn > :> to recite your telephone number, or the digits of pi, even when > :> the digits are out of order. The digits don't lose their meaning. > : A telephone number is not a number. It is a character string > : composed of numerals. > An ordering is not a number either. Once again you miss > the point. > Stephen It's not hard to miss the point of a statement that has no connection to anything that anyone has said. I think Albert hit the nail on the head by calling it a phone number. I never said you can't write digits in any order. It was a pointless question. It's you who miss the point of the entire discussion. Who ever said an ordering was a number? Take a vitamin. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science Daryl McCullough said: > aeo6 says... >Yet another example of number theory obfuscation. Very good. 1 and 2 have lost >their meanings. Good job. Have a cookie. > Are you saying that if I write down > 3 1 4 > that suddenly 3 has lost its meaning? *I* still remember what it > means, even if you don't. With a little practice, you can learn > to recite your telephone number, or the digits of pi, even when > the digits are out of order. The digits don't lose their meaning. > -- > Daryl McCullough > Ithaca, NY If you are saying 3 comes before 1, which immediately precedes 4 in a number system, then you are changing the meaning of the numerals. Of course there are an infinite number of uses for placing numbers in all sorts of orders. I am talking specifically about rearranging the number system, but I thought I made that clear already. Pay attention. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science Tony says... >Daryl McCullough said: >> Are you saying that if I write down >> 3 1 4 >> that suddenly 3 has lost its meaning? *I* still remember what it >> means, even if you don't. With a little practice, you can learn >> to recite your telephone number, or the digits of pi, even when >> the digits are out of order. The digits don't lose their meaning. >If you are saying 3 comes before 1, which immediately precedes 4 in a number >system, then you are changing the meaning of the numerals. Who said anything about a number system? I am talking about orderings of the natural number system. Sometimes, we write 3 before 1; for example, when we are writing out the decimal expansion of pi. That doesn't mean that 3 has lost its meaning. -- Daryl McCullough Ithaca, NY === Subject: Re: Epistemology 201: The Science of Science Daryl McCullough said: > Tony says... >Daryl McCullough said: >> Are you saying that if I write down >> >> 3 1 4 >> >> that suddenly 3 has lost its meaning? *I* still remember what it >> means, even if you don't. With a little practice, you can learn >> to recite your telephone number, or the digits of pi, even when >> the digits are out of order. The digits don't lose their meaning. > >If you are saying 3 comes before 1, which immediately precedes 4 in a number >system, then you are changing the meaning of the numerals. > Who said anything about a number system? I am talking about orderings > of the natural number system. Sometimes, we write 3 before 1; for example, > when we are writing out the decimal expansion of pi. That doesn't mean > that 3 has lost its meaning. > -- > Daryl McCullough > Ithaca, NY That is entirely unrelated to the reordering of the number system that I was cautioning against. The use of digits to form numbers is a matter of a digital system for expressing numbers as numerals. If you write 3.1415, that's a number between 3.1 and 3.2. Do you think I am saying that all 1's should come before all 2's? I have never made any such stupid assertion. My statement was specifically in the context of cardinality and concerning arbitrary reorderings of the number system in general to achieve a mapping function. And people accuse me of being confused....... -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science Tony says... >Daryl McCullough said: >> Who said anything about a number system? I am talking about orderings >> of the natural number system. Sometimes, we write 3 before 1; for example, >> when we are writing out the decimal expansion of pi. That doesn't mean >> that 3 has lost its meaning. >That is entirely unrelated to the reordering of the number system that I was >cautioning against. Nobody talked about reordering the number system. You are confused. -- Daryl McCullough Ithaca, NY === Subject: Re: Epistemology 201: The Science of Science Daryl McCullough said: > Tony says... >Daryl McCullough said: >> Who said anything about a number system? I am talking about orderings >> of the natural number system. Sometimes, we write 3 before 1; for example, >> when we are writing out the decimal expansion of pi. That doesn't mean >> that 3 has lost its meaning. > >That is entirely unrelated to the reordering of the number system that I was >cautioning against. > Nobody talked about reordering the number system. You are confused. > -- > Daryl McCullough > Ithaca, NY So, sticking 15 between 2 and 5 isn't reordering the number system? Counting through the multiples of two before getting to 9 isn't reordering the number system? What are all these orderings performed in bijections, then? I am not confused. followed immediately by, I am talking about orderings of the natural number system. I guess the answer to the question would be you, based on the statement that immediately follows it. And now you say, Nobody talked about reordering the number system. You are confused. So, what were you talking about immediately before? It's all right there, so don't accuse me of misquoting you. I am not the confused one. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science Tony says... >Daryl McCullough said: >> Nobody talked about reordering the number system. You are confused. >So, sticking 15 between 2 and 5 isn't reordering the number system? Sticking 15 between 2 and 5 sounds as if someone is picking numbers up and moving them around. That isn't possible, since numbers are abstractions, not physical objects. Instead, what people have done is to define a new ordering on the naturals. Defining an binary relation on numbers doesn't do anything to the numbers. -- Daryl McCullough Ithaca, NY === Subject: Re: Epistemology 201: The Science of Science > Daryl McCullough said: >>aeo6 says... >What I object to is the use of numbers in orderings that are not consistent, >using a technique that is not proven, to derive results that contradict more >basic notions of set theory >>Well, nobody is using numbers in orderings that are not consistent, and >>nobody is deriving results that contradict more basic notions of set theory. > If the ordering of quantities is inconsistent with the quantities, then the > ordering is inconsistent. If a set contains all the elements of another set, > plus some more, then it has more. These are pretty basic concepts that I > shouldn't have to repeat. >>I already told you, the result is not there are an infinite number >>of naturals between any two naturals, the result is that for the >>particular ordering that I defined, there are infinitely many >>naturals between any two naturals. >Right, but do you believe the conclusion based on that ordering? >>The conclusion is: There exists an ordering R(x,y) on naturals >>such that between any two naturals x and y, there exists infinitely >>many naturals z such that R(x,z) and R(z,y). >>Yes, I believe that. I constructed such an ordering. >Is it true that there are infinitely many naturals between >any two naturals, given the normal meaning of between for >natural numbers? >>Of course not. >If not, then you should examine the train of thought that led to >that conclusion >>Nothing led to that conclusion. You are misquoting the conclusion. >>I came to the conclusion that >>There exists an ordering R(x,y) on naturals >>such that between any two naturals x and y, >>there exists infinitely many naturals z such >>that R(x,z) and R(z,y). > You are not being honest. Here is your actual quote: > I didn't say that. I said that for that particular *ordering* on the > naturals, there exists infinitely many naturals between > any pair of naturals. It is a property of the ordering, not the > underlying set. > Now, do you believe that there exists infinitely many naturals between > any pair of naturals or not? If not, how do you explain the conclusion you > drew? Read what you quoted, Tony. It's all there. And stop smoking up - it addles your brain. [...] === Subject: Re: Epistemology 201: The Science of Science Wolf Kirchmeir said: any pair of naturals or not? If not, how do you explain the conclusion you > drew? > Read what you quoted, Tony. It's all there. And stop smoking up - it > addles your brain. > [...] Pay attention, don't be insulting, and answer the question, as I have already pointed out the flaw in your orderings, and apparently need to rub your nose in it and admit that the conclusion is false to get anywhere. Read carefully and answer the question, oh self-addler. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science aeo6 says... >Daryl McCullough said: >> aeo6 says... >What I object to is the use of numbers in orderings that are not consistent, >using a technique that is not proven, to derive results that contradict more >>basic notions of set theory >> Well, nobody is using numbers in orderings that are not consistent, and >> nobody is deriving results that contradict more basic notions of set theory. >If the ordering of quantities is inconsistent with the quantities What is that phrase supposed to mean? An ordering is a binary relation. Are you trying to say that you think that there is only one possible binary relation on the naturals? >then the ordering is inconsistent. What does it mean to say that an ordering is inconsistent? You're not making any sense. >If a set contains all the elements of another set, >plus some more, then it has more. It has more according to the subset relation on sets. Nobody argues with that. >These are pretty basic concepts that I shouldn't have to repeat. Nobody is arguing about the basic concepts: 1. If every element of A is also an element of B, but not vice-versa, then A is a proper subset of B. 2. The set of reals in [0,1] has half the measure of the set of reals in [0,2]. 3. The relative frequency of even naturals is half the relative frequency of all naturals. 4. The order type of the rationals is larger than the order type of the naturals. (That is, the naturals can be embedded in the rationals in an order-preserving way, but not vice-versa). The part that people disagree with is that you want to use the phrase has more elements for all 4 cases. That's just being perverse. The technical definitions of subset, measure, relative frequency, order embedding, and cardinality are different. No definition captures everything that you might want to say about the relationship between sets. You are arguing about words, and insisting that people use your terminology, which glosses over at least 5 different distinctions. >> There exists an ordering R(x,y) on naturals >> such that between any two naturals x and y, >> there exists infinitely many naturals z such >> that R(x,z) and R(z,y). >You are not being honest. Here is your actual quote: >I didn't say that. I said that for that particular *ordering* on the >naturals, there exists infinitely many naturals between >any pair of naturals. It is a property of the ordering, not the >underlying set. How is that different? In both cases, I'm saying that the betweeness relationship is a property of the *ordering*, and whether or not there are infinitely many naturals between any two naturals depends on what *ordering* you are using. >Now, do you believe that there exists infinitely many naturals between >any pair of naturals or not? Why do you keep leaving out the important phrase for the particular ordering? That is the *key* phrase, and you keep deleting it. Betweeness is a property of the ordering. >If not, how do you explain the conclusion you drew? The conclusion is that for that particular *ordering* on the naturals, there exists infinitely many naturals between any pair of naturals. That's a true conclusion. It is *provably* true. If you are rejecting it, then you are being inconsistent. >> Or, what's actually the case, you misquoted the conclusion. >Or not. You did misquote it. I specifically said for that particular ordering, and you left that phrase out. >>This is yet another example of how artificial orderings that >>violate the natural order of real numbers can lead to erroneous >>results. >> The only erroneous results are due to you. >Try again. Okay. The only erroneous results are due to you. >> My conclusion wasn't wrong---yours was. >Read your quoted conclusion above, again. You misquoted it by leaving out the phrase for the particular ordering I defined. >> Nobody disagrees with the fact that, with the usual ordering >> on the rationals, there are infinitely many rationals between >> any two integers. >Are there infinitely many integers between any two rationals? For which ordering? Betweeness depends on the ordering. For the *usual* ordering, there are infinitely many rationals between any two naturals, and not vice-versa. >No? What does that tell you about the relative numbers integers >and rationals? Nothing. It tells something about the *order* type of the rationals. >>To draw a conclusion so drastically different from the blatantly >>obvious, >> The only conclusion is that there exists a bijection between >> the rationals and the integers. That's provably the case. >More bijection genuflection. What does this case prove? It's just a fact. A fact that you have trouble with, for some reason. >Certainly nothing about the relative numbers of integers and rationals. There are several *different* relationship between the set of integers and the set of rationals: 1. The order type of the rationals is larger than the order type of the integers. 2. The integers are a subset of the rationals. 3. The cardinality of the integers is the same as the cardinality of the rationals. For you to say there are more rationals than there are integers is *ambiguous*. It might mean in the sense of order type, it might mean in the sense of subsets, it might mean in the sense of cardinality. >>using a technique that is assumed to work because it >>looks neat, >> That's not true. >Why else is it accepted? It's accepted for the same reasons any good theory is accepted: It is rigorous, it produces interesting results, it produces results that are useful in a wide variety of fields. >>but is not supported by any empirical evidence or >>application to reality, >> That's not true. >What empirical evidence can you offer? Cardinality theory is a critical part of measure theory, which in turn is a critical ingredient to probability theory. Probability theory has been very successful in a wide range of practical applications. >> What conclusion? The concusion is that there is a bijection >> between the integers and the rationals. You disagree with that >> conclusion? >No, just with the conclusion that there exists infinitely many naturals >between any pair of naturals Nobody made that conclusion. The conclusion was that For the particular binary relation R(x,y) that I defined, there are infinitely many naturals between any two naturals. Leaving out the phrase for the particular binary relation is leaving out the important part. Betweenness is a property of *orderings*. >> I don't see how the word entitled applies here. You are almost >> completely ignorant of the subject that you are criticizing, and >> your criticism doesn't amount to a hill of beans. The complaints >> you have are almost all complaints about *word* choice, which is >> about the silliest basis for criticizing mathematics. >That is entirely untrue. Then what *mathematical* complaint do you have? Express it in the language of mathematics. If you are going to use a phrase such as has more elements, then give a *mathematical* definition of how you are interpreting that phrase. I offered 4 different interpretations of has more elements: 1. Has a higher relative frequency. 2. Has a larger cardinality. 3. Has a larger order type. 4. Is a superset. (Each of these have precise definitions, if you are unclear about them.) If you want to use yet another notion of has more elements, then give a mathematical definition. You can't use an informal phrase in mathematics without giving a mathematical definition. >see that you have not been reading too carefully, as I've been making a clear >case that the conclusions drawn from bijection are overdrawn. Do you now agree >that the conclusion you drew, which I quoted, is incorrect? You have consistently quoted me incorrectly. In particular, I have consistently said that the word betweenness in a phrase such as There are infinitely many elements z between x and y is a property of the *ordering*, not a property of the underlying sets. When you leave off the specification of the ordering, you are changing the meaning of the phrase. -- Daryl McCullough Ithaca, NY === Subject: Re: Epistemology 201: The Science of Science Daryl McCullough said: > aeo6 says... >Daryl McCullough said: >> aeo6 says... >> >What I object to is the use of numbers in orderings that are not consistent, >using a technique that is not proven, to derive results that contradict more >>basic notions of set theory >> >> Well, nobody is using numbers in orderings that are not consistent, and >> nobody is deriving results that contradict more basic notions of set theory. >If the ordering of quantities is inconsistent with the quantities > What is that phrase supposed to mean? An ordering is a binary relation. > Are you trying to say that you think that there is only one possible > binary relation on the naturals? >then the ordering is inconsistent. > What does it mean to say that an ordering is inconsistent? You're > not making any sense. There is one natural ordering of numbers in general, and that's where smaller quantitative values precede larger values. Any other ordering violates the members' identities as numbers. >If a set contains all the elements of another set, >plus some more, then it has more. > It has more according to the subset relation on sets. Nobody > argues with that. Except Mr. Cardinality, but he's half blind. >These are pretty basic concepts that I shouldn't have to repeat. > Nobody is arguing about the basic concepts: > 1. If every element of A is also an element of B, but not > vice-versa, then A is a proper subset of B. > 2. The set of reals in [0,1] has half the measure of the set > of reals in [0,2]. > 3. The relative frequency of even naturals is half the relative > frequency of all naturals. > 4. The order type of the rationals is larger than the order > type of the naturals. (That is, the naturals can be embedded > in the rationals in an order-preserving way, but not vice-versa). > The part that people disagree with is that you want to use the > phrase has more elements for all 4 cases. That's just being > perverse. The technical definitions of subset, measure, > relative frequency, order embedding, and cardinality > are different. No definition captures everything that you > might want to say about the relationship between sets. > You are arguing about words, and insisting that people use > your terminology, which glosses over at least 5 different > distinctions. See below. >> There exists an ordering R(x,y) on naturals >> such that between any two naturals x and y, >> there exists infinitely many naturals z such >> that R(x,z) and R(z,y). >You are not being honest. Here is your actual quote: >I didn't say that. I said that for that particular *ordering* on the >naturals, there exists infinitely many naturals between >any pair of naturals. It is a property of the ordering, not the >underlying set. > How is that different? In both cases, I'm saying that the > betweeness relationship is a property of the *ordering*, > and whether or not there are infinitely many naturals > between any two naturals depends on what *ordering* you > are using. You denied saying there were infinite many naturals between any two naturals, so I showed you your quote and asked you to defend it. If you saw no difference between the two, then why did you accuse me of misquoting and rephrase it? Is there something wrong with the way you phrased it the first time? This is exactly what I object to. That there are an infinite number of naturals between any two naturals is rotten hogwash used to make diaper tea. You can't really believe that statement, can you? >Now, do you believe that there exists infinitely many naturals between >any pair of naturals or not? > Why do you keep leaving out the important phrase for the particular > ordering? That is the *key* phrase, and you keep deleting it. I delete it because it is the flaw in your argument. I am asking if, in any real sense, in your mind, regardless of any ordering, it seems at all plausible that there are infinitely many naturals between any pair of naturals, using a sensible consistent definition for between. What naturals are more than 2 and less than 3? The conclusion is wrong, therefore there is a problem with the method, or some assumption applied to it. The problem is in the reordering of inherently ordered elements, while using the inherent orders as well. This is some typical makings of your standard paradox. Paradoxes are all resolvable. they all boil down to mutually contradictory terms where the contradiction is not obvious. Incidentally, all paradoxes are counterintuitive, aren't they? > Betweeness is a property of the ordering. >If not, how do you explain the conclusion you drew? > The conclusion is that for that particular *ordering* on the > naturals, there exists infinitely many naturals between > any pair of naturals. That's a true conclusion. It is *provably* > true. If you are rejecting it, then you are being inconsistent. You can prove it based on Cantor's theorems, but are they provable? Somewhere in the mix is the assumption that you can change the order of numbers and preserve their identities as numbers. This is false, and needs to be eliminated if any kind of consistency between these methods is to be achieved. >> Or, what's actually the case, you misquoted the conclusion. >Or not. > You did misquote it. I specifically said for that particular > ordering, and you left that phrase out. That's not how you corrected it. You changed the language so it didn't say there are an infinite number of naturals between any pair of naturals, which was dishonest. I left out the ordering aspect because it's not relevant to what I am asking. Do you actually, not in the context of any ordering but in general, see that conclusion as being correct? I have asked this several times, and you refuse to answer. Can you answer the question directly? I can. >>This is yet another example of how artificial orderings that >>violate the natural order of real numbers can lead to erroneous >>results. >> >> The only erroneous results are due to you. >Try again. > Okay. The only erroneous results are due to you. >> My conclusion wasn't wrong---yours was. >Read your quoted conclusion above, again. > You misquoted it by leaving out the phrase for the > particular ordering I defined. Explained twice already above. >> Nobody disagrees with the fact that, with the usual ordering >> on the rationals, there are infinitely many rationals between >> any two integers. >Are there infinitely many integers between any two rationals? > For which ordering? Betweeness depends on the ordering. For > the *usual* ordering, there are infinitely many rationals > between any two naturals, and not vice-versa. Correct. For the regular, non-ridiculous, non-meaning-violating order. >No? What does that tell you about the relative numbers integers >and rationals? > Nothing. It tells something about the *order* type of the rationals. Which indicates there are more rationals than integers, which means they comprise a larger set. >>To draw a conclusion so drastically different from the blatantly >>obvious, >> >> The only conclusion is that there exists a bijection between >> the rationals and the integers. That's provably the case. >More bijection genuflection. What does this case prove? > It's just a fact. A fact that you have trouble with, for some reason. What does the bijection prove? What inference can you draw from it, besides that, according to the method you have used, it is the conclusion you have drawn? The bijection does not mean the sets are of equal size. It means that the cardinality measure as defined does not distinguish between them. Please show a proof of the validity of equating set size with cardinality for infinite sets, which doesn't circularly fall back on the definition of cardinality as the size of the set. >Certainly nothing about the relative numbers of integers and rationals. > There are several *different* relationship between the set of > integers and the set of rationals: > 1. The order type of the rationals is larger than the order > type of the integers. > 2. The integers are a subset of the rationals. > 3. The cardinality of the integers is the same as the cardinality > of the rationals. > For you to say there are more rationals than there are integers is > *ambiguous*. It might mean in the sense of order type, it might mean > in the sense of subsets, it might mean in the sense of cardinality. I don't think it's ambiguous at all. I think it is the case in fact, and any method that fails to detect that fails in that respect. It's not a matter of opinion. It's not sometimes true. It's true universally. If the interpretation of cardinality is that it's not true, then the interpretation is wrong. I think it is ambiguous to have several different ways of answering the same question, and getting different answers depending on how you ask it. The question, in your mind, has no definite answer. If that's not ambiguity, then I don't know what is. >>using a technique that is assumed to work because it >>looks neat, >> >> That's not true. >Why else is it accepted? > It's accepted for the same reasons any good theory is accepted: > It is rigorous, it produces interesting results, it produces results > that are useful in a wide variety of fields. What is the application of the fact that there are as many integers as rationals in some abstract sense, operationally? >>but is not supported by any empirical evidence or >>application to reality, >> >> That's not true. >What empirical evidence can you offer? > Cardinality theory is a critical part of measure theory, which > in turn is a critical ingredient to probability theory. Probability > theory has been very successful in a wide range of practical > applications. In dealing with infinite sets of rationals vs. integers? >> What conclusion? The concusion is that there is a bijection >> between the integers and the rationals. You disagree with that >> conclusion? >No, just with the conclusion that there exists infinitely many naturals >between any pair of naturals > Nobody made that conclusion. The conclusion was that > For the particular binary relation R(x,y) that I defined, > there are infinitely many naturals between any two naturals. I stated the conclusion correctly. The first part is an assertion upon which the conclusion is based. This is basic logic, to wit: the particular binary relation R(x,y) -> there are infinitely many naturals between any two naturals in the form A->B (A implies B) Now, if A->B and B is false, then what can you say about A? This is easy, and what I have been pointing out all along. It seems like I have to iterate my way through the infinite set of ways of saying the same thing to get anywhere with this. A is false, the ordering is self-contradictory, and the conclusions drawn from a self-contradictory construct are unsound at best. > Leaving out the phrase for the particular binary relation is > leaving out the important part. Betweenness is a property of *orderings*. Numbers are already inherently ordered. >> I don't see how the word entitled applies here. You are almost >> completely ignorant of the subject that you are criticizing, and >> your criticism doesn't amount to a hill of beans. The complaints >> you have are almost all complaints about *word* choice, which is >> about the silliest basis for criticizing mathematics. >That is entirely untrue. > Then what *mathematical* complaint do you have? Express it > in the language of mathematics. If you are going to use a > phrase such as has more elements, then give a *mathematical* > definition of how you are interpreting that phrase. I offered > 4 different interpretations of has more elements: > 1. Has a higher relative frequency. > 2. Has a larger cardinality. > 3. Has a larger order type. > 4. Is a superset. > (Each of these have precise definitions, if you are unclear about > them.) > If you want to use yet another notion of has more elements, > then give a mathematical definition. You can't use an informal > phrase in mathematics without giving a mathematical definition. >see that you have not been reading too carefully, as I've been making a clear >case that the conclusions drawn from bijection are overdrawn. Do you now agree >that the conclusion you drew, which I quoted, is incorrect? > You have consistently quoted me incorrectly. In particular, I have > consistently said that the word betweenness in a phrase such as > There are infinitely many elements z between x and y > is a property of the *ordering*, not a property of the underlying > sets. When you leave off the specification of the ordering, you > are changing the meaning of the phrase. For the last time, the ordering is the flaw. I can't say this any more clearly than I already have. If you believe that there are in fact infinitely many naturals between any two naturals, by the normal definition of between, then we should just drop it, because there's no place to go from there. > -- > Daryl McCullough > Ithaca, NY -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science > Daryl McCullough said: [...] >>Why do you keep leaving out the important phrase for the particular >>ordering? That is the *key* phrase, and you keep deleting it. > I delete it because it is the flaw in your argument. No, you deklete it becasue if you you leave it oin you would realise that the question you pose in the next sentence is unanswerable. For a expositon on unanswerable questions, go to Augutsine - he's been dead. lo these many centuries, but he realsied that abdly formulated question couldn't be answerd. One of his > I am asking if, in any > real sense, in your mind, regardless of any ordering, it seems at all plausible > that there are infinitely many naturals between any pair of naturals, using a > sensible consistent definition for between. This is a meaningless question. Ordering is a way of defining what it means for an object to be between two other objects. You're also begging the question by use of that weasel word sensible, by which you clearly intyend acceptable to Tony. IOW, if the definition implies conclusions you disagree with, the definition can't have been sensible. That's been the logical form of your claim all along, in fact - you don't agree with X, so X must be nonsense. Attempting to analyse your notion of natural order, I infer that you think that the counting sequence is the only way to arrange the natural numbers. Maybe you assume that {1st, 2nd, 3rd, ...} is the same set as {1, 2, 3, ...}. These are different: that is, theorems that are true about the cardinal numbers aren't true about the natural numbers, and vice versa. Is that not obvious? > What naturals are more than 2 and > less than 3? More than and less than isn't the same as to one side of and to other side of w/ ref. to the number row. As a matter of fact, you can deduce that 3 > 2 and 2 < 3 from a specific ordering of the natural numbers, and not from other orderings. > The conclusion is wrong, therefore there is a problem with the > method, or some assumption applied to it. The problem is in the reordering of > inherently ordered elements, while using the inherent orders as well. There are no inherently ordered elements. (I suspect that this belief arises from our experience of time.) All orderings are constructed. This is obvious in the case of alphabetical order, not obvious in the case of the natural numbers or cardinal numbers. Counting Order is just one way to order them. But occasionally, even in ordinary life, this order is violated, and may even be ignored. Eg, a selection rule might be, Pick the even numbered ones, then the odd numbered ones. Or, Pick the large ones, then the middle sized ones, then the leftovers, which _ignores_ counting order. > This is > some typical makings of your standard paradox. Paradoxes are all resolvable. > they all boil down to mutually contradictory terms where the contradiction is > not obvious. Incidentally, all paradoxes are counterintuitive, aren't they? [...] Well, depends what you mean by counter-intuitive. Some of the most famous are thoroughly inutuitive, such as Zeno's paradox that the Achilles will never catch up to the Tortoise. Zeno showed that reasoning based on intuitions could lead you all the way into absurdity. IMO, paradoxes arise when people rely on incompatible intuitions, so paradoxes are all intuitive in this sense. They are counter-intuitive in the sense that they set intuitions against each other -- ie, they reveal that the inutitons are inconsistent. === Subject: Re: Epistemology 201: The Science of Science aeo6 says... >There is one natural ordering of numbers in general, and that's where smaller >quantitative values precede larger values. Any other ordering violates the >members' identities as numbers. How does it violate the member's identities as numbers? You are saying that as soon as I write down an ordering such as R(x,y) == (x+y is even and x > y) or (x+y is odd and x < y) that I'm *violating* the natural numbers? So I'm not allowed to define such a relation? That doesn't make a bit of sense. >>If a set contains all the elements of another set, >>plus some more, then it has more. >> It has more according to the subset relation on sets. Nobody >> argues with that. >Except Mr. Cardinality, but he's half blind. Who do you think Mr. Cardinality is? Nobody said that cardinality is the only relationship between sets. Mathematics uses cardinality, subset, measure theory, order types, relative frequency as appropriate. >>These are pretty basic concepts that I shouldn't have to repeat. >> Nobody is arguing about the basic concepts: >> 1. If every element of A is also an element of B, but not >> vice-versa, then A is a proper subset of B. >> 2. The set of reals in [0,1] has half the measure of the set >> of reals in [0,2]. >> 3. The relative frequency of even naturals is half the relative >> frequency of all naturals. >> 4. The order type of the rationals is larger than the order >> type of the naturals. (That is, the naturals can be embedded >> in the rationals in an order-preserving way, but not vice-versa). >> The part that people disagree with is that you want to use the >> phrase has more elements for all 4 cases. That's just being >> perverse. The technical definitions of subset, measure, >> relative frequency, order embedding, and cardinality >> are different. No definition captures everything that you >> might want to say about the relationship between sets. >> You are arguing about words, and insisting that people use >> your terminology, which glosses over at least 5 different >> distinctions. >See below. > There exists an ordering R(x,y) on naturals > such that between any two naturals x and y, > there exists infinitely many naturals z such > that R(x,z) and R(z,y). >>You are not being honest. Here is your actual quote: I didn't say that. I said that for that particular *ordering* on the >>naturals, there exists infinitely many naturals between >>any pair of naturals. It is a property of the ordering, not the >>underlying set. >> How is that different? In both cases, I'm saying that the >> betweeness relationship is a property of the *ordering*, >> and whether or not there are infinitely many naturals >> between any two naturals depends on what *ordering* you >> are using. >You denied saying there were infinite many naturals between >any two naturals, so I showed you your quote and asked you >to defend it. Leaving out the phrase for that particular ordering changes the meaning of the quote. So you are not quoting accurately. >If you saw no difference >between the two, then why did you accuse me of misquoting and rephrase >it? Because you misquoted it. You left out the qualifying phrase for that particular ordering. >Is there something wrong with the way you phrased it the first time? No, there is something wrong with the way *you* phrased it, namely, you left out the phrase for that particular ordering. >This is exactly what I object to. If you object to misquoting people, then don't do it. >That there are an infinite number of naturals between >any two naturals is rotten hogwash used to make diaper tea. >You can't really believe that statement, can you? I never made that statement. I made the statement for that particular *ordering* on the naturals, there exists infinitely many naturals between any pair of naturals. It is a property of the ordering, not the underlying set. You keep deleting the crucial phrase for that particular ordering, which completely changes the meaning. >>Now, do you believe that there exists infinitely many naturals between >>any pair of naturals or not? >> Why do you keep leaving out the important phrase for the particular >> ordering? That is the *key* phrase, and you keep deleting it. >I delete it because it is the flaw in your argument. How does misquoting me point out a flaw in my argument? >I am asking if, in any real sense, in your mind, regardless of >any ordering, it seems at all plausible that there are infinitely >many naturals between any pair of naturals, using a >sensible consistent definition for between. There *is* no meaning of between that does not depend on a choice of ordering. Between inherently involves ordering. >The conclusion is wrong, The conclusion For the particular ordering that I defined on the naturals, there exists infinitely many naturals between any pair of naturals. It is a property of the ordering, not the underlying set. is not wrong. For that notion of ordering, it is true that there are infinitely many naturals between any pair of naturals. >therefore there is a problem with the >method, or some assumption applied to it. There is a problem when misquote a claim so as to change the meaning. >The problem is in the reordering of >inherently ordered elements, There is no problem, other than the fact that you continually misquote what I say. >while using the inherent orders as well. This is >some typical makings of your standard paradox. There is no paradox. There is no problem, other than your sloppiness. >> Betweeness is a property of the ordering. >>If not, how do you explain the conclusion you drew? >> The conclusion is that for that particular *ordering* on the >> naturals, there exists infinitely many naturals between >> any pair of naturals. That's a true conclusion. It is *provably* >> true. If you are rejecting it, then you are being inconsistent. >You can prove it based on Cantor's theorems, but are they provable? Yes. That's why they are called theorems. >Somewhere in the mix is the assumption that you can change the >order of numbers and preserve their identities as numbers. >This is false I didn't *change* the ordering of the naturals, I defined a *different* ordering on the naturals. The fact that I define a new binary relation on the naturals doesn't do *anything* to the naturals. You have a totalitarian view of mathematics, in which anything that is not forbidden is mandatory. The fact that I choose to use a *different* ordering on the naturals for some purpose does not imply that I have eliminated the usual ordering. >> You did misquote it. I specifically said for that particular >> ordering, and you left that phrase out. >That's not how you corrected it. You changed the language so it didn't say >there are an infinite number of naturals between any pair of naturals, which >was dishonest. There exists an ordering R(x,y) on naturals such that between any two naturals x and y, there exists infinitely many naturals z such that R(x,z) and R(z,y). But z is between x and y (according to ordering R) means the same thing as R(x,z) and R(z,y). That's what between means. >I left out the ordering aspect because it's not relevant to what >I am asking. If you leave out the ordering, then between doesn't mean *anything*. Between only has meaning for an ordering. So by leaving out the ordering aspect, you completely changed the meaning of the sentence. >Do you actually, not in the context of any ordering but in >general, see that conclusion as being correct? Between doesn't mean anything except in the context of an ordering. >I have asked this several times, >and you refuse to answer. Can you answer the question directly? I can. You ask a nonsense question, and you get mad because I don't answer it. You can't ask someone to disregard ordering, and then *also* ask him to say how many elements are between 1 and 2. Between only makes sense relative to an ordering. >> You misquoted it by leaving out the phrase for the >> particular ordering I defined. >Explained twice already above. By leaving out the phrase for the particular ordering I defined, you completely changed the meaning. >>Are there infinitely many integers between any two rationals? >> For which ordering? Betweeness depends on the ordering. For >> the *usual* ordering, there are infinitely many rationals >> between any two naturals, and not vice-versa. >Correct. For the regular, non-ridiculous, non-meaning-violating order. The phrases non-ridiculous and non-meaning-violating add nothing *mathematically* to the statement. The fact is between is relative to an ordering, and whether there are infinitely many elements z between x and y is a fact about an *ordering*, not about the underlying set. >>No? What does that tell you about the relative numbers integers >>and rationals? >> Nothing. It tells something about the *order* type of the rationals. >Which indicates there are more rationals than integers, which means they >comprise a larger set. No, it doesn't. It indicates that the order type of the rationals under the usual ordering is larger than the order type of the naturals under the usual ordering. >To draw a conclusion so drastically different from the blatantly >obvious, > > The only conclusion is that there exists a bijection between > the rationals and the integers. That's provably the case. More bijection genuflection. What does this case prove? >> It's just a fact. A fact that you have trouble with, for some reason. >What does the bijection prove? It doesn't prove anything. It is just a fact about rationals and naturals. There are a number of things we can say about the naturals and the rationals: 1. The set of naturals is a proper subset of the set of rationals. 2. The usual order type of the naturals is smaller than the usual order type of the rationals. 3. The cardinality of the naturals is equal to the cardinality of the rationals. These three facts together tell more about the relationship between the rationals and the naturals than any single fact separately. The phrase There are more rationals than naturals doesn't say anything, since it is ambiguous whether it means 1,2, 3 or something else. >What inference can you draw from it, besides >that, according to the method you have used, it is the conclusion you have >drawn? The bijection does not mean the sets are of equal size. That's because there are about 5 different definitions of size. Cardinality is one. Measure is another. Order type is another. Subset is another. Relative frequency is another. >It means that the cardinality measure as defined does not >distinguish between them. That's right. Cardinality makes some distinctions, measure theory makes other distinctions, the subset relationship makes other distinctions, relative frequency makes other distinctions, order type makes yet other distinctions. Why do you want to pick on cardinality? It doesn't make all possible distinctions, but no notion of size can possibly make all possible distinctions. >Please show a proof of the validity of equating set size with >cardinality for infinite sets which doesn't circularly fall >back on the definition of cardinality as the size of the set. What does it mean to prove that a definition is valid? >>Certainly nothing about the relative numbers of integers and rationals. >> There are several *different* relationship between the set of >> integers and the set of rationals: >> 1. The order type of the rationals is larger than the order >> type of the integers. >> 2. The integers are a subset of the rationals. >> 3. The cardinality of the integers is the same as the cardinality >> of the rationals. >> For you to say there are more rationals than there are integers is >> *ambiguous*. It might mean in the sense of order type, it might mean >> in the sense of subsets, it might mean in the sense of cardinality. >I don't think it's ambiguous at all. I gave you three different common interpretations of the phrase set A has more elements than set B. That makes it ambiguous. >It's not a matter of opinion. No, it's a matter of definition. Whether set A has more elements than set B depends on how you define has more elements. >I think it is ambiguous to have several different ways of answering the same >question, If the question is a *mathematical* question, then there is a single answer for it. But a question involving *intuitive* notions of size is not a mathematical question until you give a mathematical definition of what you mean by size. >> It's accepted for the same reasons any good theory is accepted: >> It is rigorous, it produces interesting results, it produces results >> that are useful in a wide variety of fields. >What is the application of the fact that there are as many integers as >rationals in some abstract sense, operationally? In computer science, the fact that every countable set can be coded as an integer is an important fact. It allows us to iterate over rationals, lists, ordered pairs, etc. as easily as we loop over integers. >but is not supported by any empirical evidence or >application to reality, > > That's not true. What empirical evidence can you offer? >> Cardinality theory is a critical part of measure theory, which >> in turn is a critical ingredient to probability theory. Probability >> theory has been very successful in a wide range of practical >> applications. >In dealing with infinite sets of rationals vs. integers? > What conclusion? The concusion is that there is a bijection > between the integers and the rationals. You disagree with that > conclusion? No, just with the conclusion that there exists infinitely many naturals >>between any pair of naturals >> Nobody made that conclusion. The conclusion was that >> For the particular binary relation R(x,y) that I defined, >> there are infinitely many naturals between any two naturals. >I stated the conclusion correctly. No. You didn't. Leaving out the context for the particular binary relation R(x,y) completely changes the meaning. >> You have consistently quoted me incorrectly. In particular, I have >> consistently said that the word betweenness in a phrase such as >> There are infinitely many elements z between x and y >> is a property of the *ordering*, not a property of the underlying >> sets. When you leave off the specification of the ordering, you >> are changing the meaning of the phrase. >For the last time, the ordering is the flaw. For the last time, no it's not. >If you believe that there are in fact infinitely many >naturals between any two naturals I have said that I *don't* believe that. You have to specify according to what ordering. >by the normal definition of between I've said many times that according to the usual ordering on rationals, there are infinitely many rationals between any pair of naturals. That is a fact about the ordering, not about the size of the underlying sets. -- Daryl McCullough Ithaca, NY === Subject: Re: Epistemology 201: The Science of Science Discussion, linux) > aeo6 says... >>If you saw no difference >>between the two, then why did you accuse me of misquoting and rephrase >>it? > Because you misquoted it. You left out the qualifying phrase > for that particular ordering. I think that Tony fails to see the equivalence between the following two statements. Maybe not, but why else complain about your rephrasing? There exists an ordering R(x,y) on naturals such that between any two naturals x and y, there exists infinitely many naturals z such that R(x,z) and R(z,y). I didn't say that. I said that for that particular *ordering* on the naturals, there exists infinitely many naturals between any pair of naturals. It is a property of the ordering, not the underlying set. -- Jesse F. Hughes Besides, discoverers are too proud to kiss butt. Indiana Jones would never kiss some academic's ass to get published, and neither will I. --James Harris === Subject: Re: Epistemology 201: The Science of Science : aeo6 says... :>What is the application of the fact that there are as many integers as :>rationals in some abstract sense, operationally? : In computer science, the fact that every countable set can be coded : as an integer is an important fact. It allows us to iterate over : rationals, lists, ordered pairs, etc. as easily as we loop over integers. I have already pointed out that the fact each rational number is computable is an application of the fact that there are not more rationals than integers. For each rational number there clearly exists a Turing Machine that computes it, and each Turing Machine can be encoded as an integer. I have yet to hear what the application of the fact that there are not as many integers as rationals is. Stephen === Subject: Re: Epistemology 201: The Science of Science stephen@nomail.com said: > : aeo6 says... > :>What is the application of the fact that there are as many integers as > :>rationals in some abstract sense, operationally? > : In computer science, the fact that every countable set can be coded > : as an integer is an important fact. It allows us to iterate over > : rationals, lists, ordered pairs, etc. as easily as we loop over integers. > I have already pointed out that the fact each rational number > is computable is an application of the fact that there are not > more rationals than integers. For each rational number there clearly > exists a Turing Machine that computes it, and each Turing Machine > can be encoded as an integer. > I have yet to hear what the application of the fact that there are > not as many integers as rationals is. > Stephen Sure, you can translate any countable grammar into any other if you want. That's fine. It doesn't explain the flaw in the idea that for any integer x there are an infinite number of rationals between it and the next integer x+1, namely x*n+m/n for for m=1 to oo and n=m+1 to oo, and that if this is true of every integer, it is true for integers in general. The set of rationals should be considered to have the integral of the size of the integers, not the same size, that is, if the size of the integers is x, then the size of the rationals is x^2/2, and the size of the set of reals should be considered to be the infinitieth integral of x. You may consider this exercise an application of the theory to the reality of the real numbers. -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >: aeo6 says... >:>What is the application of the fact that there are as many integers as >:>rationals in some abstract sense, operationally? >: In computer science, the fact that every countable set can be coded >: as an integer is an important fact. It allows us to iterate over >: rationals, lists, ordered pairs, etc. as easily as we loop over integers. >I have already pointed out that the fact each rational number >is computable is an application of the fact that there are not >more rationals than integers. For each rational number there clearly >exists a Turing Machine that computes it, and each Turing Machine >can be encoded as an integer. >I have yet to hear what the application of the fact that there are >not as many integers as rationals is. Well for that matter we're all waiting with bated breath to hear what the application of sets and subsets of equal undefined cardinality is? === Subject: Re: Epistemology 201: The Science of Science Discussion, linux) >> What does it mean to say that an ordering is inconsistent? You're >> not making any sense. > There is one natural ordering of numbers in general, and that's where smaller > quantitative values precede larger values. Any other ordering violates the > members' identities as numbers. Violates the members' identities as numbers? Is that a misdemeanor or a felony? Is Daryl gonna get nicked for that one? This is nonsense. A relation R is a linear order of N iff for every n,m,p in N, the following hold: (1) n R n (2) n R m and m R p implies n R p (3) n R m and m R n implies n = m (4) n R m or m R n There are gobs of such relations on N. Oodles even. I'd say there were infinitely many, but certain small brains in this discussion might object. The existence of such relations don't violate the members' identities as numbers, their sensibilities, chastity or anything else. It's just a particular kind of relation, nothing scarier than a subset of N x N satisfying certain nice properties. -- Jesse F. Hughes But nothing's being Dr. Ullrich is a particular case of something's being such that nothing is it: (Ex)~(Ey)(y = x) -- John Correy on the failings of first order logic === Subject: Re: Epistemology 201: The Science of Science <39eq3eF614usvU2@individual.net> <4234a632.28350469@netnews.att.net> <39jq7jF61e1pvU2@individual.net> <9x3Zd.10663$Fy.1366@okepread04> <39lvtbF63mmkhU2@individual.net> <39mo82F63lffvU2@individual.net> <39n5fvF62s52iU2@individual.net> In , on 03/15/2005 at 10:36 PM, mmeron@cars3.uchicago.edu said: >How about a fly? That's a rather arthropromorphic concept. The arthropods, and indeed all of the metazoans, are outnumbered and outweighed by the bacteria. -- Shmuel (Seymour J.) Metz, SysProg and JOAT Unsolicited bulk E-mail subject to legal action. I reserve the right to publicly post or ridicule any abusive E-mail. Reply to domain Patriot dot net user shmuel+news to contact me. Do not === Subject: Re: Epistemology 201: The Science of Science > That's a rather arthropromorphic concept. The arthropods, and indeed > all of the metazoans, are outnumbered and outweighed by the bacteria. God is a germ? Bob Kolker === Subject: Re: Epistemology 201: The Science of Science >> That's a rather arthropromorphic concept. The arthropods, and indeed >> all of the metazoans, are outnumbered and outweighed by the bacteria. >God is a germ? I've often speculated that based on interbreedable numbers homo s. is the most successful species in the history of the earth. === Subject: Re: Epistemology 201: The Science of Science >That's a rather arthropromorphic concept. The arthropods, and indeed >all of the metazoans, are outnumbered and outweighed by the bacteria. >>God is a germ? > I've often speculated that based on interbreedable numbers homo s. is > the most successful species in the history of the earth. What do you mean by interbreedable numbers? And don't speculate, go out there and count 'em. Or read the papers of people who have counted 'em. === Subject: Re: Epistemology 201: The Science of Science >>That's a rather arthropromorphic concept. The arthropods, and indeed >>all of the metazoans, are outnumbered and outweighed by the bacteria. >God is a germ? >> I've often speculated that based on interbreedable numbers homo s. is >> the most successful species in the history of the earth. >What do you mean by interbreedable numbers? And don't speculate, go >out there and count 'em. Or read the papers of people who have counted 'em. Or count the people who have interbred. Wolf, you have a rather nasty habit of telling people what to do. If you can't make anything of my statement, go research the conept for yourself for a change. Then maybe you could explain what you don't understand instead of whining. === Subject: Re: Epistemology 201: The Science of Science Lester Zick said: >> >> >> >> >>That's a rather arthropromorphic concept. The arthropods, and indeed >>all of the metazoans, are outnumbered and outweighed by the bacteria. >>God is a germ? >> >> >> I've often speculated that based on interbreedable numbers homo s. is >> the most successful species in the history of the earth. >> >What do you mean by interbreedable numbers? And don't speculate, go >out there and count 'em. Or read the papers of people who have counted 'em. > Or count the people who have interbred. Wolf, you have a rather nasty > habit of telling people what to do. If you can't make anything of my > statement, go research the conept for yourself for a change. Then > maybe you could explain what you don't understand instead of whining. And we were so close to becoming a ring species. (sigh) -- Smiles, Tony === Subject: Re: Epistemology 201: The Science of Science >Lester Zick said: > > > > >That's a rather arthropromorphic concept. The arthropods, and indeed >all of the metazoans, are outnumbered and outweighed by the bacteria. >>God is a germ? > > > I've often speculated that based on interbreedable numbers homo s. is > the most successful species in the history of the earth. > What do you mean by interbreedable numbers? And don't speculate, go >>out there and count 'em. Or read the papers of people who have counted 'em. >> Or count the people who have interbred. Wolf, you have a rather nasty >> habit of telling people what to do. If you can't make anything of my >> statement, go research the conept for yourself for a change. Then >> maybe you could explain what you don't understand instead of whining. >And we were so close to becoming a ring species. (sigh) Ring species? === Subject: Re: Epistemology 201: The Science of Science >> And a species that can predict that event and model an escape stands a >> chance of surviving even that. Catastrophes will continue erasing the >Two chances: slim and none. >> blackboard until something gets the right answer. >It is human reproductive behaviour that extends our stay (as a species) >not how smart we are. The people who are doing the most reproduction >generally are the least bright of our species. The lower the >intelligence the greater the number of children (on average). No. You are confusing today's demographics with what has happened over the past, long-term. /BAH Subtract a hundred and four for e-mail. === Subject: Re: Epistemology 201: The Science of Science >> People keep confusing cause and effect. Evolution is a description >> of changes we see that has happened. It is a process; people >> have assigned a noun to it. It is not a cause; it isn't an effect. >> It is a summary of all effects observed so far. You can do ^not >> x, and have an evolution immediately pop out. >Evolution = Variation + Natural Selection. Selection is on the basis of >reproductive fitness. Those species that do not reproduce well become >extinct. Those the reproduce in great numbers survive barring a >catastrophe like the comet that hit earth about 65,000,000 ybp This occurs over a long period of time (where long is dependent on life span counts). My point is that the theory is not about one event but a summary of many events after they have happened. Now take a look at what the Creationists assume. They think that somebody gave an incantation and Poof! there was a fully grown animal. Read the arguments that have been given to you here. /BAH Subtract a hundred and four for e-mail. === Subject: A short question about Banach algebra. let B(N,C)=l^{infinity}(N). Then for me it easily follows with norm defined by sup_n|x_n|, l^{infinity} is a banach space. I think Banach algebra is built by giving product as (x_n)*(y_n):=(x_n*y_n) in banach space because banach space is already complete normed vector space. So I think now I have a ring structure on l^{infinity}. If somebody uses the term 'unital' it means the space has identity? What is the unit element in l^{infinity}? === Subject: Re: A short question about Banach algebra. >let B(N,C)=l^{infinity}(N). Then for me it easily follows with norm >defined by sup_n|x_n|, l^{infinity} is a banach space. >I think Banach algebra is built by giving product as >(x_n)*(y_n):=(x_n*y_n) in banach space because banach space is already >complete normed vector space. So I think now I have a ring structure on >l^{infinity}. >If somebody uses the term 'unital' it means the space has identity? Yes >What is the unit element in l^{infinity}? Well, what do you think x_n should be if x_n*y_n = y_n for all y? Robert Israel israel@math.ubc.ca Department of Mathematics http://www.math.ubc.ca/~israel University of British Columbia Vancouver, BC, Canada === Subject: Re: A short question about Banach algebra. :) It should be x_n = 1 i.e. constant sequence ? === Subject: Flies in the ointment. The recent sci.math mudfest with the character Jason contained a number of references to some [perhaps different person] Gabriel, in which it was suggest the this Gabriel person had exhibited a similar lack of propriety on some newsgroup, presumably (at least presumed by me), this occurred on sci.math. I have been unable to find any reference to (John?) Gabriel, and don't actually recall him. As a result, I'm somewhat curious about seeing pointers to his, er, contributions. Dale. === Subject: REPOST: Re: Flies in the ointment. [Randy Poe] ... > I'm beginning to suspect that all original John Gabriel > posts have been deleted. Check out this exchange from > the numerical analysis group, where John Gabriel > appears only in quoted text, but a character named > Jason Wells tells him he is a genius who has revolutionized > calculus: > http://tinyurl.com/3rryy LOL! Jason Wells offering sage counsel to John Gabriel: You have a very abrupt style of responding to objections - if I may, you may try posing your responses as questions rather than 'attacks' as has been interpreted by most. Uh huh. I also stumbled into this amazing scam on Wikipedia: John Gabriel's Nth root algorithm http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm Nothing wrong with the algorithm, but it's just a clumsily-stated direct application of Newton's method to finding a zero of f(y) = y^n-x (iterate y <- y - f(y)/f'(y)). This certainly doesn't go under the name of John Gabriel in any numerical analysis circles I've run in . === Subject: Re: REPOST: Re: Flies in the ointment. ... > I'm beginning to suspect that all original John Gabriel > posts have been deleted. Check out this exchange from > the numerical analysis group, where John Gabriel > appears only in quoted text, but a character named > Jason Wells tells him he is a genius who has revolutionized > calculus: > http://tinyurl.com/3rryy > LOL! Jason Wells offering sage counsel to John Gabriel: > You have a very abrupt style of responding to objections - if I > may, you may try posing your responses as questions rather than > 'attacks' as has been interpreted by most. > Uh huh. > I also stumbled into this amazing scam on Wikipedia: > John Gabriel's Nth root algorithm > http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm > Nothing wrong with the algorithm, The Gabriel algorithm says the iterations are defined by s_(i+1) = ((s_i)^(x/(n - 1)) + (n - 1) s_i)) / n, which seems a little silly. The object is to compute the n-th root of x. As can be seen above, in order to compute the n-th root of x, you will need to compute the (n-1)st root of (s_i)^x. But if you have a way of computing (n - 1)st roots [for arbitray integer n, presumably] in the first place, why do you need the algorithm ? A straightforward implementation of Newton's method to solve y^n = x is simpler and requires only that you can compute integer powers, rather than roots. Nora B. but it's just a clumsily-stated direct > application of Newton's method to finding a zero of f(y) = y^n-x (iterate y > <- y - f(y)/f'(y)). This certainly doesn't go under the name of John > Gabriel in any numerical analysis circles I've run in . === Subject: Re: REPOST: Re: Flies in the ointment. ... [Tim Peters] >> I also stumbled into this amazing scam on Wikipedia: >> John Gabriel's Nth root algorithm >> http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm >> Nothing wrong with the algorithm, [Nora Baron] > The Gabriel algorithm says the iterations are defined by > s_(i+1) = ((s_i)^(x/(n - 1)) + (n - 1) s_i)) / n, > which seems a little silly. Maybe this is browser-dependent. When I look at that page, it's clearly s_i/(x^(n-1)) instead. Which is why I said what I said . If you look at the history of the page, the original version was ASCII art, and not open to this misinterpretation (well, not in a fixed-width font anyway); this is cut-and-paste from page's first revision: x --------- means x divided by (n-1) s ^(n-1) s = s + (n-1)*s i i+1 i i ---------------------- (2) n [...] > A straightforward implementation of Newton's method to solve > y^n = x > is simpler and requires only that you can compute integer powers, > rather than roots. That's what I said: >> but it's just a clumsily-stated direct application of Newton's method >> to finding a zero of f(y) = y^n-x (iterate y <- y - f(y)/f'(y)). I think there's nothing here but a misunderstanding. === Subject: Re: REPOST: Re: Flies in the ointment. >>[Randy Poe] >>... >I'm beginning to suspect that all original John Gabriel >posts have been deleted. Check out this exchange from >the numerical analysis group, where John Gabriel >appears only in quoted text, but a character named >Jason Wells tells him he is a genius who has revolutionized >calculus: >http://tinyurl.com/3rryy >>LOL! Jason Wells offering sage counsel to John Gabriel: >> You have a very abrupt style of responding to objections - if I >> may, you may try posing your responses as questions rather than >> 'attacks' as has been interpreted by most. >>Uh huh. >>I also stumbled into this amazing scam on Wikipedia: >> John Gabriel's Nth root algorithm >> http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm >>Nothing wrong with the algorithm, > The Gabriel algorithm says the iterations are defined by > s_(i+1) = ((s_i)^(x/(n - 1)) + (n - 1) s_i)) / n, > which seems a little silly. The object is to compute the n-th root > of x. As can be seen above, in order to compute the n-th root > of x, you will need to compute the (n-1)st root of (s_i)^x. But if > you have a way of computing (n - 1)st roots [for arbitray integer n, > presumably] in the first place, why do you need the algorithm ? > A straightforward implementation of Newton's method to solve > y^n = x > is simpler and requires only that you can compute integer powers, > rather than roots. > Nora B. I think the problem is with the crappy formatting. Newton's method would give this: s_(i+1) = ( x/ s_i^(n-1) + (n-1) s_i ) / n That is, in the Wikipedia entry, the first term in the numerator for s_(i+1) should read x / s_i^(n-1), not s_i^(x/(n-1)). As such, it would be a correct reading of Newton's method. However, for Gabriel to have appropriated it as his own is ludicrous. Dale === Subject: Re: REPOST: Re: Flies in the ointment. <4Al_d.11477$C47.9472@newssvr14.news.prodigy.com>[Randy Poe] >>... >I'm beginning to suspect that all original John Gabriel >posts have been deleted. Check out this exchange from >the numerical analysis group, where John Gabriel >appears only in quoted text, but a character named >Jason Wells tells him he is a genius who has revolutionized >calculus: >http://tinyurl.com/3rryy LOL! Jason Wells offering sage counsel to John Gabriel: You have a very abrupt style of responding to objections - if I >> may, you may try posing your responses as questions rather than >> 'attacks' as has been interpreted by most. Uh huh. I also stumbled into this amazing scam on Wikipedia: John Gabriel's Nth root algorithm >> http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm Nothing wrong with the algorithm, > The Gabriel algorithm says the iterations are defined by > s_(i+1) = ((s_i)^(x/(n - 1)) + (n - 1) s_i)) / n, > which seems a little silly. The object is to compute the n-th root > of x. As can be seen above, in order to compute the n-th root > of x, you will need to compute the (n-1)st root of (s_i)^x. But if > you have a way of computing (n - 1)st roots [for arbitray integer n, > presumably] in the first place, why do you need the algorithm ? > A straightforward implementation of Newton's method to solve > y^n = x > is simpler and requires only that you can compute integer powers, > rather than roots. > Nora B. > I think the problem is with the crappy formatting. > Newton's method would give this: > s_(i+1) = ( x/ s_i^(n-1) + (n-1) s_i ) / n > That is, in the Wikipedia entry, the first term in the numerator for > s_(i+1) should read x / s_i^(n-1), not s_i^(x/(n-1)). > As such, it would be a correct reading of Newton's method. You're right - that makes a LOT more sense. > However, for Gabriel to have appropriated it as his own is ludicrous. You're even more right on this. Wikipedia needs better editing. Nora B. > Dale === Subject: Re: REPOST: Re: Flies in the ointment. Nora Baron a .8ecrit : >>[Randy Poe] >>... >I'm beginning to suspect that all original John Gabriel >posts have been deleted. Check out this exchange from >the numerical analysis group, where John Gabriel >appears only in quoted text, but a character named >Jason Wells tells him he is a genius who has revolutionized >calculus: >http://tinyurl.com/3rryy >>LOL! Jason Wells offering sage counsel to John Gabriel: >> You have a very abrupt style of responding to objections - if I >> may, you may try posing your responses as questions rather than >> 'attacks' as has been interpreted by most. >>Uh huh. >>I also stumbled into this amazing scam on Wikipedia: >> John Gabriel's Nth root algorithm > http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm >>Nothing wrong with the algorithm, > The Gabriel algorithm says the iterations are defined by > s_(i+1) = ((s_i)^(x/(n - 1)) + (n - 1) s_i)) / n, >which seems a little silly. The object is to compute the n-th root >of x. As can be seen above, in order to compute the n-th root >of x, you will need to compute the (n-1)st root of (s_i)^x. But if >you have a way of computing (n - 1)st roots [for arbitray integer > n, >presumably] in the first place, why do you need the algorithm ? >A straightforward implementation of Newton's method to solve > y^n = x >is simpler and requires only that you can compute integer powers, >rather than roots. > Nora B. >>I think the problem is with the crappy formatting. >>Newton's method would give this: >> s_(i+1) = ( x/ s_i^(n-1) + (n-1) s_i ) / n >>That is, in the Wikipedia entry, the first term in the numerator for >>s_(i+1) should read x / s_i^(n-1), not s_i^(x/(n-1)). >>As such, it would be a correct reading of Newton's method. > You're right - that makes a LOT more sense. >>However, for Gabriel to have appropriated it as his own is ludicrous. > You're even more right on this. Wikipedia needs better editing. Not really possible: I edited it , and it was reverted back to its original misleading (to say the least) version in less than one minute. More and more JSH's like. > Nora B. >>Dale === Subject: Re: REPOST: Re: Flies in the ointment. <4Al_d.11477$C47.9472@newssvr14.news.prodigy.com> <423a8bf5$0$25019$8fcfb975@news.wanadoo.fr Not really possible: I edited it , and it was reverted back to its > original misleading (to say the least) version in less than one minute. > More and more JSH's like. Looks like it was reverted by someone called Inter, who is probably an admin on wikipedia. Reverting back in less than minute is most likely an automated process! === Subject: Re: REPOST: Re: Flies in the ointment. <4Al_d.11477$C47.9472@newssvr14.news.prodigy.com> <423a8bf5$0$25019$8fcfb975@news.wanadoo.fr Nora Baron a .8ecrit : [Randy Poe] >>... >I'm beginning to suspect that all original John Gabriel >posts have been deleted. Check out this exchange from >the numerical analysis group, where John Gabriel >appears only in quoted text, but a character named >Jason Wells tells him he is a genius who has revolutionized >calculus: >http://tinyurl.com/3rryy >>LOL! Jason Wells offering sage counsel to John Gabriel: >> You have a very abrupt style of responding to objections - if I >> may, you may try posing your responses as questions rather than >> 'attacks' as has been interpreted by most. >>Uh huh. >>I also stumbled into this amazing scam on Wikipedia: >> John Gabriel's Nth root algorithm > http://en.wikipedia.org/wiki/John Gabriel%27s Nth root algorithm >>Nothing wrong with the algorithm, >> The Gabriel algorithm says the iterations are defined by >> s (i+1) = ((s i)^(x/(n - 1)) + (n - 1) s i)) / n, >>which seems a little silly. The object is to compute the n-th root >of x. As can be seen above, in order to compute the n-th root >of x, you will need to compute the (n-1)st root of (s i)^x. But if >you have a way of computing (n - 1)st roots [for arbitray integer > n, >presumably] in the first place, why do you need the algorithm ? >A straightforward implementation of Newton's method to solve >> y^n = x >>is simpler and requires only that you can compute integer powers, >rather than roots. >> Nora B. >>I think the problem is with the crappy formatting. >>Newton's method would give this: s (i+1) = ( x/ s i^(n-1) + (n-1) s i ) / n That is, in the Wikipedia entry, the first term in the numerator for >>s (i+1) should read x / s i^(n-1), not s i^(x/(n-1)). As such, it would be a correct reading of Newton's method. > You're right - that makes a LOT more sense. >>However, for Gabriel to have appropriated it as his own is ludicrous. > You're even more right on this. Wikipedia needs better editing. > Not really possible: I edited it , and it was reverted back to its > original misleading (to say the least) version in less than one minute. > More and more JSH's like. Probably Gabriel aka Jason is monitoring this thread I've been reading Wikipedia. Of particular interest are Now though this is clearly a (badly-formatted) version of the Newton-Raphson method, Gabriel is trying to claim it is original research. Wikipedia rules prohibit publishing original research. Wikipedia overview: http://en.wikipedia.org/wiki/Wikipedia (see Policies, Disputes, and Vandalism). Vandalism mechanism: http://en.wikipedia.org/wiki/Wikipedia:Dealing with vandalism http://en.wikipedia.org/wiki/Wikipedia:Votes for deletion mentions the Newton-Raphson algorithm. I'm going to write an n-th root version of this and link back to the square root page. Square roots: http://en.wikipedia.org/wiki/Square root over the line from vanity to vandalism, and Wikipedia has established mechanisms for dealing with that, ultimately resulting in a blocked user. Let's fight the good fight, but it may take a few weeks to sort out. I'm still learning my way through the Wiki world. - Randy === Subject: Re: REPOST: Re: Flies in the ointment. <4Al_d.11477$C47.9472@newssvr14.news.prodigy.com> <423a8bf5$0$25019$8fcfb975@news.wanadoo.fr mentions the Newton-Raphson algorithm. I'm going to write > an n-th root version of this and link back to the square > root page. Done! It's rough, could be reorganized and tightened up a bit, and could stand to be expanded. But now there's http://en.wikipedia.org/wiki/N-th_root_algorithm Suggested expansions: - Methods for picking initial guesses - Termination rules - Examples - The alternate derivation from fixed-point iteration (which I'm not familiar with). - Randy === Subject: Re: REPOST: Re: Flies in the ointment. <4Al_d.11477$C47.9472@newssvr14.news.prodigy.com However, for Gabriel to have appropriated it as his own is ludicrous. > You're even more right on this. Wikipedia needs better editing. > Nora B. Wikipedia is open-source, but it's supposed to be self-correcting. I notice that somebody has made a comment that it's Newton's method. Think I'll take a and see what happens. Randy === Subject: Re: REPOST: Re: Flies in the ointment. [Randy Poe] > Wikipedia is open-source, but it's supposed to be > self-correcting. I notice that somebody has made a > comment that it's Newton's method. Given that the comment is a nearly verbatim repeat of what I posted here last night, my guess is that either Jason Wells added that comment, or that I did . > and see what happens. on the Newton-Raphson method instead, and give this as an interesting example. The Numerical Analysis section of Wikipedia doesn't appear to === Subject: Re: REPOST: Re: Flies in the ointment. <4Al_d.11477$C47.9472@newssvr14.news.prodigy.com> <86KdnaQ5TImBhaffRVn-vQ@comcast.com [Randy Poe] > Wikipedia is open-source, but it's supposed to be > self-correcting. I notice that somebody has made a > comment that it's Newton's method. > Given that the comment is a nearly verbatim repeat of what I posted here > last night, my guess is that either Jason Wells added that comment, or that > I did . > and see what happens. > If you have the time (I sure don't), it would be great to write an > on the Newton-Raphson method instead, and give this as an interesting > example. The Numerical Analysis section of Wikipedia doesn't appear to I had that thought, but just discovered there's a very nice http://en.wikipedia.org/wiki/Newton%27s_method to discuss n-th root-finding as a specific application of I've never done any writing for Wikipedia so I'm not sure what the process is, but I'm definitely going to take a stab at it over the next day or two. Randy === Subject: Re: REPOST: Re: Flies in the ointment. [Tim Peters, to Randy Poe] >> If you have the time (I sure don't), it would be great to write an >> interesting example. The Numerical Analysis section of Wikipedia [Randy Poe] > I had that thought, but just discovered there's a very nice > http://en.wikipedia.org/wiki/Newton%27s_method So there is! Cool. I can't find it again now, but last time I looked I ended up on what claimed to be an alphabetized list of numerical analysis topics, and there was no relevant entry under N. But what I found just now: http://en.wikipedia.org/wiki/List_of_numerical_analysis_topics doesn't have that problem (or form), and is intelligently organized. Damn software bugs . > to discuss n-th root-finding as a specific application of Or even delete it. > I've never done any writing for Wikipedia so I'm not sure > what the process is, but I'm definitely going to take > a stab at it over the next day or two. I haven't either, and would also like to. Won't have sufficient free time for more than a week, so the glory is all yours (and the money, the groupies, everything!). If you can tolerate a hint from an old Open Source hand, write something _you'd_ like to read. Open Source works so long as people contribute work they love. In that sense, John Gabriel's n'th-root contribution was likely appropriate after all . === Subject: Re: REPOST: Re: Flies in the ointment. > I notice that somebody has made a > comment that it's Newton's method. Think I'll take a > and see what happens. Please see also my comment that it is a simple fixed-point iteration obtainable without Newton's method. --r.e.s. === Subject: Re: REPOST: Re: Flies in the ointment. [Randy Poe] >> I notice that somebody has made a >> comment that it's Newton's method. Think I'll take a >> and see what happens. [r.e.s.] > Please see also my comment that it is a simple fixed-point iteration > obtainable without Newton's method. Don't you think that's a stretch, though? I do, for two reasons: 1. General. A zero r of a function f(x) is always a fixed point of a Newton-method iteration (well, assuming f'(r) is defined). Deriving the same formula from a fixed-point perspective may be an exercise in cleverness, but if you can get the same thing directly from applying Newton's method, the latter is preferable because entirely straightforward. 2. Specific. You can find the n'th-root Newton method all over the web, in its weighted-average and raw forms. Heck, it's frequently given as a programming assignment in intro numerical analysis courses. In these contexts, it's always presented as an application of Newton-Raphson (proof: I looked at a lot of course handouts Google could find ). === Subject: Re: REPOST: Re: Flies in the ointment. reply-type=response > [r.e.s.] >> Please see also my comment that it is a simple fixed-point iteration >> obtainable without Newton's method. > Don't you think that's a stretch, though? I do, for two reasons: > 1. General. A zero r of a function f(x) is always a fixed point of a > Newton-method iteration (well, assuming f'(r) is defined). Deriving > the same formula from a fixed-point perspective may be an exercise > in cleverness, but if you can get the same thing directly from > applying Newton's method, the latter is preferable because entirely > straightforward. > 2. Specific. You can find the n'th-root Newton method all over the > web, in its weighted-average and raw forms. Heck, it's frequently > given as a programming assignment in intro numerical analysis > courses. In these contexts, it's always presented as an application > of Newton-Raphson (proof: I looked at a lot of course handouts > Google could find ). I want to add one more comment to my previous reply on those two points. The following is a well-known method intended to improve convergence of fixed-point iterations (or to produce convergence where there otherwise is none): If y = h(y), then y = y + p*(h(y)-y), where p is arbitrary. This is sometimes called a dampening or averaging method, with p in [0,1]; note that y = p*h(y) + (1-p)*y. By adjusting p, the iteration y <- y + p*(h(y)-y) can often be made to converge in cases where y <- h(y) does not. In the present case of y^n = x, the natural first attempt at a fixed-point iteration is y = x/y^(n-1) = h(y), and the averaging method then gives the revised iteration y <- p*x/y^(n-1) + (1-p)*y which is the same algorithm as obtained by Newton-Raphson if one takes p = 1/n (although other values of p also work). This method is not so well-known as Newton-Raphson, to be sure, but I recall it from a numerical analysis course back in the '60s. It seems remotely possible that the wikipedia page on the so-called John Gabriel's method may have originated along these lines. === Subject: Re: REPOST: Re: Flies in the ointment. reply-type=response > [Randy Poe] > I notice that somebody has made a > comment that it's Newton's method. Think I'll take a > and see what happens. > [r.e.s.] >> Please see also my comment that it is a simple fixed-point iteration >> obtainable without Newton's method. > Don't you think that's a stretch, though? Not a stretch, really, and I do think it's worth noting that this algorithm has a simple derivation that does not require differentiation. (It's not that the differentiation is difficult.) > I do, for two reasons: > 1. General. A zero r of a function f(x) is always a fixed point of a > Newton-method iteration (well, assuming f'(r) is defined). Deriving > the same formula from a fixed-point perspective may be an exercise > in cleverness, but if you can get the same thing directly from > applying Newton's method, the latter is preferable because entirely > straightforward. Of course Newton's method *is* a fixed-point iteration, but the point is that it's as straightforward to derive the algorithm -- as posted at the wikipedia site -- in three lines of algebra as it is to manipulate the equation from Newton's method. Both require about the same not-so-clever manipulations. > 2. Specific. You can find the n'th-root Newton method all over the > web, in its weighted-average and raw forms. Heck, it's frequently > given as a programming assignment in intro numerical analysis > courses. In these contexts, it's always presented as an application > of Newton-Raphson (proof: I looked at a lot of course handouts > Google could find ). True, but it's nice also to bring in the connection to fixed-point iterations (and also a fixed-point theorem relating to convergence). === Subject: Re: REPOST: Re: Flies in the ointment. > Wikipedia is open-source, but it's supposed to be > self-correcting. I notice that somebody has made a > comment that it's Newton's method. Think I'll take a > and see what happens. possible. So much for self-correction. === Subject: REPOST: Re: Flies in the ointment. > The recent sci.math mudfest with the character Jason contained a > number of references to some [perhaps different person] Gabriel, > in which it was suggest the this Gabriel person had exhibited a > similar lack of propriety on some newsgroup, presumably (at least > presumed by me), this occurred on sci.math. > I have been unable to find any reference to (John?) Gabriel, and don't > actually recall him. As a result, I'm somewhat curious about seeing > pointers to his, er, contributions. I can't find it (in Google) either, yet I do remember something about average tangents. I'm beginning to suspect that all original John Gabriel posts have been deleted. Check out this exchange from the numerical analysis group, where John Gabriel appears only in quoted text, but a character named Jason Wells tells him he is a genius who has revolutionized calculus: http://tinyurl.com/3rryy - Randy === Subject: Re: Flies in the ointment. reply-type=response > I also stumbled into this amazing scam on Wikipedia: > John Gabriel's Nth root algorithm > http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm > Nothing wrong with the algorithm, but it's just a clumsily-stated direct > application of Newton's method to finding a zero of f(y) = y^n-x (iterate > y <- y - f(y)/f'(y)). This certainly doesn't go under the name of John > Gabriel in any numerical analysis circles I've run in . Surprisingly, it's cited at http://www.cs.princeton.edu/introcs/96optimization/ which seems not to recognize it as an application of Newton's Method. It is somewhat interesting that the recurrence relation has been written in the form of an *average* (shades of an average tangent?). This post is even more interesting ... http://mathforge.net/index.jsp?page=seeReplies&messageNum=635 There are infinitely many numbers between 0.999.. and 1 [...] My name is JOhn Gabriel and I am on a crusade [...] Why not call 0.999... what it really is - an irrational like 1/3, pi, e or sqrt(2). === Subject: Re: Flies in the ointment. [Tim Peters] ... >> I also stumbled into this amazing scam on Wikipedia: >> John Gabriel's Nth root algorithm >> http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm >> Nothing wrong with the algorithm, but it's just a clumsily-stated >> direct application of Newton's method to finding a zero of f(y) = y^n-x >> (iterate y <- y - f(y)/f'(y)). This certainly doesn't go under the >> name of John Gabriel in any numerical analysis circles I've run >> in . [r.e.s.] > Surprisingly, it's cited at > http://www.cs.princeton.edu/introcs/96optimization/ Brrrrrr. > which seems not to recognize it as an application of Newton's Method. > It is somewhat interesting that the recurrence relation has been > written in the form of an *average* (shades of an average tangent?). Well, it's a weighted averge, and it's not unusual to write it like that; e.g., http://www.gnu.org/software/gmp/manual/html_node/Nth-Root-Algorithm.html It takes a bit of algebraic manipulation to get it into that form, so I'm not surprised if a teacher who understands Newton-Raphson but hasn't actually applied it to n-th roots in anger didn't recognize the weighted-average form. Still, to give a reference to a web page that can't do better than characterize its convergence as much faster is pretty lame even for a professor . > This post is even more interesting ... > http://mathforge.net/index.jsp?page=seeReplies&messageNum=635 > There are infinitely many numbers between 0.999.. and 1 > [...] My name is JOhn Gabriel and I am on a crusade [...] > Why not call 0.999... what it really is - an irrational > like 1/3, pi, e or sqrt(2). Excellent! That link just took me to the top of a large page, so I started skimming down. When I got to: There are infinitely many numbers between 0.999.. and 1 By definition, 0.999.. is less than 1. ... 1000 100 10 Units . 1/10 1/100 1/1000 1 . 0 0 0 0 . 9 9 9 ... Look at the above carefully! Now most mathematicians are unfortunately fools and will pull out all stops to cover their folly. my first thought was ah, so Jason Wells posted here too. Giving 1/3 as an example of an irrational just nailed it. LOL -- maybe they're just identical twins. I _would_ like to believe this kind of insanity is confined to rare unfortunate families . === Subject: Re: Flies in the ointment. reply-type=response > [Tim Peters] > ... > I also stumbled into this amazing scam on Wikipedia: > John Gabriel's Nth root algorithm > http://en.wikipedia.org/wiki/John_Gabriel%27s_Nth_root_algorithm > Nothing wrong with the algorithm, but it's just a clumsily-stated > direct application of Newton's method to finding a zero of f(y) = y^n-x > (iterate y <- y - f(y)/f'(y)). This certainly doesn't go under the > name of John Gabriel in any numerical analysis circles I've run > in . > [r.e.s.] >> Surprisingly, it's cited at >> http://www.cs.princeton.edu/introcs/96optimization/ > Brrrrrr. >> which seems not to recognize it as an application of Newton's Method. >> It is somewhat interesting that the recurrence relation has been >> written in the form of an *average* (shades of an average tangent?). > Well, it's a weighted averge, and it's not unusual to write it like that; > e.g., > http://www.gnu.org/software/gmp/manual/html_node/Nth-Root-Algorithm.html > It takes a bit of algebraic manipulation to get it into that form, so I'm > not surprised if a teacher who understands Newton-Raphson but hasn't > actually applied it to n-th roots in anger didn't recognize the > weighted-average form. Still, to give a reference to a web page that > can't do better than characterize its convergence as much faster is > pretty lame even for a professor . Possibly, at the link I cited above, the algorithm is to be seen as a fixed point iteration, rather than an application of Newton's method -- y = x^n can be manipulated into the fixed-point equation y = (x/y^(n-1) + (n-1)y) / n (with appropriate assumptions). === Subject: Re: Flies in the ointment. reply-type=response > Possibly, at the link I cited above, the algorithm is to be seen > as a fixed point iteration, rather than an application of Newton's > method -- y = x^n can be manipulated into the fixed-point equation I meant y = x^(1/n) of course. > y = (x/y^(n-1) + (n-1)y) / n (with appropriate assumptions). === Subject: Re: Flies in the ointment. > The recent sci.math mudfest with the character Jason contained a > number of references to some [perhaps different person] Gabriel, > in which it was suggest the this Gabriel person had exhibited a > similar lack of propriety on some newsgroup, presumably (at least > presumed by me), this occurred on sci.math. > I have been unable to find any reference to (John?) Gabriel, and > don't > actually recall him. As a result, I'm somewhat curious about seeing > pointers to his, er, contributions. > I can't find it (in Google) either, yet I do remember > something about average tangents. Back in an older thread, Larry Hammick posted the following link to some original John Gabriel material: http://www.cut-the-knot.org/htdocs/dcforum/DCForumID6/403.shtml However, it seems to have been cleaned up since the time of Larry's posting, so that the infantile tantrum to which Larry alluded is no longer present there. I can say it certainly *was* there a month ago, and it did look uncannily similar to Jason Wells' writing style. Of course this may prove nothing more than that crank math of a certain kind attracts similar personalities. === Subject: Re: Flies in the ointment. Russell a .8ecrit : >The recent sci.math mudfest with the character Jason contained a >number of references to some [perhaps different person] Gabriel, >in which it was suggest the this Gabriel person had exhibited a >similar lack of propriety on some newsgroup, presumably (at least >presumed by me), this occurred on sci.math. >I have been unable to find any reference to (John?) Gabriel, and >>don't >actually recall him. As a result, I'm somewhat curious about seeing >pointers to his, er, contributions. >>I can't find it (in Google) either, yet I do remember >>something about average tangents. > Back in an older thread, Larry Hammick posted the following > link to some original John Gabriel material: > http://www.cut-the-knot.org/htdocs/dcforum/DCForumID6/403.shtml > However, it seems to have been cleaned up since the time of > Larry's posting, so that the infantile tantrum to which Larry > alluded is no longer present there. But what is left is enough for any reader (except perhaps Jason) to make up his/her mind. It sems, besides, that the guy behind this (Gabriel?) was also vandalizing the site... I can say it certainly > *was* there a month ago, and it did look uncannily similar to > Jason Wells' writing style. Of course this may prove nothing > more than that crank math of a certain kind attracts similar > personalities. === Subject: Re: Flies in the ointment. > The recent sci.math mudfest with the character Jason contained a > number of references to some [perhaps different person] Gabriel, > in which it was suggest the this Gabriel person had exhibited a > similar lack of propriety on some newsgroup, presumably (at least > presumed by me), this occurred on sci.math. I have been unable to find any reference to (John?) Gabriel, and > don't > actually recall him. As a result, I'm somewhat curious about seeing > pointers to his, er, contributions. > I can't find it (in Google) either, yet I do remember > something about average tangents. > Back in an older thread, Larry Hammick posted the following > link to some original John Gabriel material: > http://www.cut-the-knot.org/htdocs/dcforum/DCForumID6/403.shtml > However, it seems to have been cleaned up since the time of > Larry's posting, so that the infantile tantrum to which Larry > alluded is no longer present there. I can say it certainly > *was* there a month ago, and it did look uncannily similar to > Jason Wells' writing style. Of course this may prove nothing > more than that crank math of a certain kind attracts similar > personalities. So, probably he'll be back with another sock puppet. If so, I'll respond impassively to the mathematical arguments and not make any accusations of puppetry. - Randy === Subject: Re: lyapunov function for a computer networking problem > Unfortunately, (mu/2, mu/2) is on the line x1 + x2 = mu, and you haven't > correctly specified what happens on that line. Until you do, nothing further > can be said about it. > > I agree with you. So, please, what's the continuous-time version of: > x_1(k+delta) = x_1(k) + delta * I(x_1(k) + x_2(k) <= mu) - beta * > delta * x_1(k) * I(x_1(k) + x_2(k) > mu) > x_2(k+delta) = x_2(k) + delta * I(x_1(k) + x_2(k) <= mu) - beta * > delta * x_2(k) * I(x_1(k) + x_2(k) > mu) > considering a very small delta? > Here, 0 < beta < 1, mu > 0, delta > 0 and k > 0. > I(x < mu) is and indicator function, which is equal to 1 if x < mu, > and 0 otherwise. There doesn't necessarily have to be a continuous-time version. In this case, let's see what happens when your system comes close to the line x_1 + x_2 = mu. It's simpler to change variables: take y_1 = x_1 + x_2 - mu y_2 = x_1 - x_2 Thus your system becomes y_1(k + delta) = y_1(k) + 2 * delta when y_1(k) <= 0 = y_1(k) - beta * delta *(y_1(k) + mu) when y_1(k) > 0 y_2(k + delta) = y_2(k) when y_1(k) <= 0 = (1 - beta * delta) * y_2(k) when y_1(k) > 0 So y_1 will increase at a constant rate until it crosses the line y_1 = 0, then oscillate back and forth across that line. Since over the long run it won't change much after that, and the steps forward are of size 2*delta while the steps backward are of size approximately beta*mu*delta, on the average the fraction of time you spend (after crossing y_1 = 0) with y_1 > 0 will be 2/(2 + beta*mu), and the fraction of time with y_1 < 0 will be beta*mu/(2+beta*mu). Thus I would say the appropriate continuous-time version would have d/dt y_1 = 2 for y_1 < 0 = 0 for y_1 = 0 = -beta*(y_1 + mu) for y_1 > 0 d/dt y_2 = 0 for y_1 < 0 = -2*beta/(2 + beta*mu) * y_2 for y_1 = 0 = -beta*y_2 for y_1 > 0 (these being only one-sided derivatives at the time you hit y_1 = 0). And for this system it's easy to see that y_1 = y_2 = 0 (i.e. x_1 = x_2 = mu/2) is the unique fixed point, and is asymptotically stable. Robert Israel israel@math.ubc.ca Department of Mathematics http://www.math.ubc.ca/~israel University of British Columbia Vancouver, BC, Canada === Subject: Re: lyapunov function for a computer networking problem > Thus I would say the appropriate continuous-time version would have > d/dt y_1 = 2 for y_1 < 0 > = 0 for y_1 = 0 > = -beta*(y_1 + mu) for y_1 > 0 > d/dt y_2 = 0 for y_1 < 0 > = -2*beta/(2 + beta*mu) * y_2 for y_1 = 0 > = -beta*y_2 for y_1 > 0 > (these being only one-sided derivatives at the time you hit y_1 = 0). d/dt y_2 = -2*beta/(2 + beta*mu) * y_2 for y_1 = 0 ? I wasn't able to figure out what was the motivation of this equation. I understand that this equation needs to have the form -k*y2. You suggest - (approx. average fraction of time y1 > 0)*beta*y2 . Why? Maybe because we are trying to make the convergence time of the continuous-time system equal to the convergence time of the discrete-time system. But how is it accomplished? Indeed, I made some simulations, and the convergence time of both systems is approx. the same. But again, I wasn't able to figure out why. Also, one philosophical fuzzy question: why the discrete time system is so simple, and the continuous time system is a bit intricate? Would it be possible to find a continuous-time system which also needs just two conditions, and not three, in order to characterize the desired behaviour? Continuous random variables, for instance, have the property that P{X=x}=0. Would it be possible to use something like that in order to simplify the continuous-time equations above? Daniel Sadoc === Subject: Re: lyapunov function for a computer networking problem >> Thus I would say the appropriate continuous-time version would have >> d/dt y_1 = 2 for y_1 < 0 >> = 0 for y_1 = 0 >> = -beta*(y_1 + mu) for y_1 > 0 >> d/dt y_2 = 0 for y_1 < 0 >> = -2*beta/(2 + beta*mu) * y_2 for y_1 = 0 >> = -beta*y_2 for y_1 > 0 >> (these being only one-sided derivatives at the time you hit y_1 = 0). >d/dt y_2 = -2*beta/(2 + beta*mu) * y_2 for y_1 = 0 >? >I wasn't able to figure out what was the motivation of this equation. >I understand that this equation needs to have the form -k*y2. You >suggest >- (approx. average fraction of time y1 > 0)*beta*y2 . Why? Think of it this way. In the discrete system, look at what happens in N steps after the first time it crosses y1 = 0. Of these steps, say k are forward (with y1 increasing by 2*delta) and the other N-k backward (with y1 decreasing by approximately beta*mu*delta). Since the system must stay within one step of y1=0, 2*delta*k - beta*mu*delta*(N-k) is nearly 0, so k is approximately beta*mu/(2+beta*mu) * N, and N-k is approximately 2/(2+beta*mu)*N. Now in the k forward steps y2 doesn't change, but in each of the N-k backward steps it changes by -beta*delta*y2, for an average of 2/(2+beta*mu)*beta*delta*y2 per step. So in the continuous-time version, you should see d/dt y2 = lim_{delta -> 0} (2/(2+beta*mu)*beta*delta*y2)/delta = 2*beta/(2+beta*mu)*y2 Robert Israel israel@math.ubc.ca Department of Mathematics http://www.math.ubc.ca/~israel University of British Columbia Vancouver, BC, Canada === Subject: advice for proving things about the tensor product of vectors? I've been through just about every algebra book in the university library and they're all the same: they have a paragraph, *MAYBE* a page, about the tensor product of vectors, while having whole chapters about the tensor product of vector _spaces_, linear transformations etc. I'm frantic because I have a homework assignment to prove a ton of little properties about tensor product of vectors; the problems look simple but there's just nothing to say. You open your mouth to start saying a proof, and it hits you-- you can't say a thing, because everything you know is about the tensor product of _spaces_ or transformations. The canonical concrete construction of the tensor product of vectors is quite worthless (I'm talking about the quotient version here, where you include an n-tuple into the free module and add (take quotient map) a rather complicated mess). One book put forth a bunch of little properties about the things, and the proof went like: this is immediate. Er, no, it's not immediate at all! And to make matters worse, the problems are general in the sense that I'm asked to prove things about tensor product of many (arbitrary, not necessarily finite) vectors. What little any texts have to say about the matter at all, is almost entirely restricted to the case of 2 vectors! So if anyone can help - even if just giving references to books that actually offer insight - it would be greatly valued. === Subject: Re: advice for proving things about the tensor product of vectors? Post a problem,maybe somebody will do it and you will get the idea.Tensor Products are characterized by a universal property and you need to use it in proofs. === Subject: Re: advice for proving things about the tensor product of vectors? > Post a problem,maybe somebody will do it and you will get the > idea.Tensor Products are characterized by a universal property and you > need to use it in proofs. Here is a problem then. I've struggled quite a lot with this. I use (x) to denote tensor product. Given zin V (x) W, and given that z has two representations of the form z=sum_{i=1}^r (v_i) (x) (w_i), z=sum_{i=1}^s (v'_i) (x) (w'_i), where {v_i}, {w_i}, {v'_i} and {w'_i} are linearly indep. (just with themselves, not necessarily with eachother, ie perhaps some v'_i is a combination of the v_i)... then prove r=s. All I can think of doing is induction. If a term in the 2nd sum is a lin. comb. of the terms in the 1st, then (inducting on, say, r+s) we can say it is strictly a multiple of one particular term from the 1st, and then playing around with it we can conclude it in fact equals a term from the 1st, so we can subtract this term from both sides and finish by induction. This is all assuming we can prove the claim for the special case when one of r or s is 1- which I haven't actually managed to do, that being itself rather hard. Much harder is the case if nothing in the 2nd sum is a lin. comb. of the terms in the first. If this is the case, we can move terms from one side to the other without breaking the hypothesis. And likewise we can add a copy of any term to both sides. By doing the former, we can reduce the difference between r and s by 2, assuming it's >2 to begin with, and by doing the latter, we can reduce it by 1, assuming it's >1 to begin with, so we can basically reduce everything to the case when the difference between r and s is 1. Then we're at a dead-end because there's just nothing we can say. Anyway, it seems there should be an easier solution anyway- my method is leading toward a 2-page proof! === Subject: Re: advice for proving things about the tensor product of vectors? > Post a problem,maybe somebody will do it and you will get the > idea.Tensor Products are characterized by a universal property and > you > need to use it in proofs. > Here is a problem then. I've struggled quite a lot with this. I use > (x) to denote tensor product. > Given zin V (x) W, and given that z has two representations of the > form > z=sum_{i=1}^r (v_i) (x) (w_i), > z=sum_{i=1}^s (v'_i) (x) (w'_i), > where {v_i}, {w_i}, {v'_i} and {w'_i} are linearly indep. (just with > themselves, not necessarily with eachother, ie perhaps some v'_i is a > combination of the v_i)... then prove r=s. > All I can think of doing is induction. If a term in the 2nd sum is a > lin. comb. of the terms in the 1st, then (inducting on, say, r+s) we > can say it is strictly a multiple of one particular term from the 1st, > and then playing around with it we can conclude it in fact equals a > term from the 1st, so we can subtract this term from both sides and > finish by induction. This is all assuming we can prove the claim for > the special case when one of r or s is 1- which I haven't actually > managed to do, that being itself rather hard. Much harder is the case > if nothing in the 2nd sum is a lin. comb. of the terms in the first. > If this is the case, we can move terms from one side to the other > without breaking the hypothesis. And likewise we can add a copy of any > term to both sides. By doing the former, we can reduce the difference > between r and s by 2, assuming it's >2 to begin with, and by doing the > latter, we can reduce it by 1, assuming it's >1 to begin with, so we > can basically reduce everything to the case when the difference between > r and s is 1. Then we're at a dead-end because there's just nothing we > can say. > Anyway, it seems there should be an easier solution anyway- my method > is leading toward a 2-page proof! You have to use the characterizing property of tensor products,namely the lifting of bilinear maps to linear maps.Still,it takes some experience to see how to use it in this problem. To do the problem one proves that every v_i is a linear combination of the v'_i 's and the same argument (or symmetry )shows that every v'_i is a linear combination of the v_i's.This means the spans of the v_i's and v'i's are the same and the dimension of this span is r=s since both sequences are basis for the span. For this ,fix a positive integer k, at most r,and construct a linear functional f on W with f(w_k)=1 and f(w_i)=0 for all i not = k.(Just extend the w_i's to a basis for W and let f(w)= the kth coordinate of the expansion of w as a finite linear combination of the extended w_i's. Now let G(v,w)= f(w)v ,G is a bilinear function from VxW into V ,and thus by the so called universal property of tensor products ,there is a linear function g from V(x)W into V with g(v(x)w)= f(w)v for all v,w. g(sum(v_i(x)w_i))= g( sum(v'_i(x)w'_i)) implies that sum (f(w_i)v_i)= sum f(w'_i)v'_i) which gives by simplifying the left curious -What text are you using for tensor products ? === Subject: Rationalize Expression http://mygate.mailgate.org/mynews/sci/sci.math/47752daae0951dfb038a7d3d15467 0 a3.61944%40mygate.mailgate.org How would you rationalize [1/2^(1/2)] + [1/3^(1/3)] + 1/5^(1/5)]? -- === Subject: Re: Rationalize Expression > How would you rationalize [1/2^(1/2)] + [1/3^(1/3)] + 1/5^(1/5)]? I'm not sure what rationalize means in this context. If it means to combine into a single term with no fractional powers in the denominator, then look for a common denominator which has no such powers, i.e. put each term over the common denominator 2*3*5. For instance, multiply numerator and denominator of the second term by 2*3^(2/3)*5. Something similar can be done for the other two terms. - Randy === Subject: Re: Rationalize Expression http://mygate.mailgate.org/mynews/sci/sci.math/023140da1f3347a0036134f1527cd e 82.61944%40mygate.mailgate.org > How would you rationalize [1/2^(1/2)] + [1/3^(1/3)] + 1/5^(1/5)]? > I'm not sure what rationalize means in this context. > If it means to combine into a single term with no > fractional powers in the denominator, then look for > a common denominator which has no such powers, i.e. > put each term over the common denominator 2*3*5. > For instance, multiply numerator and denominator of > the second term by 2*3^(2/3)*5. Something similar > can be done for the other two terms. > - Randy Silly me. I meant 1 / [2^(1/2) + 3^(1/3) + 5^(1/5)] That is, find an x such that x * [2^(1/2) + 3^(1/3) + 5^(1/5)] is an integer. -- === Subject: Re: Rationalize Expression <023140da1f3347a0036134f1527cde82.61944@mygate.mailgate.org> Here's the easy way to do it. Let a = 2^(1/2), b = 3^(1/3), c = 5^(1/5) The the answer will be a polynomial in a,b,c P(a,b,c) = sum A_n,m,p a^n b^m c^p with 0<=n<2, 0<=m<3, 0<=p<5 So set (a+b+c)*P(a,b,c) = 1, and it will lead you to a system of linear equations with rational coefficients. Thus each of the A_m,n,p will be rational. Note that Rusin's answer introduced irrational quantities like cos(pi/5), which suggests that either his answer is wrong or more likely that it is simply not in simplest form. === Subject: Re: Rationalize Expression |>I meant 1 / [2^(1/2) + 3^(1/3) + 5^(1/5)] |>That is, find an x such that x * [2^(1/2) + 3^(1/3) + 5^(1/5)] is an |>integer. Maple 9.5 says: > rationalize(1 / (2^(1/2) + 3^(1/3) + 5^(1/5))); -1/867818606*(-3^(1/3)-5^(1/5)+2^(1/2))*(2*3^(2/3)+3*3^(2/3)*5^(2/5)+3*3^(1/ 3) -2*3^(1/3)*5^(3/5)+4*3^(1/3)*5^(1/5)+4-4*5^(2/5)+5^(4/5)-6*5^(1/5)) *(-1676849-2931551*5^(1/5)+3730879*5^(2/5)-995123*5^(3/5)+3557707*5^(4/5)) Robert Israel israel@math.ubc.ca Department of Mathematics http://www.math.ubc.ca/~israel University of British Columbia Vancouver, BC, Canada === Subject: Re: Rationalize Expression <023140da1f3347a0036134f1527cde82.61944@mygate.mailgate.org>, > I meant 1 / [2^(1/2) + 3^(1/3) + 5^(1/5)] > That is, find an x such that x * [2^(1/2) + 3^(1/3) + 5^(1/5)] is an > integer. [meaning, a non-zero integer, and presumably meaning x expressed without fractions, in some sense, so as to rule out wiseguy answers like x = 73 / [2^(1/2) + 3^(1/3) + 5^(1/5)]] The product of the conjugates of 2^(1/2) + 3^(1/3) + 5^(1/5) will be an integer. The conjugates of 2^(1/2) + 3^(1/3) + 5^(1/5) are the numbers a + b + c, where a = plus or minus 2^(1/2), b = w 3^(1/3), c = z 5^(1/5), where w runs through the three roots of unity, and z through the five fifth roots of unity. -- Gerry Myerson (gerry@maths.mq.edi.ai) (i -> u for email) === Subject: Re: Rationalize Expression >> That is, find an x such that x * [2^(1/2) + 3^(1/3) + 5^(1/5)] is an >> integer. >[meaning, a non-zero integer, and presumably meaning x expressed >without fractions, in some sense, so as to rule out wiseguy answers >like x = 73 / [2^(1/2) + 3^(1/3) + 5^(1/5)]] But Gerry, the right answer IS x = 867818606 / [2^(1/2) + 3^(1/3) + 5^(1/5)]], for exactly the reasons you gave. You could, of course, express it as an integer polynomial in a=2^(1/2), b=3^(1/3), c=5^(1/5), d=cos(pi/5), and e=cos(2pi/5), but you would not want to do so because then it would be -21665049+34735946*a-36130691*b+86604619*c+30341150*e-30341150*d-27594638*a* c* e+12260718*b*c*e+61422896*b^2*c*e-12201798*c^4*b*e-3774890*c^4*b^2*e-2041555 2* b*c^2*e+81991118*a*c^2*e+36571890*b^2*c^2*e+43466136*a*c^3*e+7217050*c^3*b*e + 2142042*c^3*b^2*e-6159832*c^4*a*e+25669360*c^4*a*b*e+5029878*c^4*b^2*a*e+ 278949*c^4*a*b-15793112*c^4*b^2*a-15333920*a*b*d-152670*a*b^2*d+27594638*a*c *d -12260718*b*c*d-61422896*b^2*c*d-81991118*a*c^2*d+20415552*b*c^2*d-36571890* b^ 2*c^2*d-43466136*a*c^3*d-7217050*c^3*b*d-2142042*c^3*b^2*d+12201798*c^4*b*d+ 6159832*c^4*a*d+3774890*c^4*b^2*d+15333920*a*b*e+152670*a*b^2*e-12683047*a*c ^2 *b^2-6111030*a*c^3*b-162336*a*c^3*b^2+40367536*a*c-40446855*a*c*b^2+10769044 *a *c^2*b+61575566*a*b*c*d-25236964*a*b*c-21147843*a*b+18356878*a*b^2-19219693* b* c+6880086*b^2*c+6750956*a*c^2+18486008*b*c^2+29677811*b^2*c^2+18794077*c^3*b ^2 -116613*c^4*b^2-104582022*c*d+18584095*a*c^3-29353139*c^3*b+12792147*c^4*b- 6681117*c^4*a+146915910*a*d-18569110*b*d+40483310*b^2*d+18569110*b*e-8910565 4* c^2*d+16307708*c^3*d+58555770*c^4*d-40483310*b^2*e+104582022*c*e+89105654*c^ 2* e-16307708*c^3*e-58555770*c^4*e-146915910*a*e+100113403*b^2-2318395*c^2- 6263948*c^3+28795241*c^4-14111296*a*c*b^2*d+50683186*a*c^2*b*d+20503672*a*c^ 2* b^2*d-18361630*a*c^3*b*d+21894470*a*c^3*b^2*d-25669360*c^4*a*b*d-5029878*c^4 *b ^2*a*d-61575566*a*b*c*e+14111296*a*c*b^2*e-50683186*a*c^2*b*e-20503672*a*c^2 *b ^2*e+18361630*a*c^3*b*e-21894470*a*c^3*b^2*e and nobody wants to see that! dave === Subject: Re: Rationalize Expression > > find an x such that x * [2^(1/2) + 3^(1/3) + 5^(1/5)] is an integer. >> [meaning, a non-zero integer, and presumably meaning x expressed >> without fractions, in some sense, so as to rule out wiseguy answers >> like x = 73 / [2^(1/2) + 3^(1/3) + 5^(1/5)]] > But Gerry, the right answer IS x = 867818606/[2^(1/2) + 3^(1/3) + 5^(1/5)]], > for exactly the reasons you gave. You could, of course, express it as an > integer polynomial in a=2^(1/2), b=3^(1/3), c=5^(1/5), d=cos(pi/5), and > e=cos(2pi/5), but you would not want to do so because then it would be >-21665049+34735946*a-36130691*b+86604619*c+30341150*e-30341150*d-27594638*a *c* >e+12260718*b*c*e+61422896*b^2*c*e-12201798*c^4*b*e-3774890*c^4*b^2*e-204155 52* >b*c^2*e+81991118*a*c^2*e+36571890*b^2*c^2*e+43466136*a*c^3*e+7217050*c^3*b* e+ >2142042*c^3*b^2*e-6159832*c^4*a*e+25669360*c^4*a*b*e+5029878*c^4*b^2*a*e+ >278949*c^4*a*b-15793112*c^4*b^2*a-15333920*a*b*d-152670*a*b^2*d+27594638*a* c*d >-12260718*b*c*d-61422896*b^2*c*d-81991118*a*c^2*d+20415552*b*c^2*d-36571890 *b^ >2*c^2*d-43466136*a*c^3*d-7217050*c^3*b*d-2142042*c^3*b^2*d+12201798*c^4*b*d + >6159832*c^4*a*d+3774890*c^4*b^2*d+15333920*a*b*e+152670*a*b^2*e-12683047*a* c^2 >*b^2-6111030*a*c^3*b-162336*a*c^3*b^2+40367536*a*c-40446855*a*c*b^2+1076904 4*a >*c^2*b+61575566*a*b*c*d-25236964*a*b*c-21147843*a*b+18356878*a*b^2-19219693 *b* >c+6880086*b^2*c+6750956*a*c^2+18486008*b*c^2+29677811*b^2*c^2+18794077*c^3* b^2 >-116613*c^4*b^2-104582022*c*d+18584095*a*c^3-29353139*c^3*b+12792147*c^4*b- >6681117*c^4*a+146915910*a*d-18569110*b*d+40483310*b^2*d+18569110*b*e-891056 54* >c^2*d+16307708*c^3*d+58555770*c^4*d-40483310*b^2*e+104582022*c*e+89105654*c ^2* >e-16307708*c^3*e-58555770*c^4*e-146915910*a*e+100113403*b^2-2318395*c^2- >6263948*c^3+28795241*c^4-14111296*a*c*b^2*d+50683186*a*c^2*b*d+20503672*a*c ^2* >b^2*d-18361630*a*c^3*b*d+21894470*a*c^3*b^2*d-25669360*c^4*a*b*d-5029878*c^ 4*b >^2*a*d-61575566*a*b*c*e+14111296*a*c*b^2*e-50683186*a*c^2*b*e-20503672*a*c^ 2*b >^2*e+18361630*a*c^3*b*e-21894470*a*c^3*b^2*e > and nobody wants to see that! It's q p(u+v,w) more simply, where u = 2^(1/2), v = 3^(1/3), w = 5^(1/5) 2 2 (1770832 v + 18893046 v + 58073126 - u(18308051 v + 12555731 v + 3601201)) q = -------------------------------------------------------------------------- 867818606 and p(x,y) = (x^5+y^5)/(x+y) [= x^4 - y x^3 + y^2 x^2 - y^3 x + y^4 ] It is tedious but straightforward to derive the above expression, namely: x^5+5 = x^5+w^5 = (x+w)p(x,w) => 1/(x+w) = p(x,w)/(x^5+5). Here x = u+v, x^5+5 = (u+v)^5+5 = (20u+3) v^2 + (15u+20) v + 4u+65 2 2 2 2 1 (b - a c) v + (3 a - b c) v + c - 3 a b Now --------------- = ------------------------------------------- 2 3 3 3 a v + b v + c 9 a + 3 b + c - 9 a b c For a,b,c = 20u+3,15u+20,4u+65 this specializes to (712 u - 495) v^2 + (695 u - 1007) v + 815 u - 2277 ---------------------------------------------------- 10147 u - 32768 Rationalizing the denominator yields the polynomial q(u,v) specified above. Compare with Maple's result posted by Robert Israel: -(u-v-w)*(2vv+3vvww+3v-2vw^3+4vw+4-4ww+w^4-6w) *(-1676849-2931551w+3730879w^2-995123w^3+3557707w^4)/867818606 --Bill Dubuque === Subject: Re: Rationalize Expression > Rationalizing the denominator yields the polynomial q(u,v) Which expressed succinctly is not too painful to look at (as opposed to the 19 line behemoth in D.R.'s prior post) 1/(u+v+w) = (10147 u + 32768) * ((712 u - 495) v^2 + (695 u - 1007) v + 815 u - 2277) * w^4 P((u+v)/w) / 867818606 where u = 2^(1/2), v = 3^(1/3), w = 5^(1/5) P(x) = (x^5+1)/(x+1) = x^4 - x^3 + x^2 + 1 I doubt it can be expressed much simpler than that. --Bill Dubuque === Subject: Re: Rationalize Expression > Compare with Maple's result posted by Robert Israel: > 4 3 2 2 2 > (W + V - U) (W - 2 V W + (3 V - 4) W + (4 V - 6) W + 2 V + 3 V + 4) > 4 3 2 > * (3557707 W - 995123 W + 3730879 W - 2931551 W - 1676849)/867818606 > where U = 2^(1/2), V = 3^(1/3), W = 5^(1/5) This comes from rationalizing in the order: U, V, W (vs. my W, V, U ) namely 1/(T+U) = (T-U)/(T^2-2), here T = V+W hence 1/(T^2-2) = 1/(V^2 + 2W V + W^2-2) 2 2 2 2 1 (b - a c) V + (3 a - b c) V + c - 3 a b Now -------------- = ------------------------------------------- 2 3 3 3 a V + b V + c 9 a + 3 b + c - 9 a b c which for a = 1, b = 2W, c = W^2-2 specializes to 4 3 2 2 2 W - 2 V W + (3 V - 4) W + (4 V - 6) W + 2 V + 3 V + 4 ---------------------------------------------------------- 4 3 2 - 6 W + 6 W + 12 W + 41 W + 1 which times T-U = W+V-U with rationalized denominator is Maple's result. --Bill Dubuque === Subject: Re: Rationalize Expression http://mygate.mailgate.org/mynews/sci/sci.math/b341a29a87aa40960b32ec380d9e9 d 72.61944%40mygate.mailgate.org > I meant 1 / [2^(1/2) + 3^(1/3) + 5^(1/5)] > That is, find an x such that x * [2^(1/2) + 3^(1/3) + 5^(1/5)] is an > integer. As x would be a rather complicated expression, how would you find the value of the denominator? -- === Subject: Re: What are numbers? > A quantity is simply a property of a set. By not refering to the set, but > instead its property of `size' or `total' The size of a set is its cardinality. I know of two approaches (I bet there are more): (i) Take cardinality as an undefined primitive. This is an approach due to Tarski that is taken in Suppes Axiomatic Set Theory (a recommended read, btw). (ii) Take the cardinality of a set to be itself a particular kind of set, viz. an initial ordinal, where an ordinal is a particular kind of set, viz. one ordered in a particular way by the is an element of relation. > I don't have to worry about > members being and not being members of themselves. > So I think of it this way. > Quantity refers to a property of a set (size or totalness). > Number refers to the names given to each distinct quantity (i.e. where > quantities are the same they share the same name, different quantities > have different names). Worry: are there uncountably many quantities? If so, how do you get to name them all if name has its usual meaning? > Numerals are the individual names refering to distinct quantities. > I am not trying to construct the set of numbers here (although I seem to > be getting close to it). By construction, I would do as you suggest, and > start with sets. I'm just trying to provide a decent conception. I can't > see how concieving of the natural numbers in this way leads to a problem If all you want is natural numbers then go for Peano's axioms. They come in two varieties: (i) First order: nice and simple but not categorical. (ii) Second order: categorical, but sets rear their ugly heads! > later. So far, I haven't seen any problems. In that case you should proceed! My worry: how _far_ can you proceed before problems appear? === Subject: Re: What are numbers? > I claim that you _can't_ get integers, rationals, reals, and complex > numbers with *only* logic[*] you need a bit of set theory as well, and > Ok, let me stupidly suggest that I can. Why can't I get integers by > pairing natural numbers? Why can't I get the rationals by paring > integers. Why can't I get reals through Dedekind cuts? > Jackson Ok, let the pair (n, m) be the integer n - m. So -1, for example is all of these (1, 2), (2, 3), (3, 4), ... The usual thing is to lump them all together into a _set_ called an equivalence class. Ditto rationals as pairs of integers. Clearly _sets_ of rational numbers are involved in the definition of Dedekind cuts. So you go beyond logic and use set theory. If you want to expand the definition of logic so that it _includes_ set theory, so be it. But many people think that the theory of the predicate is an element of goes beyond logic. === Subject: Re: What are numbers? > Ok, let the pair (n, m) be the integer n - m. So -1, for example is all > of these > (1, 2), (2, 3), (3, 4), ... > The usual thing is to lump them all together into a _set_ called an > equivalence class. Ditto rationals as pairs of integers. > Clearly _sets_ of rational numbers are involved in the definition of > Dedekind cuts. > So you go beyond logic and use set theory. > If you want to expand the definition of logic so that it _includes_ set > theory, so be it. But many people think that the theory of the > predicate is an element of goes beyond logic. Sure, its convenient to use set theory, but I don't have to use much of it--I'm not sure I need to use any of it. None of these things rests on the axioms. I can simply describe sets as elements catagorized by properties. I don't have to use is an element of because I can simply say has property P. I don't need to use compliments, replacement, choice etc. I don't know how far I can go before I will indeed have to make use of set theory, but as far as I can tell, the interest in basing numbers on set theory is simply to construct them from nothing--but this is where Godel showed that sets have content and thus are something. Jackson === Subject: Re: What are numbers? > Ok, let the pair (n, m) be the integer n - m. So -1, for example is > all > of these > (1, 2), (2, 3), (3, 4), ... > The usual thing is to lump them all together into a _set_ called an > equivalence class. Ditto rationals as pairs of integers. > Clearly _sets_ of rational numbers are involved in the definition of > Dedekind cuts. > So you go beyond logic and use set theory. > If you want to expand the definition of logic so that it _includes_ set > theory, so be it. But many people think that the theory of the > predicate is an element of goes beyond logic. > Sure, its convenient to use set theory, but I don't have to use much of > it--I'm not sure I need to use any of it. None of these things rests on > the axioms. I can simply describe sets as elements catagorized by > properties. I don't have to use is an element of because I can simply > say has property P. Eek! No you can't! Consider the property of not applying to itself. It's a perfectly reasonable property, after all the property of being red is not itself red. Call the property of not applying to itself R and ask yourself: does R apply to R? Frege had this problem. You can Google for Russell's paradox. > I don't need to use compliments, replacement, > choice etc. It depends what you're going to do with them once you've got them. If you're going to define the real numbers for use in analysis then you'll need choice. Choice isn't just there so that set theorists can play with it, it has _real_ uses. > I don't know how far I can go before I will indeed have to > make use of set theory, but as far as I can tell, the interest in basing > numbers on set theory Two things one might do: (i) Define natural numbers as sets of a particular kind, say finite von Neumann ordinals, and define all other numbers in terms of them. (ii) Take natural numbers as undefined (as Peano did), and define all other numbers in terms of them. Clearly approach (i) uses set theory, but it seems clear to me that (ii) does as well because the defining of all other numbers uses set theory (as I think I indicated). Btw, Zermelo-Fraenkel set theory with the axiom of infinity replaced by its negation is equivalent to the theory of natural numbers. If you want a theory of numbers without set theory consider these two possibilities: (i) Use lambda calculus to define the natural numbers. (ii) Start with the reals as is done in beginning analysis texts. This won't eliminate set theory, because categorical axioms for the real numbers quantify over sets of real numbers, but the intrusion will be minimal. > is simply to construct them from nothing--but this > is where Godel showed that sets have content and thus are something. > Jackson === Subject: Re: What are numbers? <140320051515000566%anniel@nym.alias.net.invalid> 03/14/2005 at 02:17 PM, quantanglement@gmail.com said: >How is that? Why is the integer 17 different from the rational 17? >etc. That depends on what you mean by number. For instance, if you start with the axioms for R and define C in terms of ordered pairs, then clearly 17 and (17,0) are different. Similarly, if you start with the integers and define rational numbers as equivalence classes of ordered pairs then 17 and {(17,1)} are different. If you start with axioms for C then all of those are the same. -- Shmuel (Seymour J.) Metz, SysProg and JOAT Unsolicited bulk E-mail subject to legal action. I reserve the right to publicly post or ridicule any abusive E-mail. Reply to domain Patriot dot net user shmuel+news to contact me. Do not === Subject: Re: What are numbers? > Aren't numbers just names for quantities? >> What is wrong with saying that numbers simply refer to their > specific quantities? > If you want to develop a theory of numbers from scratch, I think >> you will find it more productive to start with a theory of sets, and >> then define the natural numbers in terms of the far simpler notions >> of first and next (like Peano's Axioms). Or start with a set >> theory, like ZFC, in which these notions are already, in a sense, >> built in. My own preference is the former. >> Dan >> Download DC Proof 1.0 at http://www.dcproof.com > A quantity is simply a property of a set. By not refering to the set, > but instead its property of `size' or `total' I don't have to worry > about members being and not being members of themselves. > So I think of it this way. > Quantity refers to a property of a set (size or totalness). > Number refers to the names given to each distinct quantity (i.e. > where quantities are the same they share the same name, different > quantities have different names). > Numerals are the individual names refering to distinct quantities. > I am not trying to construct the set of numbers here (although I seem > to be getting close to it). By construction, I would do as you > suggest, and start with sets. I'm just trying to provide a decent > conception. I can't see how concieving of the natural numbers in this > way leads to a problem later. So far, I haven't seen any problems. >> I think you will encounter some problems when you try to do proofs by >> induction. >> Dan >> Download DC Proof 1.0 at http://www.dcproof.com > How So? Suppose we have, for some predicate P: P(1) For all k in N, P(k) => P(k+1) Prove: For all k in N, P(k) Can you do this in your system? As an amateur mathematician, I have struggled with such problems for many years -- my DC Proof program is the result. Dan === Subject: Re: What are numbers? > Suppose we have, for some predicate P: > P(1) > For all k in N, P(k) => P(k+1) > Prove: For all k in N, P(k) > Can you do this in your system? Why not? P(1) is some property. For every numeral in the set of numbers, if Property 1 applies to the quantity which the numeral k refers to then it applies to the next largest quantity which is named k+1. > As an amateur mathematician, I have struggled with such problems for > many years -- my DC Proof program is the result. > Dan === Subject: Re: What are numbers? >> Suppose we have, for some predicate P: >> P(1) >> For all k in N, P(k) => P(k+1) >> Prove: For all k in N, P(k) >> Can you do this in your system? > Why not? > P(1) is some property. > For every numeral in the set of numbers, > if Property 1 applies to the quantity which the numeral k refers to then > it applies to the next largest quantity which is named k+1. Is this an axiom in your system? Or is it a proof? You really need to formalize all the axioms and rules of inference for your proposed system. You might want to have a look at my DC Proof program to get some ideas. It is a line-by-line proof checker with what I think is very nice user interface. Dan Download DC Proof 1.0 at http://dcproof.com === Subject: Radioactive decay I am not sure how to set up this equation in order to solve this problem. Can someone help me or guide me in the direction that will Question: If the half-life of a radioactive substance is 20 days, how long will it take for 99 percent of the substance to decay? === Subject: Re: Radioactive decay > I am not sure how to set up this equation in order to solve this > problem. Can someone help me or guide me in the direction that will > Question: If the half-life of a radioactive substance is 20 days, how > long will it take for 99 percent of the substance to decay? A(t) = A0.e^-rt A0/2 = A0.e^-(r.20 day) 0.01 A0 = A0.e^-rt 1/2 = e^-(20r day) 2 = e^(20r day) 20 r day = log 2 r = (ln 2)/20 per day 0.01 = e^-rt 100 = e^rt ln 100 = rt t = (ln 100) / ((ln 2)/20 per day) = 20(ln 100)/(ln 2) days = 20(log_2 100) days === Subject: Re: Radioactive decay If I'm not mistaken, here is the gist of the solution: Find the const (k) of decay...Take logs of both side: k=k/.Solve[1/2==E^(-20*k),k] Log[2]/20 or... N[k] 0.03465735902799726 Plug back k into the equation and solve for t (time) t=t/.Solve[1/100==E^((-t)*k),t] {(20*Log[100])/Log[2]} N[t] {132.87712379549453} I think the answer is about 132 days. -- Dana >I am not sure how to set up this equation in order to solve this > problem. Can someone help me or guide me in the direction that will > Question: If the half-life of a radioactive substance is 20 days, how > long will it take for 99 percent of the substance to decay? === Subject: Re: Radioactive decay >I am not sure how to set up this equation in order to solve this >problem. Can someone help me or guide me in the direction that will >Question: If the half-life of a radioactive substance is 20 days, how >long will it take for 99 percent of the substance to decay? Solve (1/2)^x = 0.01, or 2^x = 100. Then t (in days) = 20x. Thomas === Subject: integer sums of unit fractions 3QLpj-NoP*NzsIC,boYU]bQ]H'y<#4ga3$21: I'm interested in ways of partitioning an integer n>1 into a sum of a finite sequence of unit fractions, in such a way that no nontrivial subsequence has an integer sum. For example, 2 = 1/2 + 1/3 + 1/3 + 1/4 + 1/7 + 1/7 + 1/7 + 1/7 + 1/84 but no subsequence of these fractions adds to one. Is it possible to find examples with larger values of n? Or with no two fractions equal to each other? -- David Eppstein Computer Science Dept., Univ. of California, Irvine http://www.ics.uci.edu/~eppstein/ === Subject: Re: integer sums of unit fractions > Or with no two fractions equal to each other? David: The sum = 2 for these fractions: 1/2 1/3 1/4 1/5 1/7 1/9 1/10 1/11 1/13 1/14 1/24 1/26 1/55 1/88 1/99 1/273 1/2 1/3 1/4 1/5 1/7 1/9 1/10 1/11 1/14 1/16 1/21 1/24 1/55 1/88 1/99 1/112 1/2 1/3 1/4 1/5 1/7 1/9 1/10 1/11 1/13 1/14 1/24 1/33 1/44 1/55 1/99 1/2184 1/2 1/3 1/4 1/5 1/7 1/9 1/10 1/11 1/13 1/14 1/26 1/33 1/44 1/55 1/99 1/273 1/2 1/3 1/4 1/5 1/7 1/9 1/10 1/11 1/14 1/16 1/21 1/33 1/44 1/55 1/99 1/112 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/19 1/33 1/44 1/55 1/78 1/99 1/41496 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/19 1/33 1/44 1/55 1/84 1/99 1/1064 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/21 1/33 1/44 1/55 1/57 1/99 1/3192 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/21 1/33 1/44 1/55 1/58 1/99 1/1624 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/21 1/33 1/44 1/55 1/63 1/99 1/504 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/21 1/33 1/44 1/55 1/64 1/99 1/448 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/21 1/33 1/44 1/55 1/70 1/99 1/280 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/21 1/33 1/44 1/55 1/84 1/99 1/168 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/23 1/33 1/44 1/46 1/55 1/99 1/3864 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/26 1/33 1/39 1/44 1/55 1/99 1/728 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/28 1/33 1/34 1/44 1/55 1/99 1/2856 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/28 1/33 1/35 1/44 1/55 1/99 1/840 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/28 1/33 1/44 1/48 1/55 1/99 1/112 1/2 1/3 1/4 1/5 1/7 1/8 1/9 1/10 1/11 1/28 1/33 1/44 1/55 1/56 1/84 1/99 The sum of 3 appears to be much harder. I found that a minimum of 12 terms was necessary for 2 in my search range. Randall === Subject: Re: integer sums of unit fractions > I'm interested in ways of partitioning an integer n>1 into a sum of a > finite sequence of unit fractions, in such a way that no nontrivial > subsequence has an integer sum. > For example, 2 = 1/2 + 1/3 + 1/3 + 1/4 + 1/7 + 1/7 + 1/7 + 1/7 + 1/84 > but no subsequence of these fractions adds to one. > Is it possible to find examples with larger values of n? > Or with no two fractions equal to each other? What happens when you try the greedy algorithm? e.g., 3 = 1/2 + 1/3 + 1/3 + 1/4 + 1/5 + 1/5 + 1/5 + 1/5 + a few 1/7 + whatever it takes to get to 3? Similarly for the question with no repeated fractions. -- Gerry Myerson (gerry@maths.mq.edi.ai) (i -> u for email) === Subject: Re: integer sums of unit fractions >> I'm interested in ways of partitioning an integer n>1 into a sum of a >> finite sequence of unit fractions, in such a way that no nontrivial >> subsequence has an integer sum. >> For example, 2 = 1/2 + 1/3 + 1/3 + 1/4 + 1/7 + 1/7 + 1/7 + 1/7 + 1/84 >> but no subsequence of these fractions adds to one. >> Is it possible to find examples with larger values of n? >> Or with no two fractions equal to each other? >What happens when you try the greedy algorithm? e.g., >3 = 1/2 + 1/3 + 1/3 + 1/4 + 1/5 + 1/5 + 1/5 + 1/5 + a few 1/7 >+ whatever it takes to get to 3? 3=1/2+1/3+1/3+1/4+1/5+1/5+1/5+1/5+1/7+1/7+1/7+1/7+1/7+1/16+1/153+1/85680 4=1/2+1/3+1/3+1/4+1/5+1/5+1/5+1/5+1/7+1/7+1/7+1/7+1/7+1/7+1/8+1/9+1/9 +1/11+1/11+1/11+1/11+1/11+1/11+1/31+1/797+1/1065130+1/1326334812264 >Similarly for the question with no repeated fractions. 2=1/2+1/3+1/4+1/5+1/7+1/8+1/9+1/10+1/11+1/12+1/16+1/1047+1/1138151 +1/3145940416080 It gets hard for larger integers (at least the way I tried to implement it), as you have a lot of subset sums to look at. Robert Israel israel@math.ubc.ca Department of Mathematics http://www.math.ubc.ca/~israel University of British Columbia Vancouver, BC, Canada === Subject: Re: integer sums of unit fractions 3QLpj-NoP*NzsIC,boYU]bQ]H'y<#4ga3$21: unit fractions sums to at most n, then one can partition the sequence into n+1 subsequences each of which sums to at most one. [Bar-Noy, Ladner, and Tamir, Windows scheduling as restricted version of bin packing, SODA'04 pp. 217-226.] These examples show that this can't always be improved to a partition into n subsequences. Apparently the computational complexity of distinguishing sequences that require n+1 subsequences from those that can be partitioned into n sequences is open. -- David Eppstein Computer Science Dept., Univ. of California, Irvine http://www.ics.uci.edu/~eppstein/ === Subject: Re: integer sums of unit fractions 3QLpj-NoP*NzsIC,boYU]bQ]H'y<#4ga3$21: > I'm interested in ways of partitioning an integer n>1 into a sum of a > finite sequence of unit fractions, in such a way that no nontrivial > subsequence has an integer sum. > > For example, 2 = 1/2 + 1/3 + 1/3 + 1/4 + 1/7 + 1/7 + 1/7 + 1/7 + 1/84 > but no subsequence of these fractions adds to one. > > Is it possible to find examples with larger values of n? > Or with no two fractions equal to each other? > What happens when you try the greedy algorithm? e.g., > 3 = 1/2 + 1/3 + 1/3 + 1/4 + 1/5 + 1/5 + 1/5 + 1/5 + a few 1/7 > + whatever it takes to get to 3? Greedy meaning that it takes the largest fraction for which the total is at most n and that does not create a subsequence with integer sum? Even much simpler greedy Egyptian fraction algorithms are hard to analyze. -- David Eppstein Computer Science Dept., Univ. of California, Irvine http://www.ics.uci.edu/~eppstein/ === Subject: Re: integer sums of unit fractions > I'm interested in ways of partitioning an integer n>1 into a sum of a > finite sequence of unit fractions, in such a way that no nontrivial > subsequence has an integer sum. > > For example, 2 = 1/2 + 1/3 + 1/3 + 1/4 + 1/7 + 1/7 + 1/7 + 1/7 + 1/84 > but no subsequence of these fractions adds to one. > > Is it possible to find examples with larger values of n? > Or with no two fractions equal to each other? > > What happens when you try the greedy algorithm? e.g., > 3 = 1/2 + 1/3 + 1/3 + 1/4 + 1/5 + 1/5 + 1/5 + 1/5 + a few 1/7 > + whatever it takes to get to 3? > Greedy meaning that it takes the largest fraction for which the total is > at most n and that does not create a subsequence with integer sum? Yes. > Even much simpler greedy Egyptian fraction algorithms are hard to analyze. OK, but from your original question, you don't even know whether it can be done for n = 3; is it really that hard to analyze my suggestion in that case? I grant that my suggestion is unlikely to be of much use for large n. -- Gerry Myerson (gerry@maths.mq.edi.ai) (i -> u for email) === Subject: Re: integer sums of unit fractions 3QLpj-NoP*NzsIC,boYU]bQ]H'y<#4ga3$21: > OK, but from your original question, you don't even know whether > it can be done for n = 3; is it really that hard to analyze my > suggestion in that case? I found the n=2 example I posted by hand. I'd be tempted to implement a greedy algorithm to see how well it works for larger n but it seems Robert Israel and Randall have already done so. -- David Eppstein Computer Science Dept., Univ. of California, Irvine http://www.ics.uci.edu/~eppstein/ === Subject: random model Hallo, I have a bit of an awkward question for you. I'm toying around with a GA and I would like to test it by applying several models. Unfourtunately the search is rather fast and I have to enter each time a new model by hand. So I was thinking if there are algorithms present that could generate a continuous model automatically, so I can feed it to the GA? The model should incorporate all the standard operators and allow for an undefined amount of parameters. Can this be done? I would appreciate any links or pointers on how to procede from here. === Subject: Re: random model > Hallo, > I have a bit of an awkward question for you. I'm toying around with a GA > and > I would like to test it by applying several models. Unfourtunately the > search is rather fast and I have to enter each time a new model by hand. > So > I was thinking if there are algorithms present that could generate a > continuous model automatically, so I can feed it to the GA? > The model should incorporate all the standard operators and allow for an > undefined amount of parameters. Can this be done? > I would appreciate any links or pointers on how to procede from here. It's not clear, at least to me, what you are modeling. However, if I'm guessing correctly, you're asking about an encoding, a model, over which the genetic algorithm works. For instance, one model of human populations would include heights, weights, and skin color; you'd use the GA to come up with the best combination of those characteristics. Another model might include heights, weights, skin color, and waist measurement. Then again, I'm not sure how standard operators fit into this, because the operators I'm thinking of are inherent in the GA itself, whatever you're modeling; e.g. the mutation operator is often a part of the GA itself, not the thing you're modeling. Could you be more specific about your problem, perhaps giving an example of the models you're using? lppl