mm-274
===
Subject: Re: Gauss Method 2+4+6+8+...512> My professor
wants me to learn how to do the Gauss problems>
IE:2+4+6+8+...+512 and 1+2+3+4+5+...+1000 using algebra not
write 1+2+3+...+1000 as> 1+ 2+ 3+ ... + 500 +> 1000+999+998+
... + 501> Now adding vertically first gives 500 copies of
1001 to be added.> this is, more or less, what Gauss did.See
my other post where I explain what Gauss did do.What with you
method do I do with 1+2+...+101 ?Here's a slower short
cut1+2+3+4+5 = 156+7+8+9+10 = 5*5 + 15 = 401+2+...+10 =
5511+12+...+20 = 10*10 + 55 = 15521+...+30 = 20*10 + 55 =
2551+2+...+100 = 10*(0+1+2+3...+9) +10*55 = 10*(55-10) +
550then make last steps for 1,000's.The orginal problem was
punishment for unrulely math classto add 1+2+...+100. Gauss
avoided his punishment and hadgood fortune to have teacher who
reconized his creative work.My longer short cut is for smart
students not as smart as Gaussor for those who wan to look
like that took long enuf for thepurpose of the
===
help if I explained some of the particulars offactorizations,
especially since most of you are probably used tooperating in
mathematical areas where numbers like 1/2 and 1/3 arealways
available.However, while in the complex plane you always have
fractionsavailable, there are other domains where you do
not.1. Factorizations are just ways of looking at factors of
someproduct.For instance, 2(3) is a factorization of 6, which
tells you that 6 isa product of 2 and 3.That factorization is
in an integer domain, which simply means thatyou have only
integeso a factorization like 5(6/5) = 6, is notvalid in
integethough it is valid in some other domain that has1/5 as a
member.2. Algebra allows a generalization of factorizations
beyond specificnumber examples, for instance(x+2)(x+3) = x^2 +
5x + 6which is true without regard to what domain x is in, so
you can let xbe an integer, or it could be a fraction.3. If x
is an integer, then you're guranteed to be in the
integerdomain, which logically follows from the fact that x is
added to andmultiplied times other integers.4. Algebraic
integers are roots of monic polynomials with
integercoefficients e.g. x^2 + 5x + 6, as monic just means
that leadingcoefficient is a factor of 1 in the integer
domain.Not surprisingly, if x is an algebraic integer, then
x^2 + 5x + 6 isan algebraic integer, and the
factorization(x+2)(x+3) = x^2 + 5x + 6 is in the algebraic
integer domain.What I've done is consider factorizations of
polynomials, where thefactors are not polynomials.5. In an
attempt at questioning an important conclusion a Rick
Deckermade a post with his own example of such a
factorization, and I'veused it partly because it's a quadratic
and easier to handle.That factorization is(5a_1(x) + 7)(5a_2(x)
+ 7) = 7(25x^2 + 30x + 2) where his a's are roots of a^2 - (x -
1)a + 7(x^2 + x).Notice that it is a factorization because you
have factors (5a_1(x) + 7) and (5a_2(x) + 7) which multiply to
give the product 7(25x^2 + 30x + 2).Algebra allows me to make
the substitution a_2(x) = b_2(x) - 1 to get(5a_1(x) +
7)(5b_2(x) + 2) = 7(25x^2 + 30x + 2) where the purpose is to
balance out constant factowhich here arenumbeon both sides of
the equation.Integers are rather easy to work with so now I
can use them todetermine what is forced upon the
variables.Notice that multiplying out gives25 a_1(x) b_2(x) +
10 a_1(x) + 35 b_2(x) + 14 = 175 x^2 + 210 x + 14.That's
important because I now attempt to eliminate the factor of
7from both sides, and to do so while remaining in the domain
ofalgebraic integers.6. The logical conclusion is that the
only way that might possiblyallow that is(5a_1(x)/7 +
1)(5b_2(x) + 2) = 25x^2 + 30x + 2as consider another
possibility, like (5a_1(x)/sqrt(7) + sqrt(7))(5b_2(x)/sqrt(7)
+ 2/sqrt(7)) = 25x^2 + 30x + 2which gives the
factorizationsqrt(7)(2/sqrt(7)) = 2as multiplying out gives25
a_1(x) b_2(x)/7 + 10 a_1(x)/7 + 5b_2(x) + 2 = 25 x^2 + 30 x +
2and the two factors are(5a_1(x)/sqrt(7) +
sqrt(7))and(5b_2(x)/sqrt(7) + 2/sqrt(7))which internally have
sqrt(7) and 2/sqrt(7) as the factors of 2.But that second
factor cannot be in the domain of algebraic integersas
2/sqrt(7) is not an algebraic integer.Generalizing, for any
factorization of 7, with algebraic integers f_1and f_2, where
f_1 f_2 = 7, and f_1 is assumed to be a factor of(5a_1(x) + 7)
you will have(5b_2(x)/f_2 + 2/f_2)as a factor, and if 2/f_2 is
not an algebraic integer, then thatfactor is not in algebraic
integers.7. Logically that follows from the requirement that
for afactorization to be in a particular domain, its factors
must be inthat domain as well.Like before, with 2(3) = 6, in
the domain of integers that is valid,while 5(6/5) = 6 is not
valid in the domain of integers.So if you're trying to remain
in the domain of algebraic integers then(5a_1(x)/7 +
1)(5b_2(x) + 2) = 25x^2 + 30x + 2is the only
possibility.Mathematicians, however, for many years believed
that if the roots ofa quadratic likea^2 - (x - 1)a + 7(x^2 +
x)are not integethen there's no way to figure out where
factors of 7might go between those roots, but they believed
that they did split upin some way such that each root would
have some factor of 7 in thering of algebraic integers.My work
proves that wrong with simple algebraic principles by
usingnon-polynomial factowhich is the step mathematicians did
not take.Unfortunately, rather than accept these results, most
mathematiciansare ignoring my work, while you can see on Usenet
===
Re: Factorizations, underlying theory> It might help if I
explained some of the particulars of> factorizations,
especially since most of you are probably used to> operating
in mathematical areas where numbers like 1/2 and 1/3 are>
always available.> I don't know if you intend it this way, but
sometimes you are a very funny guy.Now where the hell did I put
===
might help if I explained some of the particulars of>
factorizations, especially since most of you are probably used
to> operating in mathematical areas where numbers like 1/2 and
1/3 are> always available.> However, while in the complex
plane you always have fractions> available, there are other
domains where you do not.> 1. Factorizations are just ways of
looking at factors of some> product.> For instance, 2(3) is a
factorization of 6, which tells you that 6 is> a product of 2
and 3.> That factorization is in an integer domain, which
simply means that> you have only integeso a factorization like
5(6/5) = 6, is not> valid in integethough it is valid in some
other domain that has> 1/5 as a member.> 2. Algebra allows a
generalization of factorizations beyond specific> number
examples, for instance> (x+2)(x+3) = x^2 + 5x + 6> which is
true without regard to what domain x is in, so you can let x>
be an integer, or it could be a fraction.> 3. If x is an
integer, then you're guranteed to be in the integer> domain,
which logically follows from the fact that x is added to and>
multiplied times other integers.> 4. Algebraic integers are
roots of monic polynomials with integer> coefficients e.g. x^2
+ 5x + 6, as monic just means that leading> coefficient is a
factor of 1 in the integer domain.> Not surprisingly, if x is
an algebraic integer, then x^2 + 5x + 6 is> an algebraic
integer, and the factorization> (x+2)(x+3) = x^2 + 5x + 6 is
in the algebraic integer domain.> What I've done is consider
factorizations of polynomials, where the> factors are not
polynomials.> 5. In an attempt at questioning an important
conclusion a Rick Decker> made a post with his own example of
such a factorization, and I've> used it partly because it's a
quadratic and easier to handle.> That factorization is>
(5a_1(x) + 7)(5a_2(x) + 7) = 7(25x^2 + 30x + 2)> where his a's
are roots of> a^2 - (x - 1)a + 7(x^2 + x).> Notice that it is a
factorization because you have factors> (5a_1(x) + 7) and
(5a_2(x) + 7)> which multiply to give the product 7(25x^2 +
30x + 2).> Algebra allows me to make the substitution a_2(x) =
b_2(x) - 1 to get> (5a_1(x) + 7)(5b_2(x) + 2) = 7(25x^2 + 30x +
2)> where the purpose is to balance out constant factowhich
here are> numbeon both sides of the equation.> Integers are
rather easy to work with so now I can use them to> determine
what is forced upon the variables.> Notice that multiplying
out gives> 25 a_1(x) b_2(x) + 10 a_1(x) + 35 b_2(x) + 14 =>
175 x^2 + 210 x + 14.> That's important because I now attempt
to eliminate the factor of 7> from both sides, and to do so
while remaining in the domain of> algebraic integers.> 6. The
logical conclusion is that the only way that might possibly>
allow that is> (5a_1(x)/7 + 1)(5b_2(x) + 2) = 25x^2 + 30x + 2>
as consider another possibility, like> (5a_1(x)/sqrt(7) +
sqrt(7))(5b_2(x)/sqrt(7) + 2/sqrt(7)) => 25x^2 + 30x + 2>
which gives the factorization> sqrt(7)(2/sqrt(7)) = 2> as
multiplying out gives> 25 a_1(x) b_2(x)/7 + 10 a_1(x)/7 +
5b_2(x) + 2 => 25 x^2 + 30 x + 2> and the two factors are>
(5a_1(x)/sqrt(7) + sqrt(7))> and> (5b_2(x)/sqrt(7) +
2/sqrt(7))> which internally have sqrt(7) and 2/sqrt(7) as the
factors of 2.> But that second factor cannot be in the domain
of algebraic integers> as 2/sqrt(7) is not an algebraic
integer.> Generalizing, for any factorization of 7, with
algebraic integers f_1> and f_2, where f_1 f_2 = 7, and f_1 is
assumed to be a factor of> (5a_1(x) + 7) you will have>
(5b_2(x)/f_2 + 2/f_2)> as a factor, and if 2/f_2 is not an
algebraic integer, then that> factor is not in algebraic
integers.> 7. Logically that follows from the requirement that
for a> factorization to be in a particular domain, its factors
must be in> that domain as well.> Like before, with 2(3) = 6,
in the domain of integers that is valid,> while 5(6/5) = 6 is
not valid in the domain of integers.> So if you're trying to
remain in the domain of algebraic integers then> (5a_1(x)/7 +
1)(5b_2(x) + 2) = 25x^2 + 30x + 2> is the only possibility.>
Mathematicians, however, for many years believed that if the
roots of> a quadratic like> a^2 - (x - 1)a + 7(x^2 + x)> are
not integethen there's no way to figure out where factors of
7> might go between those roots, but they believed that they
did split up> in some way such that each root would have some
factor of 7 in the> ring of algebraic integers.> My work
proves that wrong with simple algebraic principles by using>
non-polynomial factowhich is the step mathematicians did not
take.> Unfortunately, rather than accept these results, most
mathematicians> are ignoring my work, while you can see on
Usenet a few who attempt to> convince others that I'm wrong.>
James, You are ignorant and inept. You act like we owe you
something for somereason, which we don't. You are a crank; you
needlessly contact people'semployers. When are you going to
grow up and act like a man, instead of animmature kid. Grow up
===
might help if I explained some of the particulars of>
factorizations, Hey stooopid loud troll , put up or shut
a $10,000 prizeno questions asked too small to justify your
submission of two littleprime numbers? Put up or shut
up,http://www.rsasecurity.com/rsalabs/challenges/factoring/
faq.htmlhttp://www.rsasecurity.com/rsalabs/challenges/
factoring/numbers.htmlhttp://www.crank.net/harris.html It's
not every braying jackass that gets a whole page at
in a henhouse, asteer amidst cows; a stot, a gelding, a gelt,
a havier, a gib, alapin, a seg, a hog, a wether... a boring
psychotic ignorant troll ina science newsgroup.--Uncle
Alhttp://www.mazepath.com/uncleal/qz.pdfhttp://
www.mazepath.com/uncleal/eotvos.htm (Do something naughty to
===
I S S E R23 9 19 19 5 18 = 93 Oh dear. Jordan is in today's
Saskatoon Star-Phoenix (Penis CitySun-Sunbird) obituaries, he
passed away accidentally on Saturday January170+ KerryKerry 77
Wisser 93162+ SallySally 69 Wisser 93135+ JoelJoel 42 Wisser
93146+ LauraLaura 53 Wisser 93239 Jordan 12 6 91 163/202
12533Jordan 62 Alexander 84 Wisser 93 Dad's first name adds to
77. The brothers have first names addingtogether for 104 (77th
non-prime).Non-Primes 1 27 50 72 93 4 28 51 74 94 6 30 52 75
95 8 32 54 76 96 9 33 55 77 9810 34 56 78 9912 35 57 80 10014
36 58 81 10215 38 60 82 104 <-77th16 39 62 84 10518 40 63 85
10620 42 64 86 10821 44 65 87 11022 45 66 88 11124 46 68 90
11225 48 69 91 11426 49 70 92 115 Jordan's common name adds to
the 155 verses of Bible Book 7x7. Hisconsonants exceed his
vowels by the 155 verses of Bible Book 7x7. He has anaverage
of 7 letters per name, he has 21 (7+7+7) lettethe number
ofchapters in Bible Book 7. The vowels in his given names add
to 28 (1 through7) while the consonants in his given names add
to 118 (twice the 17thprime). His consonants add with their
positions for 343 (7x7x7). His veryfirst and very last letters
add together for 28 (1 through 7). He was bornon the 12th (7th
non-prime), Bible Book 12 (7th non-prime) contains 719verses
(the 128th or the 2 to the 7th prime). Jordan died on the 17th
day ofthe month (the 7th prime while the primes up to 7 add to
17) and on the 7thday of the week. His dad is Kerry (77).243
<- 1 Samuel 7274 <- 2 Samuel 7---517298 <- 1 Kings 7320 <- 2
Kings 7---618345 <- 1 Chronicles 7374 <- 2 Chronicles 7---719
See above that First Kings 7 and Second Kings 7 are chapters
298 and 320,together for the 618 verses of Bible Book 7. And
First Samuel 7 and SecondSamuel 7 averages with First
Chronicles 7 and Second Chronicles 7 for the618 verses of
Bible Book 7 (243+274+345+374=618+618). And First Chronicles
7and Second Chronicles 7 are chapters 345 and 374, together
for the 719verses of Bible Book 12, pretty as 12 is the 7th
non-prime while 719 is the128th or the 2 to the 7th prime. See
Books by Bonnie Gaunt for a Gematricdiscussion of the number
618. Primes In Prime Primes Positions 1 2 2 3 <- 3 3 5 <- 5 4
7 5 11 <- 11 6 13 7 17 <- 17 8 19 9 2310 2911 31 <- 3112 3713
41 <- 4114 4315 4716 5317 59 <- 59 --- 167 Esther Book 17 17
is the 7th prime while the primes up to 7 add to 17. There are
7primes in prime positions up to the 17th prime (59) and they
add to the 167verses of Bible Book 17. Esther becomes Queen in
Book 17 and Q is the 17thletter of the alphabet. Psalm 59 (the
17th prime) not only contains 17verses, it is the 17th chapter
in the Bible to contain the length of 17verses. James is Book
59 (the 17th prime), it's 108 verses is the 17th primeshort of
the 167 verses of Book 17. The first 17's are at chapters 91
and93, together for 184, or the 167 verses of Book 17 plus 17
more. The first17's are at chapters 91 and 93, surrounding 92
(the 4x17th non-prime).Non-Primes 1 27 50 72 4 28 51 74 6 30
52 75 8 32 54 76 9 33 55 7710 34 56 7812 35 57 8014 36 58 8115
38 60 8216 39 62 8418 40 63 8520 42 64 8621 44 65 8722 45 66
8824 46 68 9025 48 69 9126 49 70 92 <-68th Leviticus begins
with 17 verses and terminates at chapter 117 with 17+17verses.
There are 17 verses at chapters 1 and 3, and 59 (the 17
prime)verses at chapter 13, so the 17's and the 17th prime are
at chapter numbersadding to 17 (1+3+13=17). The first 17 versed
chapters in the Bible are atchapters 91 and 93, together for
184, or the 167 verses of Book 17 plus 17more. Leviticus
contains 859 verses, it ends in 59 (the 17th prime). Thefirst
17's in the Bible surround chapter 92 (the 4x17th
non-prime):Leviticus--------- 91 1 17 92 2 <-68th (4x17th)
non-prime 93 3 17 94 4 95 5 96 6 97 7 98 8 99 9100 10101 11102
12103 13 59 <-17th prime104 14105 15106 16107 17108 18109 19110
20111 21112 22113 23114 24115 25116 26117 27 34 <-17+17 Dad's
first name adds to 111.59% of mom's first name. The males
havefirst names adding together for 181, the females have
first names addingtogether for 122 (a difference of 59).
Jordan's last two names add togetherfor 177 (3x59). The even
valued letters in his given names add to 118(59+59). The
consonants in his given names add to 118 (59+59). His
primevalued letters add to 76 (17 plus the 17th prime),
corresponding to Exodus26 (17th non-prime). His square valued
letters add to 17. Jordan's 239valued name exceeds his 163rd
day of birth by 76 (17 plus the 17th prime),corresponding to
Exodus 26 (the 17th non-prime). Jordan lived for 12.59years.
Jordan lived for 4602 (26x(59+59+59)) days. Jordan was a grade
7student at James L. Alexander School, pretty as James is Bible
Book 59 (the17th prime). The primes in prime positions up to
the 17th prime (59) add tothe 167 verses of Bible Book 17
while the 108 verses of James (Book 59, the17th prime) is the
17th prime (59) short of the 167 verses of Book 17. Psalm59
(the 17th prime) not only contains 17 verses, it is the 17th
chapter inthe Bible to contain the length of 17 verses. Dad's
common name adds to 170(Deuteronomy 17). Dad and Jordan have
first names adding together for 139(the 17+17th prime). The
family name adds to 93 (Leviticus 3 with 17verses). Jordan was
born in 91 (Leviticus 1 with 17 verses). The first 17'sin the
Bible are at chapters 91 and 93, together for 184 (the 167
verses ofBible Book 17 plus 17 more). Jordan was born a
multiple of 167 days into theprime positions up to the 17th
prime add to the 167 verses of Bible Book 17.Jordan died
accidentally on January 17th.Primes Non-Primes 2 1 3 4 5 6 7 8
11 9 13 10 17 12 19 14 23 15 29 16 31 18 37 20 41 21 43 22 47
24 53 25 59 <-17th-> 26 --- --- 440 251 The parents have first
names adding together for the 146 verses of BibleBook 30.
Laura's common name adds to 146. Jordan's given names add to
146.Jordan's 239 valued name is 146.62% of his 163rd day of
birth. He lived for4602 days. Dad's first name adds to 77 (the
primes up to 19). Mom's first name addsto 69 (Exodus 19). All
first names add together for the 303 verses ofHebrews (the
19th Book of the New Testament). Jordan was born on day
163,it's the 38th (19+19th) prime. Old Testament Book 19 and
New Testament Book19 together contain 163 chapters (the
19+19th prime). His day, month andyear of birth adds to 109
(Leviticus 19). He was born on the 12th, BibleBook 12 contains
719 verses. Jordan died 219 days after his birthday.Primes 2 61
149 3 67 151 5 71 157 7 73 163 <-38th11 79 16713 83 17317 89
17919 97 18123 101 19129 103 19331 107 19737 109 19941 113
21143 127 22347 131 22753 137 22959 139 233 Sally adds to 69
and she married Wisser (93, the 69th non-prime). Wisseradds to
93 (Bible Book 3 chapter 3) and they have 3 kids. Bible Book
3contains 27 (3x3x3) chapteit's 859 verses is 3x3x3x3x3x3 plus
3x3x3 plus103 (the 3x3x3rd prime). The 3x3 different letters in
Jordan's given namesadd to 103 (the 3x3x3rd prime), he is the
3rd of 3 kids. His name adds to239 (Bible Book 3x3 chapter 3),
he was born on day 163.3x3x3x3x3x3 3x3x3 103 <- the 3x3x3rd
prime----------- 859 <- the number of verses in Bible Book 3
Jordan was born on the 6+6th day of the 6th month. He was born
in 91 (1through to 13, the 6th prime). His middle name adds to
84 (the first 13primes minus the first 13 non-primes).
66.666...% of his names are 6lettered, and his 6 lettered
first name adds to 66.666...% of his 6 letteredlast name. His
12 (6+6) different letters add to the 154 verses
ofLamentations (the first 13 non-primes). The kids have first
names adding to42, 53 and 62, together these Bible Books
contain 1303 verses, it's the213th prime. We first hear of
Jordan in Genesis 13.Primes Non-Primes Fibonacci Lucas 2 1 0 1
3 4 1 3 5 6 1 4 7 8 2 7 11 9 3 11 13 10 5 18 17 12 8 29 19 14
13 47 23 15 21 76 29 16 34 123 31 18 55 199 37 20 89 322 41
<-13th-> 21 <-13th-> 144 <-13th-> 521 --- --- 238 154
<-Lamentations1-50 - Genesis51-90 - Exodus91-117 -
Leviticus118-153 - Numbers154-187 - Deuteronomy188-211 -
Joshua930-957 - Matthew958-973 - Mark974-997 - Luke998-1018 -
John1019-1046 - Acts1047-1062 - Romans 188 <-the opening
chapter of Book 6 is 6x6x6 short of the 404 verses of Bible
Book 66, it is the 6th prime squared (13x13) short of the 357
verses of Daniel (also in part about 666) 193 <-Book 6 chapter
6 is the 44th prime, while 44 is in turn 66.666...% of 66 211
<-the terminating chapter of Book 6 is approximately 66.6% of
the 66th prime (317) 357 <-the opening chapter of Book 6 plus
the 6th prime squared is the 357 verses of Daniel (in part
about 666) 404 <-the 6th prime squared (13x13) plus the 6th
prime squared (13x13) plus 66 adds to the 404 verses of Bible
Book 661062 <-666 plus 6x66 is a combination of the 658 verses
of Bible Book 6 plus the 404 verses of Bible Book 66, and is
the terminating chapter of New Testament Book 61070 <-666 plus
the 404 verses of Book 66 is the 1070 verses of Job (Book
6+6+6)1213 <-Exodus terminates at chapter 90 (66th non- prime)
with 1213 verses (the 198th or the 66+66+66th prime)1292 <-the
658 verses of Book 6 plus twice the 66th prime (317) is the
1292 verses of Isaiah (the Book contains 66 chapters) Jordan's
parents have first names adding together for 146 (twice the
73verses of Bible Book 29 and is the Book of Numbers chapter
29). The first oftheir kids is Joel (Bible Book 29), the
letters in Joel add to 42 (the 29thnon-prime). Dad and Joel
have first names differing in value by 35 (Genesis29 contains
35 verses, Genesis 35 contains 29 verses, and there are
35chapters in the Bible that contain the length of 29 verses).
All first namesin the family add together for the 303 verses of
Hebrews, Bible Book 58(29+29), this 58 (29+29) is the 42nd
non-prime while 42 in turn is the 29thnon-prime. Jordan's
given names add to 146 (twice the 73 verses of BibleBook 29
and is the Book of Numbers chapter 29). In his given names,
hisunrepresen letters exceed his represen letters by 145
(5x29). Hisvowels add to 42 (29th non-prime). His Fibonacci
valued letters add withtheir positions for 203 (7x29). His
Lucas valued letters are exceeded by hisnon-Lucas valued
letters by 109 (29th prime). His day, month and year ofbirth
adds to 109 (29th prime). Jordan died 219 days after his
birthday (3times the 73 verses of Bible Book 29). Bible Book
13 (the 6th prime)contains 29 chapters and Bible chapter 666
contains 29 verses, pretty as 29is 6 plus the 6th prime (13)
plus the 6th non-prime (10). There were 29Lucas 1 3 4 7 11 18
29 -- 73 <-the Lucas numbers up to 29 add to the 73 verses of
Bible Book 29J O E L <-Bible Book 2910 15 5 12 = 42 <-29th
non-primeC O P P E R <-29th element3 15 16 16 5 18 = 73 <-Book
29 and is the Lucas numbers up to 29, there is a copper riding
a horse on the 1973 Canadian 25 cent pieceC E N T <-made out
of 29th element3 5 14 20 = 42 <-29th non-primeCopper and Zinc
are elements 29 and 30 (togetherfor 59), and together they
make Brass (59):B R A S S2 18 1 19 19 = 59 Jordan was born on
the 12th day of the month. His first name adds to 62(Exodus
12). His middle name adds to 84 (7x12). He has 12 letters in
hiscommon name. He has 12 different letters in his full name.
The 14 differentletters he is missing from his name add to 197
(the first 12 primes). Hisfirst 12 and last 12 letters average
139 (the Book of Numbers chapter 12, orsimply Numbers 12). Dad
and Jordan have first names adding together for 139found his
obituary in a newspaper published on the 20th (12th
non-prime).The kids have first names adding together for 157
(the 37th prime while 37in turn is the 12th prime), it is the
12th prime in prime position. Again,Bible Book 12 (7th
non-prime) contains 719 verses (the 2 to the 7th prime).Primes
Non-Primes Fibonacci Lucas 2 1 0 1 3 4 1 3 5 6 1 4 7 8 2 7 11 9
3 11 13 10 5 18 17 12 8 29 19 14 13 47 23 15 21 76 29 16 34 123
31 18 55 199 37 <-12th-> 20 <-12th-> 89 <-12th-> 322 --- ---
--- --- 197 133 232 840 The obituary states He will be missed
beyond words and we take somesolace in knowing Jordan is in
heaven taking care of us now. The funeralservice is to be
conduc by The Lakeview Methodist Church, likely theminister
will provide assurances to the family that Jordan is in
heaven, andlikely the family believes this load of crap
because it is the line that thefilthy churches (and media,
they are uni with the churches) have beenfeeding them for
years. The Bible is clear that the dead know nothing, thatthey
are in the ground waiting for the second coming of the Lord,
they willnot go to heaven until judged worthy of such. For the
parents or thechurches to claim that their son is in heaven
means that they are judgingthe son, and have judged him worthy
of the great honor. They taught the sonto turn trees into
decora idols, now they are having him crema like hewas a
God-damned Hindu, and then have the audacity to claim that
theirsmitten son is in heaven. The death was not an accident,
the kid wassmitten. The churches teach that the dead are in
heaven because they desireto make the family feel good about
supporting the church. And by teachingthat the dead are in
heaven, this opens the door to necromancy (talking tothe dead)
and other forms of spirituality where the dead individual
isprovided with god-like attributes, as in this case where it
is bluntlysta that Jordan is now taking care of the family.
Believing thatprotection comes from horsehoes, rabbit's feet,
planets, numbecolors,furniture placement, decora trees, Mary
or dead family members is idolatry, repent of the crap or be
prepared to lose another family member, Ipredict. Protestant
and Catholic church members were upset with my words
andlobbied my abusive parents to have me tortured, I begged in
vain forassistance to flee my persecutonow see where this gets
you?!!! It isquite likely the family still has their decora
tree up, I bet it's heightin inches and the number of
decorations strongly relates to Jordan's nameand age at death,
or maybe Jordan died when the God-damned tree fell on him.You
people only have compassion for your decora trees and
othertraditions, let your decora trees, traditions and Jordan
save you. Goappeal to Shaw Cable to terminate my internet
account, go appeal to thepolice to arrest me, go appeal to my
parents to have me arres, go appealto thugs to beat me or kill
me, and I will appeal to God to terminate thelives of your
other two children (Exodus 20:5 and Hosea 4:6).
Vengeancebelongs to The Lord, and I leave vengeance to The
Lord, feel free to have mearres and tortured and then quote
Scripture to me telling me to leavevengeance to the Lord, and
feel free to have me arres and tortured andthen quote
Scripture to me telling me that God is love and I so should
behappier.187 Dar 17 2 57 48/317 00Daryl 60 Shawn 65 Kabatoff
62240 Bethany 28 10 76 302/64 7193Bethany 75 Ruth 67 Guenther
98187 Marcia 6 8 80 219/147 8571Marcia 45 Veronica 87 Acevedo
55288 Melinda 23 3 83 82/283 9530Melinda 58 Janelle 59 Elaine
46 Joyce 58 Jarocki 67 Anyway, if you people think that you
have the right to use my abusiveparents as tools and arrest
and torture me, then I think that I should havethe right to
ask women to marry me, or to marry Marcia and me, our
lastnames add together for the 117 verses of Song of Solomon,
it's the Bible'sBook of Love. The nubile sweety was born on
the 6th and has a 6 letteredfirst name). Isaiah is the Book
with 66 chaptepretty as it is Book 23,or the 6th prime plus
the 6th non-prime (13+10=23). Isaiah 4, 12 and 20(adds to 6x6)
each contains 6 verses. Isaiah 4:1 is about Marcia (and me),and
6 other women who are capable of feeling shame rather than
pride, greedor lust, or who limit their love for traditions
and for people who abide bytheir traditions. Actually and
probababbly it's about Marcia and Bethany andme, and 5 other
women. Anyway, you people have Egyptian penises on the roofsof
your churches and lined city streets with representations of
penises, andhad me tortured for years for saying so, others
just sat back in silencewhile they were doink this to me, and
similarly you remain silent andcompassionless now that the
arrests and torture have ceased. You peoplespent millions of
dollars having me tortured, and then annually you
spendbillions on your decora trees, I begged and begged for
assistance to fleethe country (they tortured me for years at
the U of S) and you people are socheap that you can't even
offer to buy me a cookie when I bust my ass toshow you
evidence that your very name is a gift from God, you cheap,
filthy,compassionless won't even spend 48 cents on a stamp so
that youcould send me a letter in the mail thanking me for
taking the time out of mylife to show you evidence that your
very name is a gift from God!!! All youare really good for is
to have your stats pos on the usenet and be usedas an example
to otheand look, here you are!!! Should Jordan have acousin
that marries me, great, but if Marcia marries me and then
Jordan'scousin marries Marcia and me, then any and all of that
cousin's siblinks aregoink to win themselves a shiny new
Cadillac. Or if Bethany Guenther marriesme, same deal. Or if
Melinda Jarocki sleeps with me and Jordan's cousinmarries me,
then any and all of that cousin's siblinks are goink to
winthemselves used Pontiacs (it's all included in my suit
against youcompassionless God-damned turds).259 Bethany 28 10
76 302/64 7193Bethany 75 Ruth 67 Acevedo-Kabatoff 55-62249
Marcia 6 8 80 219/147 8571Marcia 45 Veronica 87
Acevedo-Kabatoff 55-62 Anyway, I have Scripture to support
taking seven brides (Isaiah 4:1) andI have Scripture to
support sleeping with Melinda Jarocki outside of wedlock(First
Kings 1:1-5), while you people have a vast multitude of
Scripturescondemning your decora trees, phallic-capped
churches and your violenceagainst me for daring to point out
your pagan traditions. Good luck and mayGod bless you!!!Daryl
Shawn KabatoffBox 7134Saskatoon SaskatchewanCanadaS7K
4J1Isaiah 45:4, Ephesians 3:15 - God gives you your
name!!!Deaths (01/20/04)WISSER _ Jordan Alexander, age 12,
passed away accidentally on Saturday,survived by his loving
parents, Kerry and Sally and by his big brother Joeland big
sister Laura. He is also dearly loved by his extended
families:Grandma Doreen Wisser; Kevin and Carol Wisser and
children Josh, Callie, andLannie; Karen and John Bosker and
children Brock and Brent; Kristine andTony Goulding and
children Adree and Farren. Grandma Katie Smith; John andCarol
Smith and children Candice (Gary) Augustyn and Ryan; Brian
Smith andMike, and by his Doucie-dog Kate. Jordan was
pre-deceased by his twoGrandpas, George Wisser and George
Smith. Jordan will be missed by his Grade7 class at James L.
Alexander School, his teachers and many friends. Jordanhad a
love for the outdooenjoying many family trips to our cottage
atWaden Bay. He loved to camp and looked so forward to his
Winter Camp nextweekend with the 69th Boy Scout Troop. He
loved Nintendo and playing boardgames, especially when we were
together as a family at the lake. Jordan alsoenjoyed going to
the rink with his buddies to play scrimmage. Jordan was
aunique individual and a generous, caring person, in a quiet,
considerateway. Whenever we were feeling down Jordan always
had a hug to make us feelbetter. He will be missed beyond
words and we take some solace in knowingJordan is in heaven
taking care of us now. The Funeral Service will be held(130
Kingsmere Place) with Pastor Dean Angell officiating.
Cremation tofollow. Donations in Jordan's memory can be made
to Scouts CanadaSaskatchewan Provincial Council (2811 Estey
Drive, Saskatoon, S7J 2V8) orthe Lung Association of
Saskatchewan (1231 8th Street East, Saskatoon, S7H0S5).
Arrangements have been entrus to Lynn Constantinoff of
===
posteconsider facts>> What if you were faced with arguments
over the existence of sqrt(2),> or sqrt(-1)?Imagine if as a
group mathematicians had risen to protect the status> quo, and
rejec sqrt(-1)?sqrt(-1), sqrt(2), and a host of other things we
now use today at one time> were not accep by the mathematicians
of the day. BUT, in math, the truth> always comes out
eventually, so you have nothing to worry about. YOU might> not
be able to convince anybody of anything (as indeed appears to
be the> case), BUT if you are right, eventually someoe else
will be able to. (oh> BTW, history shows that railing against
the establishment is not a very> effective method, so your
probably accomplishing even less with your rants> and
fits).Comforting thought, eh?I'm expressing my frustration
with liars and cheats.It seems to me that it'd be worse to
just shut-up and hope, when I canexpress my opinions about
these contemptible people.Besides, it's a way to blow off
steam.After all, eventually, my work will *be* the
===
all, eventually, my work will *be* the establishment.Then why
do you care what we think? Start the new
===
facts> I'm expressing my frustration with liars and
cheats.Then, for your own sake, stay away from
===
....> Integrate f(x,y) =
(x^2+y^2+2)/(sqrt((x^2+y^2)(x^2+y^2+4))) dx dy> between x=-1
and 1, y=-1 and 1> ....> I know you want the answer
numerically rather than analytically,> but FWIW it seems to be
an elliptic integral. Changing to polar> coordinates and
chopping your square into eight triangles gives> 8*((integral
from 0 to pi/4)d(theta))(integral from 0 to sec(theta))dr> of
the integrand> (r^2 + 2)/sqrt(r^2 + 4).> The integral with
respect to r needs only elementary functions, so the> whole
thing is> 4*(integral from 0 to pi/4)d(theta)> of the
integrand> (sqrt(1 + 4(cos(theta))^2))/((cos(theta))^2).> The
substitution t = tan(theta) then gives> 4*(integral from 0 to
1)dt> of the integrand> sqrt((5 + t^2)/(1 + t^2))> which is
close to one of the standard forms of (complete?) elliptic>
integral. Perhaps someome more familiar with those can take it
from> there.A concise closed form for the answer is -4 i
Sqrt(5) E(i Arcsinh(1), 1/5)where E denotes the incomplete
elliptic integral of the second kind.[Lest there be any
notational confusion, I'm using essentially the
sameconventions used
in<http://functions.wolfram.com/EllipticIntegrals/EllipticE2/>
.]The expression above is purely real, approximately 8.115, as
===
Elliptical coordinate tranformation questionI am reading
Classical Mechanics by Corben & Stehle, and I am stuck on
aquestion:Ch1 Q4: A possible pair of coordinates of a point
with cartesiancoordinates (x,y) is furnished by the roots of
the equation:x^2/(q - e1) + y^2/(q-bar - e2) = 1 (e1>e2)Show
that these roots q1, q2 satisfy the inequalitiesq1 >= e1 >= q2
>= e2.Also show that the curves q1 = const form a family of
confocal ellipses,that the curves q2 = const form a family of
hyperbolas confocal with theellipses, and that curves of these
two families form an orthogonal net.My thoughts:Now presumably,
e1 and e2 are constants (doesn't say whether they arepositive
constants)?Not sure how q1 and q2 relate to q and q-bar.If q1
and q2 are roots, then does this mean that setting q=q1 and
q-bar=q2solves the equation? If so, and if its true that
q1>=e1 and q2>=e2, then itseems to me that the equation will
always furnish an ellipse?If q and q-bar are two separate
coordinates, then they are not uniquelydefined by the
equation? Is the equation meant to furnish a mapping of
somesort?I get the feeling that there is either a typo, or I
am missing what thequestion is asking....Any help
===
The last such collapse was May 4, when a seven-storyapartment
block in Cairo collapsed, killing at least seven people.May
4th was the 124th day of the year, Bible chapter 124 is
Numbers 7. Thenumber 7 is the 4th prime, we read in the 4th
Commandment and in Hebrews 4that God desires that we keep the
7th day of the week (now called Saturday)as a day of rest in
His honor.The first 4 primes plus the first4 non-primes add
together for the36 chapters of Bible Book 4 Numbers:Primes
Non-Primes 2 1 3 4 5 6 7 <-4th-> 8 -- -- 17 19The first 4
primes in primepositions add together for the36 chapters of
Bible Book 4: Primes In Prime Primes Positions 1 2 2 3 <- 3 3
5 <- 5 4 7 5 11 <- 11 6 13 7 17 <- 17 -- 36Seven plus the 7th
prime plus the7th non-prime adds together forthe 36 chapters
of Bible Book 4,pretty as 7 is the 4th prime:Primes Non-Primes
2 1 3 4 5 6 7 8 11 9 13 10 17 <-7th-> 12 -- -- 58 50Daryl Shawn
===
The last such collapse was May 4, when a seven-story>apartment
block in Cairo collapsed, killing at least seven people.>May
4th was the 124th day of the year, Bible chapter 124 is
Numbers 7. The>number 7 is the 4th prime, we read in the 4th
Commandment and in Hebrews 4>that God desires that we keep the
7th day of the week (now called Saturday)<<<snipped a lot of
psycho crap from Shawn pedoe-boy Kabatoff>The following
(courtesy of Waxy.org) is sort of an unofficial FAQexplaining
the psychotic nonsense pos to Usenet by Shawn DarylKabatoff
AKA Dar, AKA Probababbilities. And now AKA marcia
andme.WARNING: Read below before even thinking about
responding to
thistwit.http://www.waxy.org/archive/2002/05/21/dar_kaba.shtml
#000643Usenet has the tendency to provide a public forum for
those who wouldnormally be scribbling in a closet. For
example, take Daryl ShawnKabatoff. For the last few yeahe's
methodically gatheredstatistics from various sources, ranging
from local newspaperobituary pages to the food court of the
Saskatoon Midtown Plaza mall.With all the raw data he's
collec, he's attempting to prove dailythat our full names are
in mathematical harmony with our birthdays.His rants normally
focus on a single individual he's met or readabout, starting
with calculations rela to their birthdate and fullnames,
blending in whatever other personal information about
theirfamily membespouses, birthplace, and career he's been
able tozealotry, and personal torment. I've never seen
anything like it.With all the prime numbeFibonacci sequences
and biblicalreferences, it's like reading the notebooks of
Maximillian Cohen andJohn Nash combined. Unsurprisingly,
several posts unfold to reveal ahistory of painful mental
illness. If you have some time, take a look.I've detailed his
posting history and a several sample posts below. Usenet
Posting History:January 27, 1999 to July 5, 2000 as
Catsco@home.comDecember 9, 2000 to May 4, 2001 as
s.kabatoff@sk.sympatico.caOct 30, 2001 to Oct 31, 2001 as
kabatoff@the.link.caJanuary 20, 2002 to April 17, 2002 as
s_kabatoff@hotmail.com (originalposts have been removed from
Google Groups archive)April 26, 2002 to Present as
dar_kabatoff@hotmail.comSelec Posts:Tessa Lynne SmithDastageer
Sakhizai and Helen SmithBrett David MakiAndrew Meredith
CottonKathryn Lee HippersonAmanda Dawn NewtonMona Marie
EtcheverryTony Peter NusplLisa Charlene McMillanGrant Allyn
Wood Comments scarier still is that saskatoon is my hometown,
though not my currentresidence. and every single place he's
mentioned in his posts (mostnotably nervous harold's and the
roastary) were either places i'vebeen (as it's a small city of
200K) or hangouts, ie. the two placesmentioned. chances are i
could email some friends back home and findout if they know of
him, they (my friends that is) being of thebroadway-centred
slacker ilk. myself, too, until i got out of there.eh,
anyways. thought it odd to see all this. midtown mall. i ate
mymeals there, whilst waiting several days in line for star
wars episodeone, at the theatre across the street.pos by andy
raad on May 22, 2002 06:20 PMFascinating. It's like he's
trying to take chaos and bind it intowhatever rules he can
find, religious, logical and otherwise. Numbersand math have a
reliable pattern, something that can always be provento true or
false. People and religion do not. It reminds me of
DarrenAronofsky's movie Pi. It's the story of an paraniod
genius who istrying to find a pattern in Pi. A group that
takes interest in hiswork is convinced that the existence of
Pi, a number whose existencecan be proven but no quantified,
is proof of the existence of God.Kabatoff's hunt for patterns
in something as random as name selectionis a way to reconcile
his deeply logical thought process with hisconflicting
religious views.Exactly. I probably shouldn't have, but I
e-mailed Daryl yesterday,asking him if he'd be willing to
create a numerological analysis forme. I also asked him if he
had seen either Pi or A Beautiful Mind, andwhat he thought of
them. If he replies, I'll be sure to post it.I baked many
pumpkin pies for Shawn (he likes pumpkin pies). I
rubbedpumpkin pie all over my breasts for him, and my breasts
turned orange.I am a pumpkin for Shawn.pos by Trisha Blondie
on July 24, 2002 10:41 PMUm, that's swell. So, you're in love
with him?Shawn once went to a funeral for a Jehovah Witness
that shot himselfand the lemon tarts were very bad, they were
not only sour but wererubbery as well. Shawn said that the guy
was some kind of JehovahWitness prophet, he saw in advance that
the lemon tarts at his funeralwere to be very very bad, and so
he shot himself. Shawn said that henever ate pumpkin pie at a
funeral but would like to some day. Shawnlikes pumpkin pie and
so I have been practicing to make very goodpumpkin pies.pos by
Trisha Blondie on July 25, 2002 02:49 PMShawn said that the
lemon tarts were sour, bitter and rubbery.I don't think this
guy takes notes. I think he has Total Recall, andit has driven
him insane...Oh... I almost forgot... I didnt spend thousands
of dollars a daytormenting Daryl... We got a deal on
tormenting that fiscal year, itonly came to about 37cents a
day....Mr. Kabatoff attempts to portray himself as a victim,
but in fact heis a violent predatory pedoe who is well known
to his local lawenforcement. In his post to multiple
newsgroups with the subjectCollecting Mail For The Coming
Anti-Christ, he encourages mothers tosend him photos of their
naked daughters. Mr Kabatoff explains, Ipersonally did not
want photographs being mailed to (the comingAnt-Christ) that
were of underage children unless the parent wassigning
consent. He is banned from virtually all the shopping mallsin
his community because he stalks young people and sexually
harassesthem. He has an extensive arrest record which includes
sexualmolestation charges. He's been hospitalized in mental
institutionsabout his contact with young girls in many posts.
Search newsgrouparchives for posts by him containing the word
nubile. As part of hisharrassment, he provides personal
details in a public forum, such asthe real names of real
children, in these and other posts. About onewan her and her
sister
dead+or+in+my+bed&hl=en&lr=&ie=UTF-8&selm=asqm35%24tjq5j%241%
40ID-136124.news.dfncis.de&rnuHe not only curses children and
prays for their death in his posts, healso enjoys attending
the funerals of young people: And so, sincenubile sweeties are
found in greatest abundance at the funerals ofhigh school
students, then it is the funerals of high school studentsthat
make the very very best funerals, especially if there is
food...I stuff my face (and my pockets) with all the good food
and look atall the pretty nubile sweeties and have the time of
my
nubile+sex&hl=en&lr=&ie=UTF-8&scoring=d&selm=LfXN8.63042%
24R53.25142039%40twister.socal.rr.com&rnum=1 Many of his posts
floods and crossposts his off-topic threatening and
offensivemissives to countless newsgroups. Some people HAVE
problems and somefolks ARE problems. Don't dismiss Mr.
Kabatoff as a harmless nut. Whenhe sends these posts to any
knew of him when I was attending the University of
Saskatchewan.He'd hang out in the Arts computer lab and all
you'd see is screens ofnumbers racing by on his laptop. I have
an original copy of hisCollecting Mail for the Coming
Anti-Christ pamphlet, and have seenhim be hauled away by
campus security on more than one occasion. Myfriends and I
refer to him as Crazy Number Man.I've been posting to (and
about) Shawn for over two years with biggaps in between. He
has seen Pi and didn't like it and didn't think itresembled
him at all. (Wrong, it fits him to a tee) He doesn't havetotal
recall and has sta that he travels with a lap top to
notateitems. Also, he uses cut n' paste a lot if you read all
the waythrough his ramblings. He is anti-social as shown by
his angrystatements towards those who, by his own admission,
have been kind(but not kind enough) to him. Still, he's
intelligent and seems to beable to take a joke on occassion.
That's where I came in. ALOHAReply to group(Unsolici e-mail is
dele from the server unread if it comes from anyone not already
===
Clifton McCamon - December 8th 1957M c C A M O N13 3 3 1 13 15
14 = 62 I went to Timothy's on 21st Street where Bethany
Guenther and MelindaJarocki work, sat at the counter with
Larry, and here he provided stats.62+ Dad 29 12 /262+ Mom 15
12 /1662+ Siblink62+ Siblink62+ Siblink215 Larry 8 12 57
342/23 294Larry 74 Clifton 79 McCamon 62Primes Non-Primes
Fibonacci Lucas 2 1 0 1 3 4 1 3 5 6 1 4 7 8 2 7 11 9 3 11 13
10 5 18 17 12 8 29 19 14 13 47 23 15 21 76 29 16 34 123 31 18
55 199 37 <-12th-> 20 <-12th-> 89 <-12th-> 322 --- --- --- ---
197 133 232 840 Both parents were born in the 12th month and
Larry too was born in the12th month. Dad and Larry were born
on days of the month adding to 37 (12thprime). Larry's name
begins with the 12th letter of the alphabet. His firstand last
names differ in value by 12. His last name adds to 62 (Exodus
12).His day and month of birth adds to 20 (12th non-prime).
Dad and Larry weretogether born with 25 days remaining in
their years (the number of chaptersin Bible Book 12). The
parents generally have their birthdays on days of theyear
adding to 712, it's a multiple of 89 (12th Fibonacci). Note
that BibleBook 12 (the 7th non-prime) contains 719 verses (the
128th or the 2 to the7th prime).Non-Primes 1 27 50 4 28 51 6 30
52 8 32 54 9 33 5510 34 5612 35 5714 36 5815 38 6016 39 62
<-44th18 40 6320 42 6421 44 6522 45 6624 46 6825 48 6926 49 70
McCamon adds to 62 (44th non-prime). The McCamon (44th
non-prime) parentswere born on days of the month adding to 44.
Larry McCamon (44th non-prime)was born 344 days after dad's
birthday. Larry is the 4th of 4 kids, he isthe 6th of 6 family
membeBible Book 6 chapter 6 is chapter 193 (44thprime).Primes 2
61 149 3 67 151 5 71 157 7 73 16311 79 16713 83 17317 89 17919
97 18123 101 19129 103 193 <-44th31 107 19737 109 19941 113
21143 127 22347 131 22753 137 22959 139 233 MacCamon adds to
62, Larry's 215 valued name is 62% of his 342nd day ofbirth.
The MacCamon (62) family is a family of 6, pretty as New
TestamentBook 6 terminates at chapter 1062, it is 666 plus
6x66 is a combination ofthe 658 verses of Bible Book 6 plus
the 404 verses of Bible Book 66.1-50 - Genesis51-90 -
Exodus91-117 - Leviticus118-153 - Numbers154-187 -
Deuteronomy188-211 - Joshua930-957 - Matthew958-973 -
Mark974-997 - Luke998-1018 - John1019-1046 - Acts1047-1062 -
Romans 188 <-the opening chapter of Book 6 is 6x6x6 short of
the 404 verses of Bible Book 66, it is the 6th prime squared
(13x13) short of the 357 verses of Daniel (also in part about
666) 193 <-Book 6 chapter 6 is the 44th prime, while 44 is in
turn 66.666...% of 66 211 <-the terminating chapter of Book 6
is approximately 66.6% of the 66th prime (317) 357 <-the
opening chapter of Book 6 plus the 6th prime squared is the
357 verses of Daniel (in part about 666) 404 <-the 6th prime
squared (13x13) plus the 6th prime squared (13x13) plus 66
adds to the 404 verses of Bible Book 661062 <-666 plus 6x66 is
a combination of the 658 verses of Bible Book 6 plus the 404
verses of Bible Book 66, and is the terminating chapter of New
Testament Book 61070 <-666 plus the 404 verses of Book 66 is
the 1070 verses of Job (Book 6+6+6)1213 <-Exodus terminates at
chapter 90 (66th non- prime) with 1213 verses (the 198th or the
66+66+66th prime)1292 <-the 658 verses of Book 6 plus twice the
66th prime (317) is the 1292 verses of Isaiah (the Book
contains 66 chapters)Daniel is the 6th in a sequential set of
Books that together contain 4973verses (the 666th prime),
pretty as Daniel is in part about 666:22 Song 11723 Isaiah
129224 Jeremiah 136425 Lamentations 15426 Ezekiel 127327
Daniel 357 <-the 6th in the set28 Hosea 19729 Joel 7330 Amos
146 ---- 4973 <- the 666th prime Larry is the 6th of 6 family
members. His 6 vowels add to 66. The 10 (6thnon-prime)
different letters in his given names add to 123 (Numbers 6).
Hehas an average of 6 letters in his given names. His birthday
was 360 (6x60)days ago (goink full circle). He was born in 57,
pretty as Daniel and Book66 Revelation are the major Books of
end-times prophecy, both are in partabout 666, Daniel contains
357 verses while Revelation contains 404 verses,or 57 plus the
57th prime (269) plus the 57th non-prime (78) verses, orsimply
57+57p+57np verses.389 <-77th prime104 <-77th non-prime 77
<-77---570 The Four 57'sGenesis 41 -> 41Leviticus 14 ->
104Judges 9 -> 220 <-I dreamt of 220 roofs blownJohn 11 ->
1008 off homes in the Dakotas ---- 1373 <-220th primeChapter
57 is Exodus 7 with 25 verses Book 57 is emon with 25 verses
-- -- 41st non-prime 16th non-prime <-together for 57->Major
Books of End-Times Prophecy (Daniel and Revelation are in part
about666 while Isaiah contains 66 chapters):Daniel - 357
versesRevelation - 404 verses <-57 plus the 57th prime plus
the 57th non-primeIsaiah - 1292 verses <-an average of
19.575757... verses per chapter In leap years (years
containing 366 days), the parents have theirbirthdays on days
of the year averaging the 357 verses of Daniel. Theparents
generally have their birthdays on days 363 and 349, together
theseBible chapters contain 78 verses (57th non-prime). Larry
was born a multipleof 57 days into 57. His 342 (6x57th) day of
birth adds with his 215 valuedname for 557. His even valued
letters add to 114 (57+57). See how pretty itis that Genesis
41 would contain 57 verses, for 57 is the 41st non-prime.Larry
and is parents were together born with 41 days remaining in
theiryears (57 is the 41st non-prime). In 1988 I tried telling
people that Godwas emphasizing Genesis 41 and said that He
desires us to build up foodsupplies in anticipation of a
period of adversity, but people used myinterest in mathematics
as one of the reasons to have me arres andtortured in
psychiatric facilities, the railways sold the tracks and
landand used the money to buy lucrative hotels, the government
fined farmers forfailure to deliver grain to port fast enough,
and then they erec a statueof Gandhi with his back turned to
the facilities where they had Hindustorture me, and now I pray
for massive crop failures... for the loss ofcrops, forests,
houses, children. And while I begged in vain for assistanceto
get away from my persecutothe only assistance I get is to be
brutallyassaul and frequently libeled and told by you pieces
of crap that Ishould rejoice in my sufferings while you reward
my work on your names byblowing smoke at me, and then you fly
off to some place warm and leave me inutter poverty (and in
shock). McCamon begins with the 13th letter of the alphabet
and adds to 62, it'sthe 13th prime (41) plus the 13th
non-prime (21). Bible Book 13 opens with54 verses, or 13 plus
the 13th prime (41), while Bible Book 54 contains 113verses.
Larry and his parents generally have their birthdays on days
of theyear adding to 1054, with 41 days remaining in their
years (13th prime),it's 1013 days closer to the the end of
their years than to the beginning oftheir years. Chapter 1013
is New Testament chapter 84 (the first 13 primesminus the
first 13 non-primes). Larry's middle name adds to 79 (Psalm 79
isthe 13th chapter to contain the length of 13 verses). The
consonants in hisgiven names add to 103 (Leviticus 13). All 13
of his consonants are inpositions adding to 130 (Numbers 13).
His 11 different letters add to 136and his common name adds to
136.Primes Non-Primes Fibonacci Lucas 2 1 0 1 3 4 1 3 5 6 1 4 7
8 2 7 11 9 3 11 13 10 5 18 17 12 8 29 19 14 13 47 23 15 21 76
29 16 34 123 31 18 55 199 37 20 89 322 41 <-13th-> 21 <-13th->
144 <-13th-> 521 --- --- 238 154 <-Lamentations Larry was born
93% into the year, his first name adds to 93% of hismiddle
name. The parents generally together have their birthdays 694
dayscloser to the end of their years than to the beginning of
their yeait'sthe number of verses in The Corinthians (Bible
Books 46 and 47, together for93).46 - First Corinthians - 437
verses47 - Second Corinthians - 257 verses-- ---93 694 17 is
the 7th prime while the primes up to 7 add to 17. There are
7primes in prime positions up to the 17th prime (59) and they
add to the 167verses of Bible Book 17. Esther becomes Queen in
Book 17 and Q is the 17thletter of the alphabet. Psalm 59 (the
17th prime) not only contains 17verses, it is the 17th chapter
in the Bible to contain the length of 17verses. James is Book
59 (the 17th prime), it's 108 verses is the 17th primeshort of
the 167 verses of Book 17. Primes In Prime Primes Positions 1 2
2 3 <- 3 3 5 <- 5 4 7 <-17 is the 7th prime 5 11 <- 11 while
the primes up 6 13 to 7 add to 17 7 17 <- 17 8 19 9 2310 2911
31 <- 3112 3713 41 <- 4114 4315 4716 5317 59 <- 59 <-the 7th
prime in --- prime position 167 Esther Book 17 <-the 7th prime
Larry's first two names add together for 153 (1 through 17 and
is the117th non-prime, it's the terminating chapter of Numbers
and is the numberof fish in the net in John 21). His last two
names differ in value by 17.The parents and Larry were born on
days 29, 15 and 8, together these BibleBooks contain 17
chapters.Primes Non-Primes 2 1 3 4 5 6 7 8 11 9 13 10 17 12 19
14 23 15 29 16 31 18 37 20 41 21 43 22 47 24 53 25 59 <-17th->
26 --- --- 440 251 Leviticus begins with 17 verses and
terminates at chapter 117 with 17+17verses. There are 17
verses at chapters 1 and 3, and 59 (the 17 prime)verses at
chapter 13, so the 17's and the 17th prime are at chapter
numbersadding to 17 (1+3+13=17). The first 17 versed chapters
in the Bible are atchapters 91 and 93, together for 184, or
the 167 verses of Book 17 plus 17more. Leviticus contains 859
verses, it ends in 59 (the 17th prime). Thefirst 17's in the
Bible surround chapter 92 (the 4x17th
non-prime):Leviticus--------- 91 1 17 92 2 <-68th (4x17th)
non-prime 93 3 17 94 4 95 5 96 6 97 7 98 8 99 9100 10101 11102
12103 13 59 <-17th prime104 14105 15106 16107 17108 18109 19110
20111 21112 22113 23114 24115 25116 26117 27 34 <-17+17 Larry
was born a multiple of 19 days into 57 (19+19+19). He was born
319days closer to the end of the year than to the beginning of
the year. He has19 letters. His day, month and year of birth
adds to 77 (the primes up to19). His first and last names add
together for 136 (Numbers 19). His 11different letters add to
136 (Numbers 19). His even valued letters add to114, it is
6x19 and is 19 plus the 19th prime (67) plus the 19th
non-prime(28), or simply 19+19p+19np. His names add to the
53rd non-prime, to the22nd prime and to the 44th non-prime,
together for 119. His first name addsto 119.35% of his last
name. His first 3 letters add to 19. Larry was born1.9 years
after his parent's birthdays. The parents were born on days 29
and15, these are the 10th prime and the 9th non-prime, together
for 19. Larry's 342 day of birth adds with his 215 valued name
for 557 (Psalm79). His middle name adds to 79. His unrepresen
letters exceed hisrepresen letters by 79. Dad and Larry were
born on days 29 and 8, theseBible Books contain an average of
79 verses. The parents were born on days 29 and 15, together
these Bible Bookscontain 353 verses. Larry's given names add
together for 153. In Larry'sgiven names, his consonants exceed
his vowels by 53. The last letters ofeach of his names add
together for 53. His initials and middle letters addtogether
for 53. His primes, squares and cubes together add with
theirpositions for 153. Mom and Larry were born on days 15 and
8, the latter is53.333...% of the former. There are 53 verses
in Bible Book 36 while Larryand his parents were born in
months adding to 36.The first 4 primes plus the first4
non-primes add together for the36 chapters of Bible Book 4
Numbers:Primes Non-Primes 2 1 3 4 5 6 7 <-4th-> 8 -- -- 17
19The first 4 primes in primepositions add together for the36
chapters of Bible Book 4: Primes In Prime Primes Positions 1 2
2 3 <- 3 3 5 <- 5 4 7 5 11 <- 11 6 13 7 17 <- 17 -- 36Seven
plus the 7th prime plus the7th non-prime adds together forthe
36 chapters of Bible Book 4,pretty as 7 is the 4th
prime:Primes Non-Primes 2 1 3 4 5 6 7 8 11 9 13 10 17 <-7th->
12 -- -- 58 50 Larry is the 4th of 4 kids, he was born on the
8th (4+4 and is the 4thnon-prime, Bible Book 8 contains 4
chapters) day of the 12th (4+4+4th)month. He was born on the
342nd day of the year (First Chronicles 4). Hisgiven names add
together for 153 (the terminating chapter of Bible Book 4).His
name begins with the 12th (4+4+4th) letter of the alphabet.
His initialsadd to 28 (4 times the 4th prime). His last name
adds to 62 (44thnon-prime). His full name adds to 215 (Judges
4). His first 4 letters add to49 (the 4th prime squared). The
parents were born on days of the monthadding to 44. Larry and
his parents were born in months adding to 36 (9x4),pretty as
there are 36 chapters in Bible Books 4 and 14.Primes
Non-Primes 2 1 3 4 5 6 7 <-4th-> 8 <-Bible Book 8 contains 11
4 chaptepretty as 13 8 is the 4th non-prime 17 19 -- 77 <-the
first 8 primes plus 8 more adds to the 85 verses of Bible Book
8 Larry was born 695 months and 8 days into the century, there
are 695verses in Second Samuel, Bible Book 10, pretty as the
first 10 non-primesadd to 95. The 10 different letters in his
given names add to 123 (10thLucas). Bible Book 10 brings The
Samuels up to 1505 verses and 55 chapters,pretty as 1 through
10 adds to 55. The Old Testament terminates at BibleBook 39
with 55 verses (39th non-prime).Primes Non-Primes Lucas
Numbers 2 1 1 1 3 4 3 2 5 6 4 3 7 8 7 4 11 9 11 5 13 10 18 6
17 12 29 7 19 14 47 8 23 15 76 9 29 <-10th-> 16 <-10th-> 123
<-10th-> 10 --- --- --- --- 129 95 319 55187 Dar 17 2 57
48/317 00Daryl 60 Shawn 65 Kabatoff 62240 Bethany 28 10 76
302/64 7193Bethany 75 Ruth 67 Guenther 98187 Marcia 6 8 80
219/147 8571Marcia 45 Veronica 87 Acevedo 55288 Melinda 23 3
83 82/283 9530Melinda 58 Janelle 59 Elaine 46 Joyce 58 Jarocki
67 Anyway, if you people think that you have the right to use
my abusiveparents as tools and arrest and torture me, then I
think that I should havethe right to ask women to marry me, or
to marry Marcia and me, our lastnames add together for the 117
verses of Song of Solomon, it's the Bible'sBook of Love. The
nubile sweety was born on the 6th and has a 6 letteredfirst
name). Isaiah is the Book with 66 chaptepretty as it is Book
23,or the 6th prime plus the 6th non-prime (13+10=23). Isaiah
4, 12 and 20(adds to 6x6) each contains 6 verses. Isaiah 4:1
is about Marcia (and me),and 6 other women who are capable of
feeling shame rather than pride, greedor lust, or who limit
their love for traditions and for people who abide bytheir
traditions. You people have Egyptian penises on the roofs of
yourchurches and lined city streets with representations of
penises, and had metortured for years for saying so, others
just sat back in silence while theywere doing this to me, and
similarly you remain silent and compassionlessnow that the
arrests and torture have ceased. You people spent millions
ofdollars having me tortured, and then annually you spend
billions on yourdecora trees, I begged and begged for
assistance to flee the country(they tortured me for years at
the U of S) and you people are so cheap thatyou can't even
offer to buy me a cookie when I bust my butt to show
youevidence that your very name is a gift from God!!! Should
Larry have acousin that marries me, great, but if Marcia
marries me and then Larry'scousin marries Marcia and me, then
Larry is goink to win himself a shiny newCadillac!!! Or if
Bethany Guenther marries me, or marries Marcia and me,then
Larry will similarly win himself a shiny new Cadillac!!! Or if
MelindaJarocki sleeps with me, then Larry will win himself a
used Pontiac!!!259 Bethany 28 10 76 302/64 7193Bethany 75 Ruth
67 Acevedo-Kabatoff 55-62249 Marcia 6 8 80 219/147 8571Marcia
45 Veronica 87 Acevedo-Kabatoff 55-62 Anyway, I have Scripture
to support taking seven brides (Isaiah 4:1) andI have Scripture
to support sleeping with Melinda Jarocki outside of
wedlock(First Kings 1:1-5), while you people have a vast
multitude of Scripturescondemning your decora trees,
phallic-capped churches and your violenceagainst me for daring
to point out your pagan traditions. Good luck and mayGod bless
you!!! , you trea me with such brutality and annuallyspend
billions of dollars on turning trees into decora idols, I
lostsummer after summer after summer to psychiatric torture
and there isn't asingle one of you that has enough compassion
for me to assist me to get awayfor one single winter, indeed,
you don't have enough compassion to offer tobuy me a measly
cookie (and that's after I show you gems, evidence that
yourvery name is a gift from God). .Daryl Shawn KabatoffBox
7134Saskatoon SaskatchewanCanadaS7K 4J1Isaiah 45:4, Ephesians
===
3 1 13 15 14 = 62> I went to Timothy's on 21st Street where
Bethany Guenther and Melinda<<<snipped a lot of psycho crap
from Shawn pedoe-boy Kabatoff>The following (courtesy of
Waxy.org) is sort of an unofficial FAQexplaining the psychotic
nonsense pos to Usenet by Shawn DarylKabatoff AKA Dar, AKA
Probababbilities. And now AKA marcia andme.WARNING: Read below
before even thinking about responding to
thistwit.http://www.waxy.org/archive/2002/05/21/dar_kaba.shtml
#000643Usenet has the tendency to provide a public forum for
those who wouldnormally be scribbling in a closet. For
example, take Daryl ShawnKabatoff. For the last few yeahe's
methodically gatheredstatistics from various sources, ranging
from local newspaperobituary pages to the food court of the
Saskatoon Midtown Plaza mall.With all the raw data he's
collec, he's attempting to prove dailythat our full names are
in mathematical harmony with our birthdays.His rants normally
focus on a single individual he's met or readabout, starting
with calculations rela to their birthdate and fullnames,
blending in whatever other personal information about
theirfamily membespouses, birthplace, and career he's been
able tozealotry, and personal torment. I've never seen
anything like it.With all the prime numbeFibonacci sequences
and biblicalreferences, it's like reading the notebooks of
Maximillian Cohen andJohn Nash combined. Unsurprisingly,
several posts unfold to reveal ahistory of painful mental
illness. If you have some time, take a look.I've detailed his
posting history and a several sample posts below. Usenet
Posting History:January 27, 1999 to July 5, 2000 as
Catsco@home.comDecember 9, 2000 to May 4, 2001 as
s.kabatoff@sk.sympatico.caOct 30, 2001 to Oct 31, 2001 as
kabatoff@the.link.caJanuary 20, 2002 to April 17, 2002 as
s_kabatoff@hotmail.com (originalposts have been removed from
Google Groups archive)April 26, 2002 to Present as
dar_kabatoff@hotmail.comSelec Posts:Tessa Lynne SmithDastageer
Sakhizai and Helen SmithBrett David MakiAndrew Meredith
CottonKathryn Lee HippersonAmanda Dawn NewtonMona Marie
EtcheverryTony Peter NusplLisa Charlene McMillanGrant Allyn
Wood Comments scarier still is that saskatoon is my hometown,
though not my currentresidence. and every single place he's
mentioned in his posts (mostnotably nervous harold's and the
roastary) were either places i'vebeen (as it's a small city of
200K) or hangouts, ie. the two placesmentioned. chances are i
could email some friends back home and findout if they know of
him, they (my friends that is) being of thebroadway-centred
slacker ilk. myself, too, until i got out of there.eh,
anyways. thought it odd to see all this. midtown mall. i ate
mymeals there, whilst waiting several days in line for star
wars episodeone, at the theatre across the street.pos by andy
raad on May 22, 2002 06:20 PMFascinating. It's like he's
trying to take chaos and bind it intowhatever rules he can
find, religious, logical and otherwise. Numbersand math have a
reliable pattern, something that can always be provento true or
false. People and religion do not. It reminds me of
DarrenAronofsky's movie Pi. It's the story of an paraniod
genius who istrying to find a pattern in Pi. A group that
takes interest in hiswork is convinced that the existence of
Pi, a number whose existencecan be proven but no quantified,
is proof of the existence of God.Kabatoff's hunt for patterns
in something as random as name selectionis a way to reconcile
his deeply logical thought process with hisconflicting
religious views.Exactly. I probably shouldn't have, but I
e-mailed Daryl yesterday,asking him if he'd be willing to
create a numerological analysis forme. I also asked him if he
had seen either Pi or A Beautiful Mind, andwhat he thought of
them. If he replies, I'll be sure to post it.I baked many
pumpkin pies for Shawn (he likes pumpkin pies). I
rubbedpumpkin pie all over my breasts for him, and my breasts
turned orange.I am a pumpkin for Shawn.pos by Trisha Blondie
on July 24, 2002 10:41 PMUm, that's swell. So, you're in love
with him?Shawn once went to a funeral for a Jehovah Witness
that shot himselfand the lemon tarts were very bad, they were
not only sour but wererubbery as well. Shawn said that the guy
was some kind of JehovahWitness prophet, he saw in advance that
the lemon tarts at his funeralwere to be very very bad, and so
he shot himself. Shawn said that henever ate pumpkin pie at a
funeral but would like to some day. Shawnlikes pumpkin pie and
so I have been practicing to make very goodpumpkin pies.pos by
Trisha Blondie on July 25, 2002 02:49 PMShawn said that the
lemon tarts were sour, bitter and rubbery.I don't think this
guy takes notes. I think he has Total Recall, andit has driven
him insane...Oh... I almost forgot... I didnt spend thousands
of dollars a daytormenting Daryl... We got a deal on
tormenting that fiscal year, itonly came to about 37cents a
day....Mr. Kabatoff attempts to portray himself as a victim,
but in fact heis a violent predatory pedoe who is well known
to his local lawenforcement. In his post to multiple
newsgroups with the subjectCollecting Mail For The Coming
Anti-Christ, he encourages mothers tosend him photos of their
naked daughters. Mr Kabatoff explains, Ipersonally did not
want photographs being mailed to (the comingAnt-Christ) that
were of underage children unless the parent wassigning
consent. He is banned from virtually all the shopping mallsin
his community because he stalks young people and sexually
harassesthem. He has an extensive arrest record which includes
sexualmolestation charges. He's been hospitalized in mental
institutionsabout his contact with young girls in many posts.
Search newsgrouparchives for posts by him containing the word
nubile. As part of hisharrassment, he provides personal
details in a public forum, such asthe real names of real
children, in these and other posts. About onewan her and her
sister
dead+or+in+my+bed&hl=en&lr=&ie=UTF-8&selm=asqm35%24tjq5j%241%
40ID-136124.news.dfncis.de&rnuHe not only curses children and
prays for their death in his posts, healso enjoys attending
the funerals of young people: And so, sincenubile sweeties are
found in greatest abundance at the funerals ofhigh school
students, then it is the funerals of high school studentsthat
make the very very best funerals, especially if there is
food...I stuff my face (and my pockets) with all the good food
and look atall the pretty nubile sweeties and have the time of
my
nubile+sex&hl=en&lr=&ie=UTF-8&scoring=d&selm=LfXN8.63042%
24R53.25142039%40twister.socal.rr.com&rnum=1 Many of his posts
floods and crossposts his off-topic threatening and
offensivemissives to countless newsgroups. Some people HAVE
problems and somefolks ARE problems. Don't dismiss Mr.
Kabatoff as a harmless nut. Whenhe sends these posts to any
knew of him when I was attending the University of
Saskatchewan.He'd hang out in the Arts computer lab and all
you'd see is screens ofnumbers racing by on his laptop. I have
an original copy of hisCollecting Mail for the Coming
Anti-Christ pamphlet, and have seenhim be hauled away by
campus security on more than one occasion. Myfriends and I
refer to him as Crazy Number Man.I've been posting to (and
about) Shawn for over two years with biggaps in between. He
has seen Pi and didn't like it and didn't think itresembled
him at all. (Wrong, it fits him to a tee) He doesn't havetotal
recall and has sta that he travels with a lap top to
notateitems. Also, he uses cut n' paste a lot if you read all
the waythrough his ramblings. He is anti-social as shown by
his angrystatements towards those who, by his own admission,
have been kind(but not kind enough) to him. Still, he's
intelligent and seems to beable to take a joke on occassion.
That's where I came in. ALOHAReply to group(Unsolici e-mail is
dele from the server unread if it comes from anyone not already
===
Clifton McCamon - December 8th 1957M c C A M O N13 3 3 1 13 15
14 = 62 I went to Timothy's on 21st Street where Bethany
Guenther and MelindaJarocki work, sat at the counter with
Larry, and here he provided stats.62+ Dad 29 12 /262+ Mom 15
12 /1662+ Siblink62+ Siblink62+ Siblink215 Larry 8 12 57
342/23 294Larry 74 Clifton 79 McCamon 62Primes Non-Primes
Fibonacci Lucas 2 1 0 1 3 4 1 3 5 6 1 4 7 8 2 7 11 9 3 11 13
10 5 18 17 12 8 29 19 14 13 47 23 15 21 76 29 16 34 123 31 18
55 199 37 <-12th-> 20 <-12th-> 89 <-12th-> 322 --- --- --- ---
197 133 232 840 Both parents were born in the 12th month and
Larry too was born in the12th month. Dad and Larry were born
on days of the month adding to 37 (12thprime). Larry's name
begins with the 12th letter of the alphabet. His firstand last
names differ in value by 12. His last name adds to 62 (Exodus
12).His day and month of birth adds to 20 (12th non-prime).
Dad and Larry weretogether born with 25 days remaining in
their years (the number of chaptersin Bible Book 12). The
parents generally have their birthdays on days of theyear
adding to 712, it's a multiple of 89 (12th Fibonacci). Note
that BibleBook 12 (the 7th non-prime) contains 719 verses (the
128th or the 2 to the7th prime).Non-Primes 1 27 50 4 28 51 6 30
52 8 32 54 9 33 5510 34 5612 35 5714 36 5815 38 6016 39 62
<-44th18 40 6320 42 6421 44 6522 45 6624 46 6825 48 6926 49 70
McCamon adds to 62 (44th non-prime). The McCamon (44th
non-prime) parentswere born on days of the month adding to 44.
Larry McCamon (44th non-prime)was born 344 days after dad's
birthday. Larry is the 4th of 4 kids, he isthe 6th of 6 family
membeBible Book 6 chapter 6 is chapter 193 (44thprime).Primes 2
61 149 3 67 151 5 71 157 7 73 16311 79 16713 83 17317 89 17919
97 18123 101 19129 103 193 <-44th31 107 19737 109 19941 113
21143 127 22347 131 22753 137 22959 139 233 MacCamon adds to
62, Larry's 215 valued name is 62% of his 342nd day ofbirth.
The MacCamon (62) family is a family of 6, pretty as New
TestamentBook 6 terminates at chapter 1062, it is 666 plus
6x66 is a combination ofthe 658 verses of Bible Book 6 plus
the 404 verses of Bible Book 66.1-50 - Genesis51-90 -
Exodus91-117 - Leviticus118-153 - Numbers154-187 -
Deuteronomy188-211 - Joshua930-957 - Matthew958-973 -
Mark974-997 - Luke998-1018 - John1019-1046 - Acts1047-1062 -
Romans 188 <-the opening chapter of Book 6 is 6x6x6 short of
the 404 verses of Bible Book 66, it is the 6th prime squared
(13x13) short of the 357 verses of Daniel (also in part about
666) 193 <-Book 6 chapter 6 is the 44th prime, while 44 is in
turn 66.666...% of 66 211 <-the terminating chapter of Book 6
is approximately 66.6% of the 66th prime (317) 357 <-the
opening chapter of Book 6 plus the 6th prime squared is the
357 verses of Daniel (in part about 666) 404 <-the 6th prime
squared (13x13) plus the 6th prime squared (13x13) plus 66
adds to the 404 verses of Bible Book 661062 <-666 plus 6x66 is
a combination of the 658 verses of Bible Book 6 plus the 404
verses of Bible Book 66, and is the terminating chapter of New
Testament Book 61070 <-666 plus the 404 verses of Book 66 is
the 1070 verses of Job (Book 6+6+6)1213 <-Exodus terminates at
chapter 90 (66th non- prime) with 1213 verses (the 198th or the
66+66+66th prime)1292 <-the 658 verses of Book 6 plus twice the
66th prime (317) is the 1292 verses of Isaiah (the Book
contains 66 chapters)Daniel is the 6th in a sequential set of
Books that together contain 4973verses (the 666th prime),
pretty as Daniel is in part about 666:22 Song 11723 Isaiah
129224 Jeremiah 136425 Lamentations 15426 Ezekiel 127327
Daniel 357 <-the 6th in the set28 Hosea 19729 Joel 7330 Amos
146 ---- 4973 <- the 666th prime Larry is the 6th of 6 family
members. His 6 vowels add to 66. The 10 (6thnon-prime)
different letters in his given names add to 123 (Numbers 6).
Hehas an average of 6 letters in his given names. His birthday
was 360 (6x60)days ago (goink full circle). His dad was born on
the 29th, there are 29chapters in Bible Book 13 (6th prime) and
29 verses in chapter 666, prettyas 29 is a combination of 6
plus the 6th prime (13) plus the 6th non-prime(10). He was
born in 57, pretty as Daniel and Book 66 Revelation are
themajor Books of end-times prophecy, both are in part about
666, Danielcontains 357 verses while Revelation contains 404
verses, or 57 plus the57th prime (269) plus the 57th non-prime
(78) verses, or simply 57+57p+57npverses.389 <-77th prime104
<-77th non-prime 77 <-77---570 The Four 57'sGenesis 41 ->
41Leviticus 14 -> 104Judges 9 -> 220 <-I dreamt of 220 roofs
blownJohn 11 -> 1008 off homes in the Dakotas ---- 1373
<-220th primeChapter 57 is Exodus 7 with 25 verses Book 57 is
emon with 25 verses -- -- 41st non-prime 16th non-prime
<-together for 57->Major Books of End-Times Prophecy (Daniel
and Revelation are in part about666 while Isaiah contains 66
chapters):Daniel - 357 versesRevelation - 404 verses <-57 plus
the 57th prime plus the 57th non-primeIsaiah - 1292 verses <-an
average of 19.575757... verses per chapter In leap years (years
containing 366 days), the parents have theirbirthdays on days
of the year averaging the 357 verses of Daniel. Theparents
generally have their birthdays on days 363 and 349, together
theseBible chapters contain 78 verses (57th non-prime). Larry
was born a multipleof 57 days into 57. His 342 (6x57th) day of
birth adds with his 215 valuedname for 557. His even valued
letters add to 114 (57+57). See how pretty itis that Genesis
41 would contain 57 verses, for 57 is the 41st non-prime.Larry
and is parents were together born with 41 days remaining in
theiryears (57 is the 41st non-prime). In 1988 I tried telling
people that Godwas emphasizing Genesis 41 and said that He
desires us to build up foodsupplies in anticipation of a
period of adversity, but people used myinterest in mathematics
as one of the reasons to have me arres andtortured in
psychiatric facilities, the railways sold the tracks and
landand used the money to buy lucrative hotels, the government
fined farmers forfailure to deliver grain to port fast enough,
and then they erec a statueof Gandhi with his back turned to
the facilities where they had Hindustorture me, and now I pray
for massive crop failures... for the loss ofcrops, forests,
houses, children. And while I begged in vain for assistanceto
get away from my persecutothe only assistance I get is to be
brutallyassaul and frequently libeled and told by you pieces
of crap that Ishould rejoice in my sufferings while you reward
my work on your names byblowing smoke at me, and then you fly
off to some place warm and leave me inutter poverty (and in
shock). McCamon begins with the 13th letter of the alphabet
and adds to 62, it'sthe 13th prime (41) plus the 13th
non-prime (21). Bible Book 13 opens with54 verses, or 13 plus
the 13th prime (41), while Bible Book 54 contains 113verses.
Larry and his parents generally have their birthdays on days
of theyear adding to 1054, with 41 days remaining in their
years (13th prime),it's 1013 days closer to the the end of
their years than to the beginning oftheir years. Chapter 1013
is New Testament chapter 84 (the first 13 primesminus the
first 13 non-primes). Larry's middle name adds to 79 (Psalm 79
isthe 13th chapter to contain the length of 13 verses). The
consonants in hisgiven names add to 103 (Leviticus 13). All 13
of his consonants are inpositions adding to 130 (Numbers 13).
His 11 different letters add to 136and his common name adds to
136. Dad was born on the 29th (the number ofchapters in Bible
Book 13).Primes Non-Primes Fibonacci Lucas 2 1 0 1 3 4 1 3 5 6
1 4 7 8 2 7 11 9 3 11 13 10 5 18 17 12 8 29 19 14 13 47 23 15
21 76 29 16 34 123 31 18 55 199 37 20 89 322 41 <-13th-> 21
<-13th-> 144 <-13th-> 521 --- --- 238 154 <-Lamentations Larry
was born 93% into the year, his first name adds to 93% of
hismiddle name. The unrepea letters in his given names add to
93. Theparents generally together have their birthdays 694
days closer to the endof their years than to the beginning of
their yeait's the number ofverses in The Corinthians (Bible
Books 46 and 47, together for 93).46 - First Corinthians - 437
verses47 - Second Corinthians - 257 verses-- ---93 694 17 is
the 7th prime while the primes up to 7 add to 17. There are
7primes in prime positions up to the 17th prime (59) and they
add to the 167verses of Bible Book 17. Esther becomes Queen in
Book 17 and Q is the 17thletter of the alphabet. Psalm 59 (the
17th prime) not only contains 17verses, it is the 17th chapter
in the Bible to contain the length of 17verses. James is Book
59 (the 17th prime), it's 108 verses is the 17th primeshort of
the 167 verses of Book 17. Primes In Prime Primes Positions 1 2
2 3 <- 3 3 5 <- 5 4 7 <-17 is the 7th prime 5 11 <- 11 while
the primes up 6 13 to 7 add to 17 7 17 <- 17 8 19 9 2310 2911
31 <- 3112 3713 41 <- 4114 4315 4716 5317 59 <- 59 <-the 7th
prime in --- prime position 167 Esther Book 17 <-the 7th prime
Larry's first two names add together for 153 (1 through 17 and
is the117th non-prime, it's the terminating chapter of Numbers
and is the numberof fish in the net in John 21). His last two
names differ in value by 17.The parents and Larry were born on
days 29, 15 and 8, together these BibleBooks contain 17
chapters.Primes Non-Primes 2 1 3 4 5 6 7 8 11 9 13 10 17 12 19
14 23 15 29 16 31 18 37 20 41 21 43 22 47 24 53 25 59 <-17th->
26 --- --- 440 251 Leviticus begins with 17 verses and
terminates at chapter 117 with 17+17verses. There are 17
verses at chapters 1 and 3, and 59 (the 17 prime)verses at
chapter 13, so the 17's and the 17th prime are at chapter
numbersadding to 17 (1+3+13=17). The first 17 versed chapters
in the Bible are atchapters 91 and 93, together for 184, or
the 167 verses of Book 17 plus 17more. Leviticus contains 859
verses, it ends in 59 (the 17th prime). Thefirst 17's in the
Bible surround chapter 92 (the 4x17th
non-prime):Leviticus--------- 91 1 17 92 2 <-68th (4x17th)
non-prime 93 3 17 94 4 95 5 96 6 97 7 98 8 99 9100 10101 11102
12103 13 59 <-17th prime104 14105 15106 16107 17108 18109 19110
20111 21112 22113 23114 24115 25116 26117 27 34 <-17+17 Larry
was born a multiple of 19 days into 57 (19+19+19). He was born
319days closer to the end of the year than to the beginning of
the year. He has19 letters. His day, month and year of birth
adds to 77 (the primes up to19). His first and last names add
together for 136 (Numbers 19). His 11different letters add to
136 (Numbers 19). His even valued letters add to114, it is
6x19 and is 19 plus the 19th prime (67) plus the 19th
non-prime(28), or simply 19+19p+19np. His names add to the
53rd non-prime, to the22nd prime and to the 44th non-prime,
together for 119. His first name addsto 119.35% of his last
name. His first 3 letters add to 19. Larry was born1.9 years
after his parent's birthdays. The parents were born on days 29
and15, these are the 10th prime and the 9th non-prime, together
for 19. Larry's 342 day of birth adds with his 215 valued name
for 557 (Psalm79). His middle name adds to 79. His unrepresen
letters exceed hisrepresen letters by 79. Dad and Larry were
born on days 29 and 8, theseBible Books contain an average of
79 verses. The parents were born on days 29 and 15, together
these Bible Bookscontain 353 verses. Larry's given names add
together for 153. In Larry'sgiven names, his consonants exceed
his vowels by 53. The last letters ofeach of his names add
together for 53. His initials and middle letters addtogether
for 53. His primes, squares and cubes together add with
theirpositions for 153. Mom and Larry were born on days 15 and
8, the latter is53.333...% of the former. There are 53 verses
in Bible Book 36 while Larryand his parents were born in
months adding to 36.The first 4 primes plus the first4
non-primes add together for the36 chapters of Bible Book 4
Numbers:Primes Non-Primes 2 1 3 4 5 6 7 <-4th-> 8 -- -- 17
19The first 4 primes in primepositions add together for the36
chapters of Bible Book 4: Primes In Prime Primes Positions 1 2
2 3 <- 3 3 5 <- 5 4 7 5 11 <- 11 6 13 7 17 <- 17 -- 36Seven
plus the 7th prime plus the7th non-prime adds together forthe
36 chapters of Bible Book 4,pretty as 7 is the 4th
prime:Primes Non-Primes 2 1 3 4 5 6 7 8 11 9 13 10 17 <-7th->
12 -- -- 58 50 Larry is the 4th of 4 kids, he was born on the
8th (4+4 and is the 4thnon-prime, Bible Book 8 contains 4
chapters) day of the 12th (4+4+4th)month. He was born on the
342nd day of the year (First Chronicles 4). Hisgiven names add
together for 153 (the terminating chapter of Bible Book 4).His
name begins with the 12th (4+4+4th) letter of the alphabet.
His initialsadd to 28 (4 times the 4th prime). His last name
adds to 62 (44thnon-prime). His full name adds to 215 (Judges
4). His first 4 letters add to49 (the 4th prime squared). The
parents were born on days of the monthadding to 44. Larry and
his parents were born in months adding to 36 (9x4),pretty as
there are 36 chapters in Bible Books 4 and 14.Primes
Non-Primes 2 1 3 4 5 6 7 <-4th-> 8 <-Bible Book 8 contains 11
4 chaptepretty as 13 8 is the 4th non-prime 17 19 -- 77 <-the
first 8 primes plus 8 more adds to the 85 verses of Bible Book
8 Larry was born 695 months and 8 days into the century, there
are 695verses in Second Samuel, Bible Book 10, pretty as the
first 10 non-primesadd to 95. The 10 different letters in his
given names add to 123 (10thLucas). Bible Book 10 brings The
Samuels up to 1505 verses and 55 chapters,pretty as 1 through
10 adds to 55. The Old Testament terminates at BibleBook 39
with 55 verses (39th non-prime).Primes Non-Primes Lucas
Numbers 2 1 1 1 3 4 3 2 5 6 4 3 7 8 7 4 11 9 11 5 13 10 18 6
17 12 29 7 19 14 47 8 23 15 76 9 29 <-10th-> 16 <-10th-> 123
<-10th-> 10 --- --- --- --- 129 95 319 55187 Dar 17 2 57
48/317 00Daryl 60 Shawn 65 Kabatoff 62240 Bethany 28 10 76
302/64 7193Bethany 75 Ruth 67 Guenther 98187 Marcia 6 8 80
219/147 8571Marcia 45 Veronica 87 Acevedo 55288 Melinda 23 3
83 82/283 9530Melinda 58 Janelle 59 Elaine 46 Joyce 58 Jarocki
67 Anyway, if you people think that you have the right to use
my abusiveparents as tools and arrest and torture me, then I
think that I should havethe right to ask women to marry me, or
to marry Marcia and me, our lastnames add together for the 117
verses of Song of Solomon, it's the Bible'sBook of Love. The
nubile sweety was born on the 6th and has a 6 letteredfirst
name). Isaiah is the Book with 66 chaptepretty as it is Book
23,or the 6th prime plus the 6th non-prime (13+10=23). Isaiah
4, 12 and 20(adds to 6x6) each contains 6 verses. Isaiah 4:1
is about Marcia (and me),and 6 other women who are capable of
feeling shame rather than pride, greedor lust, or who limit
their love for traditions and for people who abide bytheir
traditions. You people have Egyptian penises on the roofs of
yourchurches and lined city streets with representations of
penises, and had metortured for years for saying so, others
just sat back in silence while theywere doing this to me, and
similarly you remain silent and compassionlessnow that the
arrests and torture have ceased. You people spent millions
ofdollars having me tortured, and then annually you spend
billions on yourdecora trees, I begged and begged for
assistance to flee the country(they tortured me for years at
the U of S) and you people are so cheap thatyou can't even
offer to buy me a cookie when I bust my butt to show
youevidence that your very name is a gift from God!!! Should
Larry have acousin that marries me, great, but if Marcia
marries me and then Larry'scousin marries Marcia and me, then
Larry is goink to win himself a shiny newCadillac!!! Or if
Bethany Guenther marries me, or marries Marcia and me,then
Larry will similarly win himself a shiny new Cadillac!!! Or if
MelindaJarocki sleeps with me, then Larry will win himself a
used Pontiac!!!259 Bethany 28 10 76 302/64 7193Bethany 75 Ruth
67 Acevedo-Kabatoff 55-62249 Marcia 6 8 80 219/147 8571Marcia
45 Veronica 87 Acevedo-Kabatoff 55-62 Anyway, I have Scripture
to support taking seven brides (Isaiah 4:1) andI have Scripture
to support sleeping with Melinda Jarocki outside of
wedlock(First Kings 1:1-5), while you people have a vast
multitude of Scripturescondemning your decora trees,
phallic-capped churches and your violenceagainst me for daring
to point out your pagan traditions. Good luck and mayGod bless
you!!! , you trea me with such brutality and annuallyspend
billions of dollars on turning trees into decora idols, I
lostsummer after summer after summer to psychiatric torture
and there isn't asingle one of you that has enough compassion
for me to assist me to get awayfor one single winter, indeed,
you don't have enough compassion to offer tobuy me a measly
cookie (and that's after I show you gems, evidence that
yourvery name is a gift from God). .Daryl Shawn KabatoffBox
7134Saskatoon SaskatchewanCanadaS7K 4J1Isaiah 45:4, Ephesians
===
is supremeDedekind has shown that the algebraic integers form
a gcd domain (actually> a bit more: it is a Bezout domain), so
the gcd exists. It is quite> similar to the standard gcd in the
integeexcept that this definition> is not concerned with the
sign, so in the integethe gcd of 6 and 14> is +2 or -2.> Now a
little theorem:> gcd(a * b, c) | gcd(a, c) * gcd(b, c).> You
might try to prove it. The prove is easy in a unique
factorisation> domain, less easy in other domains.> This is
true in any gcd domain. Don't know if it is true in a>
pre-Schreier domain by itself, but here goes my proof for
gcd-domain.The proof is trivial using this basic
propertyClaim: (ab,c) = (a(b,c),c)Proof: = (ab,ac, c) =
(ab,c(a,1)) = (ab,c)So applying claim twice (ab,c) =
((a,c)(b,c),c) | (a,c)(b,c) QED-Bill Dubuque> (See>
40nestle.ai.mit.edu> for a table of implications; gcd implies
pre-Schreier).In a pre-Schreier ring, any two factorizations
of the same element> have common refinements; and both gcd and
pre-Schreier domain implyProp. If gcd(a,b)=1, then gcd(a,bc) =
gcd(a,c).Proof. Let x = gcd(a,c), y = gcd(a,bc). Clealry x|y.
Write a = yu, bc> = yv. Then the factorizations bc=yv have a
common refinement, so> bc = yv = p*q*r*s, where b = pq, c =
y=pr, v=qs. Thus> p|gcd(b,y). But if p|y then p|a, so
p|gcd(b,y) = 1. Therefore, p is a> unit. But that means that
y=pr divides c=so y|a, y|c, hence> y|gcd(a,c)=x. Thus, x|y and
y|x, giving that, up to units, they are> equal. QED.Now back to
the condition we have: we want to prove that gcd(ab,c)> divides
gcd(a,c)*gcd(b,c).Let r = gcd(a,c), s = gcd(b,c). We want to
show that gcd(ab,c) divides> rs.Write a = ru, c = rv with
gcd(u,v) = 1;> b = sw c = sy with gcd(w,y) = 1.Using the
pre-Schreier property, we can take the two factorizations of>
c, rv = sy and find a common refinement, that is, writec =
h*k*m*n, wherer = hk, v = mn> s = hm, y = kn.We haveab =
(ru)(sw) = (hku)(hmw) = h^2*k*m*u*w.> c = h*k*m*n.rs =
h^2*k*m; and we see that the gcd of ab and c is
h*k*m*gcd(huw,n).Since n|y and gcd(n,y) = 1, we have
gcd(huw,n) = gcd(hu,n). Since n|v> and gcd(u,v)=1, we have
gcd(n,u)=1, so gcd(huw,n) => gcd(hu,n)=gcd(h,n). So gcd(ab,c)
= h*k*m*gcd(h,n), which divides> h*k*m*h = h^2*k*m = rs =
===
gcd(a,c)*gcd(b,c).QEDSubject: Re: Do you or your children have
children, 10,13 and 15 years old.The oldest had problems with
her mathematics and, just looking I found> a marvellous site
explaining lots of things about maths, try it out :>
http://www.outwar.com/page.php?x=1920394 . It can seem
strange, but> dont miss a bit :D> When a link pops up an
executable download, I consider it a game site, not a math
site.-- Will Twentymanemail: wtwentyman at copper dot
===
[(R -> S) -> (R -> R)]> can I write:1 [(R -> S) -> (R -> R)]>
2 R -> S hyp1> 3 R -> R mp,2,1> 4 [(R -> S) -> (R -> R)]
discharge hyp1R -> R is always true, can i discharge hyp1 and
thats it?> or do i have to prove R -> S is true?You can't use
4 as 1, otherwise you're assuming what you wish to prove.The
key will be knowing that q->q = T, and p->T = T.-- Will
===
Simplicity versus dirty math tricksI've no recently that you
can't claim to be in a ring while usingelements outside of
that ring. The mathematics is rather basic butI'm seeing
disagreement as if there's something to debate.Here's an
example to help take away places to hide:1 + 2 = 3, so you can
say (1+2)/3 = 1, and some might try to claimthat my current
position is like trying to say that 1/2 + 2/3 = 1 isnot in the
ring of integeas you have to sum *first* and then byconvention,
since the division isn't a ring operation anyway, you cansay
3/3 = 1.Now though, consider4(1+2) = 4 + 8as here notice that
you have *two* sums on both sides wher 8 on theright side is a
factor of 4 and 2 on the left.I've poin out that you *have* to
use elements from within the ring,for such an operation, while
posters arguing with me, keep trying topush the argument as if
it's like the 1+2 = 3 example before.Here's how they do it.The
modified Decker example is(5a_1(x) + 7)(5b_2(x) + 2) = 7(25x^2
+ 30x + 2)where b_2(x) = a_2(x) + 1, and a^2 - (x - 1)a +
7(x^2 + x).So multiplying through by 7 on the right side you
have(5a_1(x) + 7)(5b_2(x) + 2) = 7(25)x^2 + 7(30)x + 7(2)and 7
and 2 on the left are factors of 7(2) on the right.Notice that
besides 7(2) on the right you also have 7(25)x^2 + 7(30)x,so
you have two sets of sums: the summation on the right, and
thesummations on the left.There's no simplifying possible,
like with 1+2=3 to be done.It's just a mathematical fact that
the factors of 7(2) on the rightare 7 and 2 on the left.Now
then, if you factor out 7, and try to do so with factors f_1
andf_2, such that(5a_1(x) + 7)/f_1 (5b_2(x) + 2)/f_2 = 25x^2 +
30x + 2then necessarily you *still* have the factors of 2 on
the right as7/f_1 and 2/f_2 on the left.So claiming that the
*sum* is all that matters is just a dirty trick,meant to fool
readers into thinking that it's something like 1+2 = 3,where
you have to add first before you can divide out the 3.The
simple mathematical fact is that the factors of 2 on the right
are7/f_1 and 2/f_2 on the left.However, 2/f_2 is not an
algebraic integer if f_2 is a non-unit factorof 7, so if f_2
is a non-unit factor of 7 then you're NOT in the ringof
algebraic integers.So then, if posters claim you add first, as
if that matteconsiderthat they're trying to fool you with a
rather basic trick thatrequires that you ignore basic
===
Here's an example to help take away places to hide:> 1 + 2 =
3, so you can say (1+2)/3 = 1, and some might try to claim>
that my current position is like trying to say that 1/2 + 2/3
= 1 is> not in the ring of integeas you have to sum *first*
and then by> convention, since the division isn't a ring
operation anyway, you can> say 3/3 = 1.Actually, your claim is
more like saying that 1/2 + 2/3 = 1.And as for taking away
===
places to hide, well-done!Subject: Re: JSH: Simplicity versus
be in a ring while using> elements outside of that ring. The
mathematics is rather basic but> I'm seeing disagreement as if
there's something to debate.Here's an example to help take away
places to hide:1 + 2 = 3, Correct.> so you can say (1+2)/3 = 1,
Also correct, and confined to the integers.> and some might try
to claim> that my current position is like trying to say that
1/2 + 2/3 = 1 is> not in the ring of integeNow you are clearly
working with rationals (I'll assume the 1/2 is a typo for 1/3).
The question is: WHAT do you claim must exist within the
integers? (1+2)/3 or 1/3 and 2/3? If you mean the first, then
you can't discuss the second at all. If you mean the second,
then you have to be far more careful than you have been. > as
you have to sum *first* and then by> convention, since the
division isn't a ring operation anyway, you can> say 3/3 =
1.Now though, consider4(1+2) = 4 + 8as here notice that you
have *two* sums on both sides wher 8 on the> right side is a
factor of 4 and 2 on the left.This has nothing to do with the
above.I've poin out that you *have* to use elements from
within the ring,> for such an operation, while posters arguing
with me, keep trying to> push the argument as if it's like the
1+2 = 3 example before.Here's how they do it.The modified
Decker example is(5a_1(x) + 7)(5b_2(x) + 2) = 7(25x^2 + 30x +
2)where b_2(x) = a_2(x) + 1, and a^2 - (x - 1)a + 7(x^2 +
x).So multiplying through by 7 on the right side you
have(5a_1(x) + 7)(5b_2(x) + 2) = 7(25)x^2 + 7(30)x + 7(2)and 7
and 2 on the left are factors of 7(2) on the right.Notice that
besides 7(2) on the right you also have 7(25)x^2 + 7(30)x,> so
you have two sets of sums: the summation on the right, and the>
summations on the left.There's no simplifying possible, like
with 1+2=3 to be done.It's just a mathematical fact that the
factors of 7(2) on the right> are 7 and 2 on the left.Now
then, if you factor out 7, and try to do so with factors f_1
and> f_2, such that> (5a_1(x) + 7)/f_1 (5b_2(x) + 2)/f_2 =
25x^2 + 30x + 2then necessarily you *still* have the factors
of 2 on the right as> 7/f_1 and 2/f_2 on the left.This is
where you make your leap. What is supposed to be divisible by
f_2: (5b_2(x) + 2) or 2? You haven't clearly sta it.What's
your goal?So claiming that the *sum* is all that matters is
just a dirty trick,> meant to fool readers into thinking that
it's something like 1+2 = 3,> where you have to add first
before you can divide out the 3.The simple mathematical fact
is that the factors of 2 on the right are> 7/f_1 and 2/f_2 on
the left.However, 2/f_2 is not an algebraic integer if f_2 is
a non-unit factor> of 7, so if f_2 is a non-unit factor of 7
then you're NOT in the ring> of algebraic integers.Can you
prove this? It is not immediately obvious to me.So then, if
posters claim you add first, as if that matteconsider> that
they're trying to fool you with a rather basic trick that>
requires that you ignore basic algebra.The issue comes down to
a simple question: WHAT is supposed to have f_1 as a factor and
WHAT is supposed to have f_2 as a factor? Using your
example:(1+2) has 3 as a factor.1 and 2 do not have 3 as a
factor.Therefore, we must know whether you wish to find a
factor of the sum or a factor of the summands.-- Will
===
JSH: Simplicity versus dirty math tricks> I've no recently
that you can't claim to be in a ring while using> elements
outside of that ring. The mathematics is rather basic but> I'm
seeing disagreement as if there's something to debate.Here's an
example to help take away places to hide:1 + 2 = 3, so you can
say (1+2)/3 = 1, and some might try to claim> that my current
position is like trying to say that 1/2 + 2/3 = 1 is> not in
the ring of integeas you have to sum *first* and then by>
convention, since the division isn't a ring operation anyway,
you can> say 3/3 = 1.I have no problem with 1/2 + 2/4 not
being in the ring of integebut I do have some problems with
1/2 + 2/3 = 1.Now though, consider4(1+2) = 4 + 8as here notice
that you have *two* sums on both sides wher 8 on the> right
side is a factor of 4 and 2 on the left.I've poin out that you
*have* to use elements from within the ring,> for such an
operation, while posters arguing with me, keep trying to> push
the argument as if it's like the 1+2 = 3 example before.Here's
how they do it.The modified Decker example is(5a_1(x) +
7)(5b_2(x) + 2) = 7(25x^2 + 30x + 2)where b_2(x) = a_2(x) + 1,
and a^2 - (x - 1)a + 7(x^2 + x).So multiplying through by 7 on
the right side you have(5a_1(x) + 7)(5b_2(x) + 2) = 7(25)x^2 +
7(30)x + 7(2)and 7 and 2 on the left are factors of 7(2) on the
right.Notice that besides 7(2) on the right you also have
7(25)x^2 + 7(30)x,> so you have two sets of sums: the
summation on the right, and the> summations on the
left.There's no simplifying possible, like with 1+2=3 to be
done.It's just a mathematical fact that the factors of 7(2) on
the right> are 7 and 2 on the left.But in the ring of algebraic
integethere are factorizations of 14 into p times q, both
algebraic integewhere neither p nor q is a factor of 7 in that
ring.What you are saying for algebric integers is equivalent to
saying for rational integers that 210 MUST factor into 12 times
10 and in no other way, so that anyone who suggests that 210
can also befactored into 14 time 15 must be wrong.Now then, if
you factor out 7, and try to do so with factors f_1 and> f_2,
such that> (5a_1(x) + 7)/f_1 (5b_2(x) + 2)/f_2 = 25x^2 + 30x +
2then necessarily you *still* have the factors of 2 on the
right as> 7/f_1 and 2/f_2 on the left.No you don't. The
factors on the left will be (5a_1(x) + 7)/f_1 and (5b_2(x) +
2)/f_2.There is no more reason to suppose that5*b_2(x)/f_2 or
2/f_2 need be algebraic integers than to suppose that because
(10 + 11)/7 is an integer then 10/7 or 11/7 need also to be
integers.So claiming that the *sum* is all that matters is
just a dirty trick,Since it is only the sum, and not the
summands seqparately, that is being divided, it is only the
divisibility of the sum one need worry about. Since every
positive integer is a sum of 1's, by your theory nothing is
divisible by anything but 1.> meant to fool readers into
thinking that it's something like 1+2 = 3,> where you have to
add first before you can divide out the 3.Well, lets see you
do it first, in the ring of integers of course so that no
fractions are allowed.The simple mathematical fact is that the
factors of 2 on the right are> 7/f_1 and 2/f_2 on the left.Only
if we are stuck in the ring of rational integeas you seem to
be.However, 2/f_2 is not an algebraic integer if f_2 is a
non-unit factor> of 7, so if f_2 is a non-unit factor of 7
then you're NOT in the ring> of algebraic integers.You may not
be, but you are the only one who finds it necessary to look at
2/f_2 at all.So then, if posters claim you add first, as if
that matteIn the ring of intege(10 + 11)/7 is a rational
integer while 10/7 11/7 are not. JSH would have you believe
that 10/7 and 11/7 not being rational integers is relevant in
determining whether 21/7 is a rational integer.consider> that
they're trying to fool you with a rather basic trick that>
requires that you ignore basic algebra.While JSH's basic trick
requires you to ignore both algebra and arithmetic, and to come
===
Simplicity versus dirty math tricks>I've no recently that you
can't claim to be in a ring while using>elements outside of
that ring. The mathematics is rather basic but>I'm seeing
disagreement as if there's something to debate.Part of the
problem with all of this is that you insist on usingstrange
language. No mathematician ever claims to be ina ring. When he
talks about an element of a ring he saysso - if he's talking
about something other than an elementof that ring he makes it
clear that he's not talking aboutan element of that
ring.>Here's an example to help take away places to hide:>1 +
2 = 3, so you can say (1+2)/3 = 1, and some might try to
claim>that my current position is like trying to say that 1/2
+ 2/3 = 1 is>not in the ring of integeas you have to sum
*first* and then by>convention, since the division isn't a
ring operation anyway, you can>say 3/3 = 1.>Now though,
consider>4(1+2) = 4 + 8>as here notice that you have *two*
sums on both sides wher 8 on the>right side is a factor of 4
and 2 on the left.>I've poin out that you *have* to use
elements from within the ring,>for such an operation, while
posters arguing with me, keep trying to>push the argument as
if it's like the 1+2 = 3 example before.>Here's how they do
it.>The modified Decker example is>(5a_1(x) + 7)(5b_2(x) + 2)
= 7(25x^2 + 30x + 2)>where b_2(x) = a_2(x) + 1, and >a^2 - (x
- 1)a + 7(x^2 + x).>So multiplying through by 7 on the right
side you have>(5a_1(x) + 7)(5b_2(x) + 2) = 7(25)x^2 + 7(30)x +
7(2)>and 7 and 2 on the left are factors of 7(2) on the
right.>Notice that besides 7(2) on the right you also have
7(25)x^2 + 7(30)x,>so you have two sets of sums: the summation
on the right, and the>summations on the left.>There's no
simplifying possible, like with 1+2=3 to be done.>It's just a
mathematical fact that the factors of 7(2) on the right>are 7
and 2 on the left.>Now then, if you factor out 7, and try to
do so with factors f_1 and>f_2, such that>(5a_1(x) + 7)/f_1
(5b_2(x) + 2)/f_2 = 25x^2 + 30x + 2>then necessarily you
*still* have the factors of 2 on the right as>7/f_1 and 2/f_2
on the left.>So claiming that the *sum* is all that matters is
just a dirty trick,>meant to fool readers into thinking that
it's something like 1+2 = 3,>where you have to add first
before you can divide out the 3.>The simple mathematical fact
is that the factors of 2 on the right are>7/f_1 and 2/f_2 on
the left.>However, 2/f_2 is not an algebraic integer if f_2 is
a non-unit factor>of 7, so if f_2 is a non-unit factor of 7
then you're NOT in the ring>of algebraic integers.>So then, if
posters claim you add first, as if that matteconsider>that
they're trying to fool you with a rather basic trick
that>requires that you ignore basic
===
factorizations, relevanceMathematicians today are inheritors
of a rather deserved glory fromthe exploits and important work
of *past* mathematicians who have donemuch to advance
knowledge. However, it is problematic ifmathematicians today
can rely on social support garnered from theefforts of their
predecessors to hide acts of wrongdoing today.Here I'll
outline the basic mathematics underlying a find of mine of
astrange error in an esoteric branch of mathematics called
algebraicnumber theory.To understand posts on this subject, it
will help if you understandthe basics of factorizations.1.
Factorizations are just ways of looking at factors of
someproduct.For instance, 2(3) is a factorization of 6, which
tells you that 6 isa product of 2 and 3.That factorization is
in an integer domain, which simply means thatyou have only
integeso a factorization like 5(6/5) = 6, is notvalid in
integethough it is valid in some other domain likerational
numbers that has 1/5 as a member.2. Algebra allows a
generalization of factorizations beyond specificnumber
examples, for instance(x+2)(x+3) = x^2 + 5x + 6which is true
without regard to what domain x is in, so you can let xbe an
integer, or it could be a fraction.3. If x is an integer, then
you're guaranteed to be in the integerdomain, which logically
follows from the fact that x is added to andmultiplied times
other integeas addition and multiplication arewhat are called
ring operations by mathematicians.4. Algebraic integers are
roots of monic polynomials with integercoefficients e.g. x^2 +
5x + 6, as monic just means that leadingcoefficient is a factor
of 1 in the integer domain.Not surprisingly, if x is an
algebraic integer, then x^2 + 5x + 6 isan algebraic integer,
and the factorization(x+2)(x+3) = x^2 + 5x + 6 is in the
algebraic integer domain.What I've done is consider
factorizations of polynomials, where thefactors are not
polynomials.5. In an attempt at questioning an important
conclusion a RickDecker, a professor at Hamilton College, made
a post with his ownexample of such a factorization, and I've
used it partly because it'sa quadratic and easier to
handle.That factorization is(5a_1(x) + 7)(5a_2(x) + 7) =
7(25x^2 + 30x + 2) where his a's are roots of a^2 - (x - 1)a +
7(x^2 + x).Notice that it is a factorization because you have
factors (5a_1(x) + 7) and (5a_2(x) + 7) which multiply to give
the product 7(25x^2 + 30x + 2).Algebra allows me to make the
substitution a_2(x) = b_2(x) - 1 to get(5a_1(x) + 7)(5b_2(x) +
2) = 7(25x^2 + 30x + 2) where the purpose is to balance out
constant factowhich here arenumbeon both sides of the
equation.Importantly, with that substitution, at x=0, a_1(0) =
b_2(0) = 0, as Iemphasize that the 7 and 2 visible on the left
multiply to give 7(2)on the right.That is, when you multiply
through by 7 on the right side you have7(25)x^2 + 7(30)x +
7(2) where the 7(2) is the product of the factors visible on
the left in(5a_1(x) + 7)(5b_2(x) + 2).I have to elaborate to
that level of detail because for mathematiciansto fool you
about my discovery, you have to be confused on that
simplepoint.Integers are rather easy to work with so now I can
use them todetermine what is forced upon the variables.Notice
that multiplying out gives25 a_1(x) b_2(x) + 10 a_1(x) + 35
b_2(x) + 14 = 175 x^2 + 210 x + 14.That's important because I
now attempt to eliminate the factor of 7from both sides, and
to do so while remaining in the domain ofalgebraic integers.6.
The logical conclusion is that the only way that might
possiblyallow that is(5a_1(x)/7 + 1)(5b_2(x) + 2) = 25x^2 +
30x + 2as consider another possibility, like (5a_1(x)/sqrt(7)
+ sqrt(7))(5b_2(x)/sqrt(7) + 2/sqrt(7)) = 25x^2 + 30x + 2which
gives the factorizationsqrt(7)(2/sqrt(7)) = 2as multiplying out
gives25 a_1(x) b_2(x)/7 + 10 a_1(x)/7 + 5b_2(x) + 2 = 25 x^2 +
30 x + 2and the two factors are(5a_1(x)/sqrt(7) +
sqrt(7))and(5b_2(x)/sqrt(7) + 2/sqrt(7))which internally have
sqrt(7) and 2/sqrt(7) as the factors of 2.But that second
factor cannot be in the domain of algebraic integersas
2/sqrt(7) is not an algebraic integer.Generalizing, for any
factorization of 7, with algebraic integers f_1and f_2, where
f_1 f_2 = 7, and f_1 is assumed to be a factor of(5a_1(x) + 7)
you will have(5b_2(x)/f_2 + 2/f_2)as a factor, and if 2/f_2 is
not an algebraic integer, then thatfactor is not in algebraic
integers.7. Logically that follows from the requirement that
for afactorization to be in a particular domain, its factors
must be inthat domain as well.Like before, with 2(3) = 6, in
the domain of integers that is valid,while 5(6/5) = 6 is not
valid in the domain of integers.So if you're trying to remain
in the domain of algebraic integers then(5a_1(x)/7 +
1)(5b_2(x) + 2) = 25x^2 + 30x + 2is the only
possibility.Mathematicians, however, for many years believed
that if the roots ofa quadratic likea^2 - (x - 1)a + 7(x^2 +
x)are not integethen there's no way to figure out where
factors of 7might go between those roots, but they believed
that they did split upin some way such that each root would
have some factor of 7 in thering of algebraic integers.My work
proves that wrong with simple algebraic principles by
usingnon-polynomial factowhich is the step mathematicians did
not take.Now algebraic integers have been defined to be the
roots of monicpolynomials with integer coefficients, which is
actually something ofan arbitrary definition.Mathematicians
found it useful for over a hundred years without
fullyunderstanding its limitations, like how you can be forced
out of thatdomain as I have shown.It could be a small mistake,
but by trying to deny and hide it,today's mathematicians are
making a HUGE deal out of it, and bringingtheir own
credibility into question.They are damaging their discipline,
by not telling the truth fully andhonestly.I've shown what is
mathematically correct. It's been that way fromthe beginning
as the correct mathematics does not change.Today's
mathematicians gain nothing by hiding from the truth.
Afterall, in mathematics, when you're wrong, you're just
===
underlying a find of mine of a> strange error in an esoteric
ing imbecile troll . Hey stooopid loud troll JamesHarris, put
up or shut up. Is a $10,000 prize no questions asked toosmall
to justify your submission of two little prime
numbers?http://www.rsasecurity.com/rsalabs/challenges/
factoring/faq.htmlhttp://www.rsasecurity.com/rsalabs/
challenges/factoring/numbers.htmlhttp://www.crank.net/
harris.html It's not every braying jackass that gets a whole
page at
in a brothel, a capon in ahenhouse, a steer amidst cows; a
stot, a gelding, a gelt, a havier, agib, a lapin, a seg, a
hog, a wether... a loud stupid psychotic boorin a science
newsgroup.--Uncle
Alhttp://www.mazepath.com/uncleal/qz.pdfhttp://
www.mazepath.com/uncleal/eotvos.htm (Do something naughty to
===
Mathematicians today are inheritors of a rather deserved glory
from> the exploits and important work of *past* mathematicians
who have> done much to advance knowledge. However, it is
problematic if... an idiot like you decides to try to
understand some of that work?Indeed, very true. No argument on
===
relevanceFactorization
http://mathworld.wolfram.com/Factorization.html
http://mathworld.wolfram.com/PrimeFactorization.html The
determination of factors (divisors) of a given integer (prime
factorization), polynomial (polynomial factorization), etc. In
many cases of interest (particularly prime factorization,
factorization is unique, and so gives the simplest
representation of a given quantity in terms of smaller parts.
The terms factorization and factoring are used
synonymouslyPrime Counting Function
http://mathworld.wolfram.com/PrimeCountingFunction.htmlPrime
Difference Function
http://mathworld.wolfram.com/PrimeDifferenceFunction.html
Crank Information http://www.crank.net/harris.html
http://www.crank.net/usenet.html
3Ausers.pandora.be